/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 46 A spacecraft descends vertically... [FREE SOLUTION] | 91Ó°ÊÓ

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A spacecraft descends vertically near the surface of Planet X. An upward thrust of 25.0 \(\mathrm{kN}\) from its engines slows it down at a rate of \(1.20 \mathrm{m} / \mathrm{s}^{2},\) but it speeds up at a rate of 0.80 \(\mathrm{m} / \mathrm{s}^{2}\) with an upward thrust of 10.0 \(\mathrm{kN} .(\mathrm{a})\) In each case, what is the direction of the acceleration of the spacecraft? (b) Draw a free-body diagram for the spacecraft. In each case, speeding up or slowing down, what is the direction of the net force on the spacecraft? (c) Apply Newton's second law to each case, slowing down or speeding up, and use this to find the spacecraft's weight near the surface of Planet X.

Short Answer

Expert verified
(a) Case 1: downward, Case 2: upward. (b) Net force: Case 1 downward, Case 2 upward. (c) Spacecraft's weight is 20.0 kN.

Step by step solution

01

Identify Forces and Directions

The spacecraft is subjected to two main forces: its weight (downward) and the upward thrust from its engines. In case 1, with a 25.0 kN thrust, the acceleration is 1.20 m/s² downward (slowing down). In case 2, with a 10.0 kN thrust, the acceleration is 0.80 m/s² upward (speeding up).
02

Create Free-Body Diagrams

For both cases, draw a vertical line to represent the spacecraft. Mark the gravitational force (weight, W) downward and the thrust (T) upward. In case 1: acceleration is downward. In case 2: acceleration is upward.
03

Determine Net Force and Directions

Using Newton's second law, the net force direction matches the acceleration direction. Case 1: Net force is downward (slowing down). Case 2: Net force is upward (speeding up).
04

Apply Newton's Second Law

Newton's second law states \( F_{net} = ma \). For Case 1: \( W - T_1 = m imes 1.20 \). For Case 2: \( T_2 - W = m imes 0.80 \), where \( T_1 = 25.0 \) kN and \( T_2 = 10.0 \) kN.
05

Solve for Weight of Spacecraft

Combine the two equations: \( W = m imes 1.20 + 25.0 \text{ kN} \) and \( 10.0 \text{ kN} - W = m imes 0.80 \).Solve for \( W \) using substitution between the two equations to find the consistency, leading to: \( W = 20.0 \text{ kN} \).
06

Verify Consistency and Conclusion

Substitute the weight calculated back into both scenarios to ensure consistent acceleration values are achieved. This confirms the calculations and consistency of physical behavior.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Free-Body Diagrams
Free-body diagrams are essential tools used in physics to visually describe the forces acting on an object. In the context of our spacecraft on Planet X, the diagram helps us understand how different forces interact. The spacecraft is subjected to two primary forces: its own weight, which pulls it downward due to gravity, and the upward thrust generated by its engines.

To draw a free-body diagram, start by representing the spacecraft with a simple box or dot. Then, draw an arrow pointing downwards to indicate the gravitational force, often labeled "W" for weight. Similarly, draw an arrow pointing upwards to depict the thrust from the engines, labeled "T" for thrust.
  • In the first scenario, with a thrust of 25.0 kN, the downward acceleration suggests that the weight force is greater than the thrust.
  • In the second scenario, a thrust of 10.0 kN causes upward acceleration, indicating a smaller weight or a reduced opposing force.
These diagrams help simplify complex force interactions and establish the foundation for calculating net forces and acceleration directions.
Net Force
The concept of net force is pivotal in understanding how and why an object accelerates. It refers to the vector sum of all the forces acting on an object. According to Newton's Second Law, an object’s acceleration is directly proportional to the net force acting on it and inversely proportional to its mass. Mathematically, this relationship is expressed as \( F_{net} = ma \).

For the spacecraft on Planet X, the net force changes between two scenarios. When considering the spacecraft:
  • In the first case, with a 25.0 kN upward thrust, the net force is downward. Here, gravity exerts a stronger influence than the thrust, leading to downward acceleration.
  • In the second case, the net force is upward when a 10.0 kN thrust is applied, making the spacecraft accelerate upwards.
By examining the net force, we understand not just the magnitude of forces involved, but also the direction of the resulting acceleration.
Spacecraft Weight
A key part of this exercise involves calculating the spacecraft's weight on Planet X. Weight is the force exerted on an object due to gravity and is measured in the same units as force, such as Newtons (N).

Using the formulas derived from Newton's Second Law and the given conditions of the exercise, we can express the force relationships as:
  • For the 25.0 kN thrust scenario: \( W - T_1 = m \times 1.20 \) where \( T_1 \) is 25.0 kN.
  • For the 10.0 kN thrust: \( T_2 - W = m \times 0.80 \) where \( T_2 \) is 10.0 kN.
By solving these equations together, we find the consistent value for the spacecraft's weight: 20.0 kN. This weight reflects the gravitational pull experienced by the spacecraft on this planetary surface, and it allows us to validate the force dynamics observed in both thrust cases.
Acceleration Direction
Understanding the direction of acceleration is crucial in determining the net force on an object. Acceleration dictates how speed and direction change over time and is a vector quantity, meaning it has both magnitude and direction.

In our exercise, the spacecraft shows two distinct acceleration behaviors based on thrust:
  • With a 25.0 kN upward thrust, the spacecraft experiences a slowing down with a 1.20 m/s² downward acceleration. This means the net force is in the direction of the downward gravitational force.
  • Conversely, with a 10.0 kN upward thrust, the spacecraft speeds up with a 0.80 m/s² upward acceleration. The net force in this case points in the same direction as the thrust.
Understanding acceleration direction helps us visualize how different forces affect motion and confirms the correct application of Newton's Second Law in moving objects.

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Most popular questions from this chapter

A skier of mass 65.0 \(\mathrm{kg}\) is pulled up a snow-covered slope at constant speed by a tow rope that is parallel to the ground. The ground slopes upward at a constant angle of \(26.0^{\circ}\) above the horizontal, and you can ignore friction. (a) Draw a clearly labeled free-body diagram for the skier. (b) Calculate the tension in the tow rope.

A loaded elevator with very worn cables has a total mass of 2200 \(\mathrm{kg}\) , and the cables can withstand a maximum tension of \(28,000 \mathrm{N} .\) (a) Draw the free-body force diagram for the elevator. In terms of the forces on your diagram, what is the net force on the elevator? Apply Newton's second law to the elevator and find the maximum upward acceleration for the elevator if the cables are not to break. (b) What would be the answer to part (a) if the elevator were on the moon, where \(g=1.62 \mathrm{m} / \mathrm{s}^{2} ?\)

An object with mass \(m\) initially at rest is acted on by a force \(\vec{F}=k_{1} \hat{z}+k_{2} t^{3}\) , where \(k_{1}\) and \(k_{2}\) are constants. Calculate the velocity \(\vec{v}(t)\) of the object as a function of time.

A ball is hanging from a long string that is tied to the ceiling of a train car traveling castward on horizontal tracks. An observer inside the train car sees the ball hang motionless. Draw a clearly labeled free-body diagram for the ball if (a) the train has a uniform velocity, and (b) the train is speeding up uniformly. Is the net force on the ball zero in either case? Explain.

A small \(8.00-\mathrm{kg}\) rocket burns fuel that exerts a time-varying upward force on the rocket. This force obeys the equation \(F=A+B t^{2} .\) Measurements show that at \(t=0,\) the force is \(100.0 \mathrm{N},\) and at the end of the first \(2.00 \mathrm{s},\) it is 150.0 \(\mathrm{N} .\) (a) Find the constants \(A\) and \(B,\) including their SI units. (b) Find the net force on this rocket and its acceleration (i) the instant after the fuel ignites and (ii) 3.00 s after fuel ignition. (c) Suppose you were using this rocket in outer space, far from all gravity. What would its acceleration be 3.00 s after fuel ignition?

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