/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 30 A large box containing your new ... [FREE SOLUTION] | 91Ó°ÊÓ

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A large box containing your new computer sits on the bed of your pickup truck. You are stopped at a red light. The light turns green and you stomp on the gas and the truck accelerates. To your horror, the box starts to slide toward the back of the truck. Draw clearly labeled free-body diagrams for the truck and for the box. Indicate pairs of forces, if any, that are third-law action- reaction pairs. (The bed of the truck is not frictionless.)

Short Answer

Expert verified
Draw two free-body diagrams with labeled forces; indicate action-reaction pairs like friction between the box and truck bed.

Step by step solution

01

Understand the Scenario

In this situation, the truck is stationary at a red light, and when the light turns green, the truck accelerates forward. The computer box, initially at rest on the bed of the truck, begins to slide backward due to inertia. Identify which forces act on the truck and the box.
02

Identify the Forces Acting on the Truck

For the truck, identify the following forces: the force of gravity acting downward on it, the normal force exerted by the ground acting upward, the force of friction between the truck's tires and the road enabling the truck to accelerate forward, and air resistance acting against the motion.
03

Draw the Truck's Free-Body Diagram

Draw a diagram of the truck. Label the downward arrow as 'Force of Gravity on Truck' (\( F_{gT} \)), the upward arrow as 'Normal Force by Ground' (\( N_T \)), the forward arrow as 'Friction Force by Road' (\( f_{T} \)), and the backward arrow as 'Air Resistance' (\( R_T \)). Indicate the direction of acceleration which is forward.
04

Identify the Forces Acting on the Box

For the box, determine the relevant forces: the gravitational force acting downward, the normal force exerted by the truck bed acting upward, the static friction force acting forward as the truck accelerates, and the backward force due to sliding (kinetic friction) if the box moves.
05

Draw the Box's Free-Body Diagram

Draw a diagram of the box. Label the downward arrow as 'Force of Gravity on Box' (\( F_{gB} \)), the upward arrow as 'Normal Force by Truck Bed' (\( N_B \)), and the forward arrow (acting on the box) as 'Static Friction Force' (\( f_{sB} \)) to represent the truck bed pushing forward on the box. Indicate a backward force if sliding occurs.
06

Identify Third-Law Force Pairs

According to Newton's third law, the gravitational force on the truck and the normal force by the ground form an action-reaction pair. Similarly, the force of static friction on the box by the truck bed and the equal opposite force of the box on the truck as they contact form another pair, though not mutually canceling since one acts on the box and one on the truck.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Newton's Third Law
Newton's Third Law states that for every action, there is an equal and opposite reaction. This fundamental principle of physics means that forces always come in pairs. In our example, the action-reaction pairs can be seen within the system of the truck and the box.
When the truck applies a force on the road through its tires, the road applies an equal and opposite force back on the truck. This force propels the truck forward. Additionally, as the truck bed pushes on the box with static friction to move it forward, the box pushes back on the truck bed with an equal and opposite force. These interactions illustrate Newton's Third Law in action.

It's important to emphasize that while these forces are equal in magnitude and opposite in direction, they do not cancel out because they act on different objects. This is why the truck moves forward while the box tends to slide backward, further illustrating inertia which is the box’s tendency to stay at rest as the truck moves.
forces and motion
Forces are vectors, which means they have both magnitude and direction. In the context of the truck and box scenario, we need to understand several key forces at play to fully grasp the motion involved.
One primary force acting on the truck is friction. The force of friction between the truck's tires and the road enables the truck to accelerate forward when you press the gas pedal. Meanwhile, a force of air resistance acts in the opposite direction, trying to hinder the truck's motion.
For the box on the truck, while at rest, it remains under the influence of static friction, which is the initial resistant force between the truck bed and the box. When the truck accelerates rapidly, inertia causes the box to appear to move backward, even as static friction attempts to prevent this motion. If the force of static friction is overcome, kinetic friction comes into play, causing the box to slide as you observed.
Understanding these forces helps explain why the motion of the truck and box changes when the light turns green, combining the factors of useful friction aiding movement, and resisting forces altering expected paths.
friction forces
Friction is critical in real-world applications, preventing slipping and enabling controlled motion. There are two main types of friction involved in our truck scenario: static friction and kinetic friction.
Static friction occurs when the box is at rest relative to the truck bed. It is this force that initially tries to "stick" the box to the truck as it accelerates. The strength of static friction depends on the surface materials and the normal force—the force that acts perpendicular to the surfaces in contact.
When static friction is exceeded by an applied force (such as the truck's rapid acceleration), kinetic friction takes over. Kinetic friction is usually less than static friction and acts against the direction of motion, which is why the box begins to slide backward in the truck.
Understanding the role of these friction forces is essential in predicting and controlling motion within systems like vehicles transporting cargo. Knowing how forces interact at various thresholds ensures stability and helps in designing safety features to prevent unwanted sliding of loads.

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Most popular questions from this chapter

You have just landed on Planet \(X\) . You take out a 100 -g ball, release it from rest from a height of \(10.0 \mathrm{m},\) and measure that it takes 2.2 \(\mathrm{s}\) to reach the ground. You can ignore any force on the ball from the atmosphere of the planet. How much does the \(100-\mathrm{g}\) ball weigh on the surface of Planet \(\mathrm{X}\) ?

If we know \(F(t),\) the force as a function of time, for straight-line motion, Newton's second law gives us \(a(t),\) the acceleration as a function of time. We can then integrate \(a(t)\) to find \(v(t)\) and \(x(t)\) . However, suppose we know \(F(v)\) instead. (a) The net force on a body moving along the \(x\) -axis equals \(-C v^{2} .\) Use Newton's second law written as \(\Sigma F=m d v / d t\) and two integrations to show that \(x-x_{0}=(m / C) \ln \left(v_{0} / v\right) .\) (b) Show that Newton's second law can be written as \(\Sigma F=m v d v / d x .\) Derive the same expression as in part (a) using this form of the second law and one integration.

Jumping to the Ground. A 75.0 -kg man steps off a platform 3.10 \(\mathrm{m}\) above the ground. He keeps his legs straight as he falls, but at the moment his feet touch the ground his knees begin to bend, and, treated as a particle, he moves an additional 0.60 \(\mathrm{m}\) before coming to rest. (a) What is his speed at the instant his feet touch the ground? (b) Treating him as a particle, what is his acceleration (magnitude and direction) as he slows down, if the acceleration is assumed to be constant? (c) Draw his free-body diagram (see Section 4.6 ). In terms of the forces on the diagram, what is the net force on him? Use Newton's laws and the results of part \((b)\) to calculate the average force his feet exert on the ground while he slows down. Express this force in newtons and also as a multiple of his weight.

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