/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 51 A \(1125-k g\) car and a \(2250-... [FREE SOLUTION] | 91Ó°ÊÓ

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A \(1125-k g\) car and a \(2250-k g\) pickup truck aproach a curve on the expressway that has a radius of 225 \(\mathrm{m}\) . (a) At what angle should the highway engineer bank this curve so that vehicles traveling at 65.0 \(\mathrm{mi} / \mathrm{h}\) can safely round it regardless of the condition of their tires? Should the heavy truck go slower than the lighter car? (b) As the car and truck round the curve at 65.0 \(\mathrm{mi} / \mathrm{h}\) , find the normal force on each one due to the highway surface.

Short Answer

Expert verified
(a) The highway should be banked at approximately \(20.3^\circ\). The truck doesn't need to go slower. (b) Normal forces: Car \(\approx 10333.3 \text{ N}\), Truck \(\approx 20666.6 \text{ N}\).

Step by step solution

01

Convert Velocity to Meters per Second

To perform calculations, we must first convert velocity from miles per hour (mi/h) to meters per second (m/s). We know that 1 mile = 1609.34 meters. Therefore, the velocity,\[v = 65.0 \text{ mi/h} = 65.0 \times \frac{1609.34\, \text{m}}{3600 \text{s}} \approx 29.06 \text{ m/s}.\]
02

Determine Banking Angle Using Centripetal Force Equation

For safe travel around a banked curve, the following equation applies:\[\tan(\theta) = \frac{v^2}{rg}\]where \(v\) is the speed of the vehicle, \(r\) is the radius of the curve, and \(g\) is the acceleration due to gravity (\(9.81 \text{ m/s}^2\)). Substituting the known values:\[\tan(\theta) = \frac{(29.06)^2}{225 \times 9.81}\approx 0.371.\]
03

Solve for the Banking Angle

Using the value from Step 2, solve for \(\theta\):\[\theta = \tan^{-1}(0.371) \approx 20.3^\circ.\]The engineer should bank the curve at an angle of approximately \(20.3^\circ\). The truck and car can both travel safely at this angle regardless of weight, so the truck does not need to go slower.
04

Calculate Normal Force for Both Vehicles

The normal force \(F_N\) acts perpendicular to the surface and provides the centripetal force needed to keep the vehicle on a curve. Use the component of the gravitational force perpendicular to the incline:\[F_N = mg \cos(\theta)\]For the car,\[F_N = 1125 \times 9.81\times \cos(20.3^\circ) \approx 10333.3 \text{ N}.\]For the truck,\[F_N = 2250 \times 9.81 \times \cos(20.3^\circ) \approx 20666.6 \text{ N}.\]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Centripetal Force
Centripetal force is the force required to keep an object moving in a circular path, directed towards the center of the circle. When a car or truck moves along a curved road, it experiences this type of force. In the context of a banked curve, where the road is tilted or inclined, understanding centripetal force is vital. It is defined by the equation:
  • \[ F_c = \frac{mv^2}{r} \]
Here, \( m \) represents the mass of the vehicle, \( v \) is the velocity, and \( r \) is the radius of the curve.
When considering safe travel around a banked curve, the force is provided not solely by friction, but by the gravitational force and the normal force combined. This distribution lessens the reliance on tire grip, providing a safer experience regardless of weather conditions.
The angle of banking ensures that the centripetal force, needed to keep the vehicle from sliding off the road when negotiating the curve, is maintained. The significance of this comes into play heavily in highway design, where engineers compute such forces to determine necessary banking angles to prevent accidents.
Banked Curve
A banked curve is a turn or change in direction in which the surface has been inclined toward the center of the curvature. This design helps vehicles negotiate the curve safely, by utilizing not just friction but also gravitational and normal forces.
  • The ideal banking angle ensures that a vehicle can pass through the curve at a specified speed without relying on frictional force.
  • The equation for calculating the banking angle \( \theta \) is derived from the relationship:\[ \tan(\theta) = \frac{v^2}{rg} \]where:
    • \( v \): velocity of the vehicle,
    • \( r \): radius of the curve,
    • \( g \): acceleration due to gravity \( (9.81 \text{ m/s}^2) \).
To ensure vehicles remain safe on curved paths regardless of speed and weather conditions, roads are often banked. The equation above helps determine the optimal angle. For instance, in the provided scenario, once calculations are complete, we find that a banking angle of approximately \(20.3^\circ\) is safe for vehicles moving at 65.0 miles per hour. Such a clever design ensures both trucks and cars can safely navigate the curve without adjusting speed due to differing weights.
Normal Force
Normal force is a crucial concept in mechanics, particularly when dealing with inclines or banked curves. In a banked curve scenario, it is the perpendicular component of the contact force exerted by a surface that acts to support the weight of an object resting on it.
  • Normal force \( F_N \) plays a dual role:
    • It balances the component of gravitational force acting perpendicular to the road.
    • Provides the centripetal force required to allow the vehicles to negotiate the curve.
  • The calculation for normal force on a banked curve is expressed as: \[ F_N = mg \cos(\theta) \]where:
    • \( m \): mass of the vehicle,
    • \( g \): acceleration due to gravity,
    • \( \theta \): angle of the bank.
    For instance:
    • For the car weighing 1125 kg, \( F_N \) computes to approximately \(10333.3 \text{ N}\).
    • For the truck at 2250 kg, it calculates to about \(20666.6 \text{ N}\).

    Both these values ensure the vehicles adhere to the curved path effectively, with the normal force adequately balancing the gravitational pull to provide safe, consistent motion around the bend.

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Most popular questions from this chapter

A box with mass \(m\) is dragged across a level fioor having a coefficient of kinctic friction \(\mu_{k}\) by a rope that is pulled upward at an angle \(\theta\) above the horizontal with a force of magnitude \(F .(\text { a) In }\) terms of \(m, \mu_{k}, \theta,\) and \(g,\) obtain an expression for the magnitude of force required to move the box with constant speed. (b) Knowing that you are studying physics, a CPR instructor asks you how much force it would take to slide a \(90-\mathrm{kg}\) patient across a floor at constant speed by pulling on him at an angle of \(25^{\circ}\) above the borizontal. By dragging some weights wrapped in an old pair of pants down the hall with a spring balance, you find that \(\mu_{k}=0.35 .\) Use the result of part (a) to answer the instructor's question.

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