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An electron is in the hydrogen atom with \(n=3 .\) (a) Find the possible values of \(L\) and \(L_{z}\) for this electron, in units of \(\hbar .\) (b) For each value of \(L,\) find all the possible angles between \(L\) and the \(z\) -axis.

Short Answer

Expert verified
(a) Possible \(L\) values: 0, \(\sqrt{2}\hbar\), \(\sqrt{6}\hbar\); \(L_z\) values: 0, -\(\hbar, \hbar\) for \(l=1\), -2\(\hbar\) to 2\(\hbar\) for \(l=2\). (b) Angles for \(l=1\): 135°, 90°, 45°; for \(l=2\): 143.1°, 104.5°, 90°, 75.5°, 36.9°.

Step by step solution

01

Determine possible values of total angular momentum, L

For a hydrogen atom, the principal quantum number is denoted by \(n\). For any given \(n\), the possible azimuthal quantum numbers \(l\) range from 0 to \(n-1\). Therefore, for \(n=3\), \(l\) can be 0, 1, or 2. The magnitude of the angular momentum \(L\) is given by \(L = \sqrt{l(l+1)}\hbar\). Thus, the possible values for \(L\) are: \(L = 0\hbar\) for \(l=0\), \(L = \sqrt{2}\hbar\) for \(l=1\), \(L = \sqrt{6}\hbar\) for \(l=2\).
02

Determine possible values of angular momentum component, Lz

The magnetic quantum number \(m\) ranges from \(-l\) to \(l\) in integer steps. The component of angular momentum along the \(z\)-axis, \(L_z\), is given by \(L_z = m\hbar\). For each \(l\):- \(l=0\): \(m=0\rightarrow L_z=0\hbar\).- \(l=1\): \(m=-1, 0, 1\rightarrow L_z=-\hbar, 0\hbar, \hbar\).- \(l=2\): \(m=-2, -1, 0, 1, 2\rightarrow L_z=-2\hbar, -\hbar, 0\hbar, \hbar, 2\hbar\).
03

Calculate the angles between L and the z-axis

The angle \(\theta\) between \(L\) and the \(z\)-axis can be calculated using the formula: \(\cos \theta = \frac{L_z}{L}\). For each \(l\) and possible \(L_z\):- \(l=0\): \(L=0\hbar\), \(\theta\) is undefined since both \(L\) and \(L_z\) are 0.- \(l=1\), \(L = \sqrt{2}\hbar\): - \(m=-1\): \(\cos \theta = \frac{-\hbar}{\sqrt{2}\hbar}\Rightarrow \theta \approx 135^\circ\) - \(m=0\): \(\cos \theta = 0\Rightarrow \theta = 90^\circ\) - \(m=1\): \(\cos \theta = \frac{\hbar}{\sqrt{2}\hbar}\Rightarrow \theta \approx 45^\circ\)- \(l=2\), \(L = \sqrt{6}\hbar\): - \(m=-2\): \(\cos \theta = \frac{-2\hbar}{\sqrt{6}\hbar}\Rightarrow \theta \approx 143.1^\circ\) - \(m=-1\): \(\cos \theta = \frac{-\hbar}{\sqrt{6}\hbar}\Rightarrow \theta \approx 104.5^\circ\) - \(m=0\): \(\cos \theta = 0\Rightarrow \theta = 90^\circ\) - \(m=1\): \(\cos \theta = \frac{\hbar}{\sqrt{6}\hbar}\Rightarrow \theta \approx 75.5^\circ\) - \(m=2\): \(\cos \theta = \frac{2\hbar}{\sqrt{6}\hbar}\Rightarrow \theta \approx 36.9^\circ\)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Angular Momentum
In quantum mechanics, angular momentum is a fundamental concept that describes the rotation of particles, like electrons within atoms. For an electron in a hydrogen atom, angular momentum is described not as a simple vector like in classical physics, but as quantized quantities. This is due to the principles of quantum mechanics that impose discrete energy states.

To calculate the angular momentum of an electron, we utilize its azimuthal quantum number, denoted as \(l\). For a given principal quantum number \(n\), \(l\) can take values ranging from 0 to \(n-1\). Once we know \(l\), the total angular momentum \(L\) is given by the formula \(L = \sqrt{l(l+1)}\hbar\), where \(\hbar\) is the reduced Planck's constant. This quantized approach allows us to know the specific values that \(L\) can take, providing deeper insights into the behavior and arrangement of electrons in atoms.

In the example of a hydrogen atom with \(n=3\), the possible \(l\) values are 0, 1 and 2, resulting in possible angular momentum values of \(0\hbar\), \(\sqrt{2}\hbar\), and \(\sqrt{6}\hbar\). Each has specific implications for the energy and the characteristic quantum state of the electron.
Quantum Numbers
Quantum numbers are critical for understanding the structure and behavior of electrons in atoms. They define various properties like energy levels, angular momentum, and orientation in space. There are four primary quantum numbers: principal (\(n\)), azimuthal or angular momentum (\(l\)), magnetic (\(m\)), and spin (\(s\)). Together, they provide a unique set of quantum identifiers for electrons.

The principal quantum number \(n\) indicates the electron's energy level, essentially its "shell." Higher \(n\) values mean that the electron is further from the nucleus with higher energy. The azimuthal quantum number \(l\), as discussed, relates to the electron's angular momentum, determining the shape of the orbital it occupies—whether it's spherical, dumbbell-shaped, etc. The magnetic quantum number \(m\) defines the orientation of this orbital in space, while the spin quantum number \(s\) describes the intrinsic spin of the electron, which can be either +1/2 or -1/2.

In the case provided, for \(n=3\), both \(l\) and \(m\) are used to calculate possible states, showing how these quantum mechanics principles concretely determine the boundaries and states available for electrons.
Magnetic Quantum Number
The magnetic quantum number \(m\) is vital for comprehending how electrons behave in the presence of a magnetic field, which impacts their energy and position. The magnetic quantum number specifies the orientation of an electron's orbital around the nucleus. It can take integer values ranging from \(-l\) to \(+l\), including zero.

In practical terms, this means that for each azimuthal quantum number \(l\), \(m\)'s range defines multiple orientations an electron may adopt. Imagine these as the different ways to position a dumbbell in a sphere—a direct result of different magnetic quantum numbers.

In the case of the electron with \(n=3\) and \(l=2\), for example, possible values of \(m\) are -2, -1, 0, 1, and 2. Each of these translates into distinct possible orientations relative to the \(z\)-axis. This becomes especially relevant when you are calculating the component of angular momentum along the \(z\)-axis, \(L_z = m\hbar\). With each \(m\), we derive the angle between the total angular momentum vector \(L\) and the \(z\)-axis, adding more layers to the understanding of the atom's structure and characteristics.

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Most popular questions from this chapter

(a) Show all the distinct states for an electron in the \(N\) shell of hydrogen. Include all four quantum numbers. (b) For an f-electron in the \(N\) shell, what is the largest possible orbital angular momentum and the greatest positive value for the component of this angular momentum along any chosen direction (the \(z\) -axis)? What is the magnitude of its spin angular momentum? Express these quantities in units of \(\hbar\) . (c) For an electron in the \(d\) state of the \(N\) shell, what are the maximum and minimum angles between its angular momentum vector and any chosen direction (the \(z\) -axis)? (d) What is the largest value of the orbital angular momentum for an \(f\) -electron in the \(M\) shell?

(a) If the intrinsic spin angular momentum \(S\) of the earth had the same limitations as that of the electron, what would be the angular velocity of our planet's spin on its axis? To get a reasonable answer but simplify the calculations, assume that the earth is uniform throughout. (b) Could we, in principle, use the method of part (a) to determine the angular velocity of the electron's spin? Why?

Effective Magnetic Field. An electron in a hydrogen atom is in the 2\(p\) state. In a simple model of the atom, assume that the electron circles the proton in an orbit with radius \(r\) equal to the Bohr-model radius for \(n=2 .\) Assume that the speed \(v\) of the orbiting electron can be calculated by setting \(L=m v r\) and taking \(L\) to have the quantum-mechanical value for a 2\(p\) state. In the frame of the electron, the proton orbits with radius \(r\) and speed \(v\) . Model the orbiting proton as a circular current loop, and calculate the magnetic field it produces at the location of the electron.

(a) Show that the total number of atomic states (including different spin states) in a shell of principal quantum number \(n\) is 2\(n^{2}\) . [Hint: The sum of the first \(N\) integers \(1+2+3+\cdots+N\) is equal to \(N(N+1) / 2 . ](\mathrm{b})\) Which shell has 50 states?

(a) The energy of an electron in the 4\(s\) state of sodium is \(-1.947 \mathrm{eV} .\) What is the effective net charge of the nucleus "seen" by this electron? On the average, how many electrons screen the nucleus? (b) For an outer electron in the 4\(p\) state of potassium, on the average 17.2 inner electrons screen the nucleus. (i) What is the effective net charge of the nucleus "seen" by this outer electron? (ii) What is the energy of this outer electron?

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