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BIO Compression of Human Bone. The bulk modulus for bone is 15 GPa. (a) If a diver-in-training is put into a pressurized suit, by how much would the pressure have to be raised ( in batmospheres) above atmospheric pressure to compress her bones by 0.10\(\%\) of their original volume? (b) Given that the pressure in the ocean increases by \(1.0 \times 10^{4}\) Par every meter of depth below the surface, how deep would this diver have to go for her bones to compress by 0.10\(\%\) ? Does it seem that bone compression is a problem she needs to be concerned with when diving?

Short Answer

Expert verified
(a) Pressure raised by approximately 148.1 atm is needed. (b) Diver would need to go 1500 m deep. Bone compression is not a concern at typical diving depths.

Step by step solution

01

Understand Bulk Modulus Definition

The bulk modulus (K) is defined as the ratio of the change in pressure (\(\Delta P\)) to the fractional change in volume (\(-\frac{\Delta V}{V_0}\)). Mathematically,\[\Delta P = -K \left(\frac{\Delta V}{V_0}\right)\].
02

Calculate Pressure Increase in Pascals (a)

Given that \(\frac{\Delta V}{V_0} = 0.1\% = 0.001\) and \(K = 15\) GPa = \(15 \times 10^9\) Pa, substitute these values into the formula to find \(\Delta P\):\[\Delta P = -(15 \times 10^9 ) \times (-0.001) = 15 \times 10^6 \text{ Pa}\]
03

Convert Pressure to Atmospheres

1 atmosphere is equivalent to \(1.013 \times 10^5\) Pa. Convert the pressure difference to atmospheres:\[\Delta P = \frac{15 \times 10^6 \text{ Pa}}{1.013 \times 10^5 \text{ Pa/atm}} \approx 148.1 \text{ atm}\]
04

Understand Ocean Pressure Increase Definition (b)

For every meter of depth, the pressure increases by \(1.0 \times 10^4\) Pa. Use this information to find the depth that causes the same volume compression.
05

Calculate Necessary Depth

Using the pressure increase per meter:\[1.0 \times 10^4 \text{ Pa/m}\]we need 15,000,000 Pa to compress bones by 0.10%. Calculate the depth by:\[\frac{15 \times 10^6 \text{ Pa}}{1.0 \times 10^4 \text{ Pa/m}} = 1500 \text{ m}\]Thus, the diver would need to go 1500 meters underwater.
06

Analyze if Bone Compression is a Concern

Given that recreational diving rarely exceeds 40m and technical diving may reach a few hundred meters, a depth of 1500 meters is far beyond usual diving limits, so bone compression does not appear to be a significant concern for typical diving scenarios.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Compression of Materials
Compression of materials refers to the ability of a material to decrease in volume when subjected to an external force, such as pressure. This is directly linked to the concept of the bulk modulus, which is a measure of a material's resistance to compression. The higher the bulk modulus, the less compressible the material.

In diving, understanding how materials, such as bones, react to the surrounding pressure is crucial. Bone, with a bulk modulus of 15 GPa, is relatively resistant to compression. When a material's volume is reduced, this can affect its structural integrity, although it typically requires significant forces or pressures to cause notable compression in a material like bone.

The equation used to calculate the pressure needed to compress a material is \[delta P = -K \left(\frac{\Delta V}{V_0}\right)\]where:
  • \( \Delta P \) = the change in pressure
  • \( K \) = the bulk modulus
  • \( \Delta V \) = change in volume
  • \( V_0 \) = original volume
Pressure in Fluids
Pressure in fluids is the force exerted by a fluid per unit area on the surfaces around it. In the context of diving, pressure from fluids, like water, increases with depth due to the weight of the water above. This is why divers experience more pressure the deeper they dive.

A key formula to understand is how pressure changes with depth, given by:
\[\Delta P = \rho g h\]where:
  • \( \rho \) = density of the fluid (in kg/m³)
  • \( g \) = acceleration due to gravity (approximately 9.81 m/s²)
  • \( h \) = depth of the fluid (in meters)
In practical scenarios, each meter of freshwater depth adds approximately 10,000 Pa (pascals) to the pressure. Therefore, as one dives deeper, this cumulative increase in pressure can affect compressible objects, such as a diver's air supply and tissues.
Volume Change
Volume change in materials occurs when they are subjected to pressures beyond their natural state. In diving scenarios, such changes need to be carefully monitored, particularly for materials with critical functions or biological structures, like bones.

For bone compression, the concern stems from understanding how much a material can decrease or expand in volume without compromising safety. Calculations show that for human bone to compress significantly (by 0.10%), a diver must be exposed to very high pressures, such as those found at extreme ocean depths (about 1500 meters below the surface).

This type of compression can be calculated by:\[\frac{\Delta V}{V_0} = -\frac{\Delta P}{K}\]where:
  • \( \Delta V \) = the change in volume
  • \( V_0 \) = the original volume
  • \( \Delta P \) = the pressure change
  • \( K \) = the bulk modulus
In typical diving scenarios, such compression is irrelevant because diving rarely approaches such depths. Understanding these concepts helps divers recognize the limits of equipment and human capacity when facing pressure changes underwater.

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Most popular questions from this chapter

Bulk Modulus of an Ideal Gas. The equation of state (the equation relating pressure, volume, and temperature) for an ideal gas is \(p V=n R T,\) where \(n\) and \(R\) are constants. (a) Show that if the gas is compressed while the temperature \(T\) is held constant, the bulk modulus is equal to the pressure. (b) When an ideal gas is compressed without the transfer of any heat into or out of it, the pressure and volume are related by \(p V^{\gamma}=\) constant, where \(\gamma\) is a constant having different values for different gases. Show that, in this case, the bulk modulus is given by \(B=\gamma p\)

Stress on a Mountaineer's Rope. A nylon rope used by mountaineers elongates 1.10 \(\mathrm{m}\) under the weight of a 65.0 -kg climber. If the rope is 45.0 \(\mathrm{m}\) in length and 7.0 \(\mathrm{mm}\) in diameter, what is Young's modulus for nylon?

CP Blo Stress on the Shin Bone. The compressive strength of our bones is important in everyday life. Young's modulus for bone is about \(1.4 \times 10^{10}\) Pa. Bone can take only about a 1.0\(\%\) change in its length before fracturing. (a) What is the maximum force that can be applied to a bone whose minimum cross- sectional area is 3.0 \(\mathrm{cm}^{2} ?\) (This is approximately the cross-sectional area of a tibia, or shin bone, at its narrowest point.) (b) Estimate the maximum height from which a 70 -kg man could Jump and not fracture the tibia. Take the time between when he first touches the floor and when he has stopped to be 0.030 s, and assume that the stress is distributed equally between his legs.

A uniform, 7.5 - long beam weighing 5860 N is hinged to a wall and supported by a thin cable attached 1.5 \(\mathrm{m}\) from the free end of the beam. The cable runs between the beam and the wall and makes a \(40^{\circ}\) angle with the beam. What is the tension in the cable when the beam is at an angle of \(30^{\circ}\) above the horizontal?

If you put a uniform block at the edge of a table, the center of the block must be over the table for the block not to fall off. (a) If you stack two identical blocks at the table edge, the center of the top block must be over the bottom block, and the center of gravity of the two blocks together must be over the table. In terms of the length \(L\) of each block, what is the maximum overhang possible (Fig. \(P 11.78 ) ?\) (b) Repeat part (a) for three identical blocks and for four identical blocks. (c) Is it possible to make a stack of blocks such the uppermost block is not directly over the table at all? How many blocks would it take to do this? (Try this with your friends using copies of this book.)

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