/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 34 (a) What is the lowest possible ... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

(a) What is the lowest possible energy (in electron volts) of an electron in hydrogen if its orbital angular momentum is \(\sqrt{12} \mathrm{k}\) ? (b) What are the largest and smallest values of the \(z\) -component of the orbital angular momentum (in terms of \(\hbar\) ) for the electron in part (a)? (c) What are the largest and smallest values of the spin angular momentum (in terms of \(\hbar\) ) for the electron in part (a)? (d) What are the largest and smallest values of the orbital angular momentum (in terms of \(\hbar\) ) for an electron in the \(M\) shell of hydrogen?

Short Answer

Expert verified
(a) -0.85 eV; (b) \(3\hbar, -3\hbar\); (c) \(\frac{\sqrt{3}}{2}\hbar, \frac{\sqrt{3}}{2}\hbar\); (d) \(\sqrt{6}\hbar, 0\).

Step by step solution

01

Calculate Principal Quantum Number (n)

The orbital angular momentum is given by the equation \( L = \sqrt{l(l+1)} \hbar \). The problem states \( L = \sqrt{12} \hbar \). So we equate: \( \sqrt{l(l+1)} = \sqrt{12} \). Squaring both sides gives \( l(l+1) = 12 \). Solving this, we find \( l = 3 \). Since \( n > l \), the lowest possible \( n \) is 4.
02

Calculate the Lowest Energy (in eV)

The energy level for an electron in a hydrogen atom is given by \( E_n = -13.6 \text{ eV} / n^2 \). For \( n = 4 \), the energy is \( E_4 = -13.6 / 4^2 = -0.85 \text{ eV} \).
03

Identify the Largest and Smallest Lz (z-component of L)

The largest and smallest values of the z-component of the angular momentum \( L_z \) are given by \( L_z = m_l \hbar \) where \( m_l \) can be any integer between \( -l \) and \( l \). For \( l = 3 \), \( m_l \) ranges from -3 to 3. Thus, the largest value of \( L_z \) is \( 3 \hbar \), and the smallest value is \( -3 \hbar \).
04

Determine Spin Angular Momentum Values

The spin angular momentum of an electron is given by \( S = \sqrt{s(s+1)} \hbar \), where \( s = \frac{1}{2} \) for electrons. Therefore, \( S = \frac{\sqrt{3}}{2} \hbar \). The largest and smallest z-components of spin \( S_z \) are \( \frac{1}{2} \hbar \) and \( -\frac{1}{2} \hbar \), respectively.
05

Orbital Angular Momentum for M Shell

The M shell corresponds to \( n = 3 \). The possible values for \( l \) are 0, 1, and 2. The orbital angular momentum is maximized for \( l = 2 \), yielding \( L = \sqrt{6} \hbar \). The smallest possible \( L \) for \( l = 0 \) is 0.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Electron Orbital Angular Momentum
Orbital angular momentum in quantum mechanics describes the motion of electrons around the nucleus of an atom. It is designated by the symbol \( L \) and is crucial for defining the properties of electron orbitals. Angular momentum is quantized, meaning electrons can only occupy states with specific, discrete values.

The formula for orbital angular momentum is \( L = \sqrt{l(l+1)} \hbar \), where \( l \) is the azimuthal quantum number, and \( \hbar \) is the reduced Planck's constant. For example, if \( l = 3 \), the value of \( L \) becomes \( \sqrt{12} \hbar \).

The \( l \) quantum number describes the electron's subshell or shape of its orbital and is always a non-negative integer. It ranges from 0 to \( n-1 \), where \( n \) is the principal quantum number. The values of \( l \) correspond to various subshells: \( l=0 \) for s, \( l=1 \) for p, \( l=2 \) for d, and \( l=3 \) for f subshells.
Principal Quantum Number
The principal quantum number, denoted as \( n \), primarily determines an electron's energy level and distance from the nucleus. It is a positive integer and plays a critical role in the structure of electron orbitals within an atom.

In a hydrogen atom, the energy levels are marked by the formula \( E_n = -\frac{13.6\, \, \text{eV}}{n^2} \), demonstrating that energy is inversely proportional to the square of \( n \). Larger values of \( n \) indicate electrons positioned farther from the nucleus and higher energy levels, while smaller \( n \) values imply lower energies and tighter electron binding.

Additionally, \( n \) affects the number of possible values for \( l \). As shown in the given exercise, if \( l = 3 \), \( n \) must be at least 4, ensuring \( n \) is larger than \( l \). This relationship maintains the integrity of electron configurations within atoms.
Spin Angular Momentum
Spin angular momentum is intrinsic to particles such as electrons and represents a form of angular momentum independent of any rotational or translational motion around an external point. In quantum mechanics, it is fundamental and cannot be visualized in the same manner as classical spinning.

Electrons possess a spin value of \( s = \frac{1}{2} \). The formula for spin angular momentum is \( S = \sqrt{s(s+1)} \hbar \), resulting in \( S = \frac{\sqrt{3}}{2} \hbar \) for electrons.

The z-component of spin angular momentum \( S_z \) can take on values of \( \pm \frac{1}{2} \hbar \), reflecting the two possible orientations or spin states of an electron: spin-up \( (\frac{1}{2} \hbar) \) and spin-down \( (-\frac{1}{2} \hbar) \). These properties contribute extensively to the magnetic characteristics and overall behavior of atoms.
Hydrogen Atom Energy Levels
Hydrogen, being the simplest atom with only one electron, serves as an excellent model for studying atomic structures and offers insights into the nature of quantum systems.

The energy levels in a hydrogen atom are well-defined, thanks to the principal quantum number \( n \). These levels are quantized, meaning the electron can occupy only certain allowed energy states. As previously mentioned, the energy is calculated using \( E_n = -\frac{13.6\, \, \text{eV}}{n^2} \). This equation reveals that energy levels become closer together as \( n \) increases, which means an electron in higher energy levels requires less energy to move between adjacent levels.

In this quantum model, the negative sign indicates that the electron is bound to the nucleus, with higher energy states closer to zero being less tightly bound. These quantized energy levels are crucial for understanding spectral lines and transitions in atoms, such as those employed in spectroscopic analysis.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

List the different possible combinations of \(l\) and \(j\) for a hydrogen atom in the \(n=3\) level.

(a) The energy of an electron in the 4\(s\) state of sodium is \(-1.947 \mathrm{eV} .\) What is the effective net charge of the nucleus "seen" by this electron? On the average, how many electrons screen the nucleus? (b) For an outer electron in the 4\(p\) state of potassium, on the average 17.2 inner electrons screen the nucleus. (i) What is the effective net charge of the nucleus "seen" by this outer electron? (ii) What is the energy of this outer electron?

An electron is in the hydrogen atom with \(n=3 .\) (a) Find the possible values of \(L\) and \(L_{z}\) for this electron, in units of \(\hbar .\) (b) For each value of \(L,\) find all the possible angles between \(L\) and the \(z\) -axis.

(a) The doubly charged ion \(\mathrm{N}^{2+}\) is formed by removing two electrons from a nitrogen atom. What is the ground-state electron configuration for the \(\mathrm{N}^{2+}\) ion? (b) Estimate the energy of the least strongly bound level in the \(L\) shell of \(\mathrm{N}^{2+}\) . (c) The doubly charged ion \(\mathrm{P}^{2+}\) is formed by removing two electrons from a phosphorus atom. What is the ground-state electron configuration for the \(\mathrm{P}^{2+}\) ion? (d) Estimate the energy of the least strongly bound level in the \(M\) shell of \(\mathbf{P}^{2+}\) .

For germanium (Ge, \(Z=32 )\) , make a list of the number of electrons in each subshell \((1 s, 2 s, 2 p, \ldots) .\) Use the allowed values of the quantum numbers along with the exclusion principle; do not refer to Table 41.3 .

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.