Chapter 28: Problem 10
A short current element \(d \vec{l}=(0.500 \mathrm{mm}) \hat{\jmath}\) carries a current of 8.20 \(\mathrm{A}\) in the same direction as \(d \vec{l} .\) Point \(P\) is located at \(\vec{r}=(-0.730 \mathrm{m}) \hat{\imath}+(0.390 \mathrm{m}) \hat{k} .\) Use unit vectors to express the magnetic field at \(P\) produced by this current element.
Short Answer
Step by step solution
Understand the Problem
Convert Units
Apply the Biot-Savart Law
Calculate the Cross Product
Find the Magnitude of r
Substitute into the Biot-Savart Law
Express the Result
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Magnetic Field Calculation
- \(d\vec{B}\) is the differential magnetic field at a point \(P\).
- \(\mu_0\) is the permeability of free space, which has a constant value.
- \(I\) is the current through the wire segment.
- \(d\vec{l}\) is the infinitesimal length of the current element.
- \(\vec{r}\) is the position vector from the current element to the point \(P\).
- \(r\) is the magnitude of the position vector \(\vec{r}\).
Current Element
Cross Product Calculation
- \(d\vec{l} = (0, 0.500 \times 10^{-3}, 0) \ \mathrm{m}\)
- \(\vec{r} = (-0.730, 0, 0.390) \ \mathrm{m}\)
- The cross product results in a vector that is orthogonal to both \(d\vec{l}\) and \(\vec{r}\).
- This orthogonal nature determines the direction of the magnetic field around the current element.
- A zero component in the cross product indicates that some vector directions do not contribute to the magnetic field at \(P\).