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Bulk Modulus of an Ideal Gas. The equation of state (the equation relating pressure, volume, and temperature) for an ideal gas is \(p V=n R T,\) where \(n\) and \(R\) are constants. (a) Show that if the gas is compressed while the temperature \(T\) is held constant, the bulk modulus is equal to the pressure. (b) When an ideal gas is compressed without the transfer of any heat into or out of it, the pressure and volume are related by \(p V^{\gamma}=\) constant, where \(\gamma\) is a constant having different values for different gases. Show that, in this case, the bulk modulus is given by \(B=\gamma p\)

Short Answer

Expert verified
(a) Isothermal: Bulk modulus, \( B = P \). (b) Adiabatic: Bulk modulus, \( B = \gamma P \).

Step by step solution

01

Define Bulk Modulus for Isothermal Process

The bulk modulus, denoted as \( B \), is a measure of a material's resistance to compressibility. It is defined as \( B = -V \left( \frac{dP}{dV} \right) \), where \( V \) is the volume and \( P \) is the pressure. For an isothermal process, temperature \( T \) remains constant.
02

Derive the Bulk Modulus for Isothermal Compression

Using the ideal gas law \( PV = nRT \), with \( T \) constant, differentiate both sides with respect to \( V \). This yields \( P + V \left( \frac{dP}{dV} \right) = 0 \). Solve for \( \frac{dP}{dV} \) to get \( \frac{dP}{dV} = -\frac{P}{V} \). Substitute this into the bulk modulus formula: \( B = -V \left(-\frac{P}{V}\right) = P \). Thus, when an ideal gas is compressed isothermally, \( B = P \).
03

Define Bulk Modulus for Adiabatic Process

For an adiabatic process, where no heat is exchanged, the pressure \( P \) and volume \( V \) are related by \( PV^\gamma = \text{constant} \), with \( \gamma \) typically greater than 1. We need to find the bulk modulus \( B \) in this context.
04

Derive the Bulk Modulus for Adiabatic Compression

Start by differentiating \( PV^\gamma = C \). This yields \( V^\gamma \frac{dP}{dV} + \gamma PV^{\gamma-1} = 0 \). Solving for \( \frac{dP}{dV} \) gives \( \frac{dP}{dV} = -\frac{\gamma P}{V} \). Substitute this in the bulk modulus equation: \( B = -V \left(-\frac{\gamma P}{V}\right) = \gamma P \). Hence, for adiabatic compression, \( B = \gamma P \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Ideal Gas Law
The Ideal Gas Law is a fundamental equation that describes the relationship between pressure, volume, and temperature for an ideal gas. The equation is given by \( pV = nRT \), where:
  • \( p \) stands for pressure
  • \( V \) represents volume
  • \( n \) denotes the number of moles of the gas
  • \( R \) is the ideal gas constant
  • \( T \) is the temperature in Kelvin
The law assumes that the gas molecules do not interact with each other and occupy no volume themselves. This approximation works well under high temperature and low pressure conditions.
In the exercise provided, the Ideal Gas Law is applied under two conditions. In an isothermal process, where temperature \( T \) is kept constant, the pressure and volume remain in inverse relation. On the other hand, the adiabatic process requires that no heat is transferred to or from the system, which affects the interaction between pressure and volume.
Isothermal Process
In an isothermal process, the temperature of the gas remains constant throughout the compression or expansion. This means that the internal energy of the system is fixed.
In this process, as the exercise shows, when volume decreases, pressure must increase to keep the product \( pV \) constant, as described by the Ideal Gas Law \( pV = nRT \).
To determine the bulk modulus \( B \) for an isothermal process, we use the relationship \( B = -V \left( \frac{dP}{dV} \right) \). Upon differentiating the Ideal Gas Law with respect to \( V \) and keeping \( T \) constant, it yields \( \frac{dP}{dV} = -\frac{P}{V} \). Substituting this into the bulk modulus formula gives us \( B = P \). Therefore, in an isothermal process, the bulk modulus equals the pressure \( P \).
This indicates the gas's resistance to compression is directly related to the pressure itself. It's a pivotal concept that tells us about the manner in which gases respond to compression when temperature does not change.
Adiabatic Process
An adiabatic process is a thermodynamic transformation where no heat is exchanged with the environment. This typically results in temperature changes within the gas itself.
The relationship between pressure and volume in an adiabatic process is described by \( pV^\gamma = \text{constant} \), where \( \gamma \) is the adiabatic index, a constant that varies for different gases.
To find the bulk modulus \( B \) during adiabatic compression, the differentiation of the adiabatic relation gives \( \frac{dP}{dV} = -\frac{\gamma P}{V} \). When plugged into the bulk modulus equation \( B = -V \left( \frac{dP}{dV} \right) \), it simplifies to \( B = \gamma P \).
This formula informs us that the gas's resistance to being compressed in an adiabatic process is not only dependent on the current pressure \( P \) but is also affected by \( \gamma \), reflecting the nature of the gas itself. This makes adiabatic processes distinct, as the parameters are interlinked without thermal interaction with the surroundings.

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