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An object with mass \(m\) initially at rest is acted on by a force \(\vec{F}=k_{1} \hat{z}+k_{2} t^{3}\) , where \(k_{1}\) and \(k_{2}\) are constants. Calculate the velocity \(\vec{v}(t)\) of the object as a function of time.

Short Answer

Expert verified
The velocity as a function of time is \( \vec{v}(t) = \left( \frac{k_1}{m} t + \frac{k_2}{4m} t^4 \right) \hat{z} \).

Step by step solution

01

Identify the Force Equation

The force acting on the object is given by \( \vec{F} = k_1 \hat{z} + k_2 t^3 \). Here, \( k_1 \) and \( k_2 \) are constants, and \( t \) represents time.
02

Use Newton's Second Law

According to Newton's second law, force \( \vec{F} \) is equal to the mass \( m \) multiplied by acceleration \( \vec{a} \), or \( \vec{F} = m \vec{a} \). Thus, \( m \vec{a} = k_1 \hat{z} + k_2 t^3 \).
03

Solve for Acceleration

Express acceleration \( \vec{a} \) as \( \vec{a} = \frac{k_1}{m} \hat{z} + \frac{k_2}{m} t^3 \). This represents the acceleration of the object as a function of time.
04

Integrate Acceleration to Find Velocity

To find the velocity \( \vec{v}(t) \), integrate the acceleration function with respect to time: \[ \vec{v}(t) = \int \left( \frac{k_1}{m} \hat{z} + \frac{k_2}{m} t^3 \right) dt. \]
05

Compute the Integrals

Perform the integration: \[ \vec{v}(t) = \frac{k_1}{m} \hat{z} \cdot t + \frac{k_2}{m} \cdot \frac{t^4}{4} \hat{z} + \vec{C}, \] where \( \vec{C} \) is the constant of integration. Since the object starts from rest, \( \vec{v}(0) = 0 \), implying \( \vec{C} = 0 \).
06

Final Velocity Function

The velocity function becomes \[ \vec{v}(t) = \left( \frac{k_1}{m} t + \frac{k_2}{4m} t^4 \right) \hat{z}. \] This equation describes the velocity of the object as a function of time.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Force and Motion
To understand how objects move, let’s dive into the world of force and motion. When a force is applied to an object, it causes the object to move, stop, or change direction. The relationship between force and motion is at the heart of classical mechanics. Force can be anything that changes the motion of an object. For example, pulling, pushing, or gravity are all forces that can affect how an object moves.

Newton's Second Law plays a crucial role in describing this relationship. It states that the force acting on an object is equal to the mass of the object multiplied by its acceleration. In mathematical terms, the formula is: \[ F = m imes a \] Where:
  • \( F \) is the force applied to the object.
  • \( m \) is the mass of the object.
  • \( a \) is the acceleration of the object.


This equation tells us that if you know the force applied to an object and its mass, you can easily find out its acceleration, which is the rate of change of its velocity over time. As the force increases, acceleration does too, assuming the mass remains constant. Thus, force directly influences how and where an object will move.
Integration in Physics
Integration in physics is a very useful tool for solving problems related to motion. It allows us to transition from one physical quantity to another. For instance, when we have acceleration (rate of change of velocity) and we aim to find velocity (change in position over time), integration helps us.

Let's explore how integration works in this context. Suppose you have an equation for acceleration that depends on time. By integrating this function with respect to time, we can find the velocity function. Essentially, integration helps us add up all the little changes in acceleration to see how velocity builds over time. The general process involves:
  • Taking the acceleration equation: \[ a(t) = f(t) \]
  • Integrating this with respect to time: \[ v(t) = \int f(t) \, dt \]


It is important to include the constant of integration while solving these problems. This constant represents the initial condition, like the initial velocity in our problem, which is zero since the object starts from rest. By performing this integration, you can elegantly transition from acceleration to velocity.
Acceleration and Velocity
Acceleration and velocity are key concepts in the study of motion. They describe how an object's speed changes with time and the direction of that change. Acceleration is a vector quantity, meaning it has both magnitude and direction. It tells us how quickly the velocity of an object is changing. If an object speeds up or slows down, it’s experiencing acceleration.

Velocity, on the other hand, describes both the speed and direction of an object's motion. It is also a vector quantity. For example, a car moving north at 60 mph has a velocity, while its acceleration would describe how the speed changes over time, like speeding up to 70 mph. \[\vec{a} = \frac{\Delta\vec{v}}{\Delta t} \] Where:
  • \( \Delta\vec{v} \) is the change in velocity.
  • \( \Delta t \) is the change in time.


In practical problems, like the one discussed, calculating acceleration helps to determine velocity over time. Given the formula for the force, we derived the equation for acceleration, and through integration, found the velocity as a function of time. These processes show the beautiful interplay of these concepts in physics and how they help describe motion precisely.

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Most popular questions from this chapter

The position of a \(2.75 \times 10^{5} \mathrm{N}\) training helicopter under test is given by \(\vec{r}=\left(0.020 \mathrm{m} / \mathrm{s}^{3}\right) t^{3} \hat{\imath}+(2.2 \mathrm{m} / \mathrm{s}) f \hat{\jmath}-\left(0.060 \mathrm{m} / \mathrm{s}^{2}\right) t^{2} \hat{k}\) Find the net force on the helicopter at \(t=5.0 \mathrm{s}\)

Two dogs pull horizontally on ropes attached to a post; the angle between the ropes is \(60.0^{\circ} .\) If dog \(A\) exerts a force of 270 \(\mathrm{N}\) and dog \(B\) exerts a force of 300 \(\mathrm{N}\) , find the magnitude of the resultant force and the angle it makes with dog \(A^{\prime}\) s rope.

A spacecraft descends vertically near the surface of Planet X. An upward thrust of 25.0 \(\mathrm{kN}\) from its engines slows it down at a rate of \(1.20 \mathrm{m} / \mathrm{s}^{2},\) but it speeds up at a rate of 0.80 \(\mathrm{m} / \mathrm{s}^{2}\) with an upward thrust of 10.0 \(\mathrm{kN} .(\mathrm{a})\) In each case, what is the direction of the acceleration of the spacecraft? (b) Draw a free-body diagram for the spacecraft. In each case, speeding up or slowing down, what is the direction of the net force on the spacecraft? (c) Apply Newton's second law to each case, slowing down or speeding up, and use this to find the spacecraft's weight near the surface of Planet X.

A gymnast of mass \(m\) climbs a vertical rope attached to the ceiling. You can ignore the weight of the rope. Draw a free-body diagram for the gymnast. Calculate the tension in the rope if the gymnast (a) climbs at a constant rate; (b) hangs motionless on the rope; (c) accelerates up the rope with an acceleration of magnitude \(|\vec{a}| ;(\text { d) slides down the rope with a downward acceleration of }\) magnitude \(|\vec{a}| .\)

A truck is pulling a car on a horizontal highway using a horizontal rope. The car is in neutral gear, so we can assume that there is no appreciable friction between its tires and the highway. As the truck is accelerating to highway speeds, draw a free-body diagram of \((a)\) the car and \((b)\) the truck, (c) What force accelerates this system forward? Explain how this force originates.

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