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Apparent Weight. A 550 -N physics student stands on a bathroom scale in an \(850-k g\) (including the student) elevator that is supported by a cable. As the elevator starts moving, the scale reads 450 \(\mathrm{N}\) . (a) Find the acceleration of the elevator (magnitude and direction). (b) What is the acceleration if the scale reads 670 \(\mathrm{N}\) ? (c) If the scale reads zero, should the student worry? Explain. (d) What is the tension in the cable in parts (a) and (c)?

Short Answer

Expert verified
(a) Acceleration is -1.78 m/s² downwards; (b) 2.14 m/s² upwards; (c) Yes, worry due to free fall; (d) Tension is 8150 N for (a), 0 N for (c).

Step by step solution

01

Determine Accelerations

The apparent weight changes when the elevator accelerates. Use Newton’s second law: \( F_{net} = m imes a \). Consider: (a) When the scale reads 450 N, the net force \( F_{net} \) is \( 450 - 550 = -100 \, \text{N} \). Thus, \( -100 \text{ N} = (550 \text{ N} / 9.8 \text{ m/s}^2) \times a \). Solve for \( a \): \( a = -1.78 \, \text{m/s}^2 \) (downward). (b) For 670 N, \( F_{net} = 670 - 550 = 120 \, \text{N} \). Solve for \( a \): \( a = 2.14 \, \text{m/s}^2 \) (upward).
02

Scale Reading Zero

(c) If the scale reads zero, the apparent weight becomes 0 N. This means the elevator is in free fall. The net force \( F_{net} = -550 \, \text{N} = (550 \text{N} / 9.8 \text{m/s}^2) \times (-9.8\, \text{m/s}^2) \), meaning \( a = -9.8 \, \text{m/s}^2 \). Yes, the student should worry as it indicates a free fall.
03

Compute Tension in the Cable

(d) To find the tension in the cable, use the formula: \( T = W + F_{net} \), where \( W = mg \) is the total weight (850 kg times 9.8 m/s²). (a) For 450 N reading: \( F_{net} = -100 \, \text{N} \), so \( T = 850 \times 9.8 - 100 = 8150 \, \text{N} \). (c) When scale reads zero, elevator is in free fall: \( T = 0 \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Newton's Second Law
Newton's Second Law is a fundamental concept in physics. It explains how the velocity of an object changes when it is subjected to an external force. It is expressed mathematically as \( F_{\text{net}} = m \times a \), where \( F_{\text{net}} \) is the net force acting on an object, \( m \) is the mass, and \( a \) is the acceleration. This formula tells us how forces influence motion.

In the context of the exercise, when a 550-N student stands in an elevator, and the elevator starts to accelerate, the forces involved affect the reading on the scale. For example, if the scale reads 450 N, it reflects the apparent weight of the student when the elevator is moving downward, indicating a negative acceleration. Conversely, if the scale reads 670 N, the elevator is moving upward, and the apparent weight increases due to positive acceleration.

When analyzing problems with changing apparent weight, remember that the difference between the actual gravitational force and the reading on the scale is due to the acceleration of the elevator. By applying Newton's Second Law, we can calculate the elevator's acceleration either as positive (upward) or negative (downward) by rearranging the formula to solve for \( a \).
Free Fall
Free fall describes a specific condition where gravity is the only force acting on an object. This means no other external forces, like tension from a cable, oppose the gravitational force, causing the object to accelerate downward at \( 9.8 \, \text{m/s}^2 \).

In the exercise, if the scale reads zero, the elevator is in free fall. This scenario suggests that the student and the elevator are accelerating downward at the acceleration due to gravity. This leads to zero apparent weight, which is why the scale reads zero.

Understanding free fall is crucial because it indicates that the elevator's cables are not providing any support. Generally, this would be a cause for concern, as it may suggest a malfunction or breakage supporting the system, leading to potential safety risks. In real-world applications, it is essential to ensure elevators or similar systems have mechanisms to prevent free fall to protect passengers.
Elevator Physics
Elevator physics often involves applying concepts of forces and motion to understand how an elevator's movement affects its apparent weight readings. One common example is "apparent weight," which changes based on the elevator's acceleration. When an elevator accelerates upwards or downwards, the forces acting on the passengers lead to changes in apparent weight.

Key points in understanding elevator physics include:
  • **Apparent Weight**: When the elevator accelerates upward, apparent weight increases because the force exerted by the floor adds to gravitational force. In contrast, during downward acceleration, the apparent weight decreases as the lift force subtracts from gravity.

  • **Safety Systems**: Elevators typically include braking systems and suspension cables designed to prevent dangerous scenarios like free falls. In a free fall scenario, the apparent weight is zero, indicating a risk.

  • **Tension and Forces**: The cable holds the lift system in place by counteracting gravitational force, which is affected when acceleration occurs. Calculating the tension helps understand the forces involved as the elevator moves.

These concepts not only help solve physics problems but also improve practical understanding, such as safety design in elevators to ensure passengers' security by preventing uncontrolled accelerations.

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