/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 102 1.102 whe vector \(\vec{r}=x \ha... [FREE SOLUTION] | 91Ó°ÊÓ

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1.102 whe vector \(\vec{r}=x \hat{\imath}+y \hat{\jmath}+z \hat{k},\) called the position vec-tor, points from the origin \((0,0,0)\) to an arbitrary point in space with coordinates \((x, y, z) .\) Use what you know about vectors to prove the following: All points \((x, y, z)\) that satisfy the equation \(A x+B y+C z=0,\) where \(A, B,\) and \(C\) are constants, lie in a plane that passes through the origin and that is perpendicular to the vector \(A \hat{\imath}+B \hat{J}+C \hat{k} .\) Sketch this vector and the plane.

Short Answer

Expert verified
The equation \(Ax + By + Cz = 0\) defines a plane through the origin, perpendicular to vector \(A \hat{\imath} + B \hat{\jmath} + C \hat{k}\).

Step by step solution

01

Understand the problem statement

We need to show that all points \((x, y, z)\) satisfying the equation \(Ax + By + Cz = 0\) form a plane through the origin and perpendicular to the vector \(\vec{n} = A \hat{\imath} + B \hat{\jmath} + C \hat{k}\). These points are described by the position vector \(\vec{r} = x \hat{\imath} + y \hat{\jmath} + z \hat{k}\).
02

Recall the dot product condition for perpendicular vectors

Two vectors are perpendicular if their dot product is zero. In this case, the vector \(\vec{n} = A \hat{\imath} + B \hat{\jmath} + C \hat{k}\) is perpendicular to any vector \(\vec{r} = x \hat{\imath} + y \hat{\jmath} + z \hat{k}\) lying in the plane.
03

Calculate the dot product

The dot product \(\vec{r} \cdot \vec{n}\) is calculated as follows: \[ \vec{r} \cdot \vec{n} = (x \hat{\imath} + y \hat{\jmath} + z \hat{k}) \cdot (A \hat{\imath} + B \hat{\jmath} + C \hat{k}) = Ax + By + Cz. \]
04

Set up the perpendicular condition

Since \(Ax + By + Cz = 0\) is given, it equals \(\vec{r} \cdot \vec{n} = 0\). This satisfies the condition for \(\vec{n}\) and \(\vec{r}\) being perpendicular, meaning \(\vec{r}\) lies in a plane through the origin, perpendicular to \(\vec{n}\).
05

Sketch the vector and the plane

In a 3D coordinate system, sketch the vector \(\vec{n} = A \hat{\imath} + B \hat{\jmath} + C \hat{k}\) starting at the origin pointing towards \((A, B, C)\). The plane intersects the origin and is oriented such that it is perpendicular to \(\vec{n}\). All vectors \(\vec{r}\) satisfying \(Ax + By + Cz = 0\) lie in this plane.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Position Vector
A position vector is used to locate a point in space. Think of it as an arrow pointing from the origin (0, 0, 0) of a coordinate system to any desired point. This vector is represented as \( \vec{r} = x \hat{\imath} + y \hat{\jmath} + z \hat{k} \), where \( x \), \( y \), and \( z \) are the coordinates of the point. This vector tells us exactly where that point is.
- **Origin**: The starting point of the position vector is always the origin.- **Direction**: The direction of the vector indicates which way the point is from the origin.- **Magnitude**: The magnitude (or length) of the vector denotes the distance of the point from the origin.
Understanding the position vector is essential for tasks like locating planes in 3D space.It helps visualize how points are set relative to the center of the coordinate system.
Dot Product
The dot product is a mathematical operation that allows us to determine the relationship between two vectors based on the angle between them. For vectors \( \vec{a} = a_1 \hat{\imath} + a_2 \hat{\jmath} + a_3 \hat{k} \) and \( \vec{b} = b_1 \hat{\imath} + b_2 \hat{\jmath} + b_3 \hat{k} \), their dot product is \( \vec{a} \cdot \vec{b} = a_1b_1 + a_2b_2 + a_3b_3 \). This equation calculates a single scalar value.
The dot product highlights two main points:- **Perpendicularity**: If the dot product is zero, the two vectors are perpendicular. This means the vectors are at a 90-degree angle to each other.- **Projection**: It also measures the extent one vector goes in the direction of the other.
When applied to a vector problem such as determining whether a vector lies in a certain plane, the dot product becomes a crucial calculation tool.
Plane Equation
A plane in geometry can be imagined as a flat surface extending indefinitely. Planes are described by an equation of the form \( Ax + By + Cz = D \), where \( A \), \( B \), and \( C \) are constants and \( D \) determines the plane's distance from the origin.
In this specific exercise, the equation \( Ax + By + Cz = 0 \) represents a plane passing through the origin.
- **Plane Components**: The constants \( A \), \( B \), and \( C \) indicate the plane's orientation. They essentially form a vector, \( \vec{n} = A \hat{\imath} + B \hat{\jmath} + C \hat{k} \), which is normal to this plane.- **Function**: The plane equation helps determine if a specific point lies on that plane.In practical terms, such equations allow us to graphically represent spaces and understand how different points and lines interact within those spaces.
Perpendicular Vectors
Perpendicular vectors intersect at a right angle, denoted as 90 degrees. This concept is crucial in understanding vector relationships in 3D space. If two vectors, say \( \vec{a} \) and \( \vec{b} \), have a dot product of zero, then they are perpendicular, or orthogonal, to each other.
- **Geometric Interpretation**: In simple terms, if you draw these vectors starting from the same point, they would form an "L" shape, indicating a perpendicular or right-angle relationship.- **Equation Indicator**: When solving vector equations, achieving a dot product of zero indicates the vectors are perpendicular. This is used for problems involving planes and lines in space.
Understanding perpendicular vectors is vital as they provide insights into the structure and orientation of lines, planes, and various vector forms, especially in equations governing planes and directions.

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Most popular questions from this chapter

You are camping with two friends, Joe and Karl. Since all three of you like your privacy, you don't pitch your tents close together. Joe's tent is 21.0 \(\mathrm{m}\) from yours, in the direction \(23.0^{\circ}\) south of east. Karl's tent is 32.0 \(\mathrm{m}\) from yours, in the direction \(37.0^{\circ}\) north of east. What is the distance between Karl's tent and Joe's tent?

While driving in an exotic foreign land you see a speed limit sign on a highway that reads \(180,000\) furlongs per fortnight. How many miles per hour is this? (One furlong is \(\frac{1}{8}\) mile, and a fortnight is 14 days. A furlong originally referred to the length of a plowed furrow.)

Completed Pass. At Enormous State University \((\) ESU), the football team records its plays using vector displace- ments, with the origin taken to be the position of the ball before the play starts. In a certain pass play, the receiver starts at \(+1.0 \hat{\imath}-5.0 \hat{\boldsymbol{J}},\) where the units are yards, \(\hat{\boldsymbol{\imath}}\) is to the right, and \(\hat{J}\) is downfield. Subsequent displacements of the receiver are \(+9.0 \hat{\imath}\) (in motion before the snap), \(+11.0 \hat{J}\) (breaks downfield), \(-6.0 \hat{\imath}+4.0 \hat{J}(\) zigs \(),\) and \(+12.0 \hat{\imath}+18.0 \hat{\jmath}(\) zags \() .\) Meanwhile, the quarterback has dropped straight back to a position \(-7.0 \hat{\jmath} .\) How far and in which direction must the quarterback throw the ball? (Like the coach, you will be well advised to diagram the situation before solving it numerically.)quarterback has dropped straight back to a position \(-7.0 \hat{\jmath} .\) How far and in which direction must the quarterback throw the ball? (Like the coach, you will be well advised to diagram the situation before solving it numerically.)

Find the angle between each of the following pairs of vectors: $$(a)\vec{A}=-2.00 \hat{\imath}+6.00 \hat{J} \quad\( and \)\quad \vec{B}=2.00 \hat{\imath}-3.00 \hat{J}$$ $$(b) \vec{A}=3.00 \hat{\imath}+5.00 \hat{J} \quad\( and \)\quad \vec{B}=10.00 \hat{\imath}+6.00 \hat{J}$$ $$(c)\vec{A}=-4.00 \hat{\imath}+2.00 \hat{J} \quad\( and \)\quad \vec{B}=7.00 \hat{\imath}+14.00 \hat{J}$$

Stars in the Universe. Astronomers frequently say that there are more stars in the universe than there are grains of sand on all the beaches on the earth. (a) Given that a typical grain of sand is about 0.2 \(\mathrm{mm}\) in diameter, estimate the number of grains of sand on all the earth's beaches, and hence the approximate number of stars in the universe. It would be helpfult an atlas and do some measuring. (b) Given that a typical galaxy contains about 100 billion stars and there are more than 100 billion galaxies in the known universe, estimate the number of stars in the universe and compare this number with your result from part (a).

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