/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 9 Light traveling in air is incide... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Light traveling in air is incident on the surface of a block of plastic at an angle of \(62.7^{\circ}\) to the normal and is bent so that it makes a \(48.1^{\circ}\) angle with the normal in the plastic. Find the speed of light in the plastic.

Short Answer

Expert verified
The speed of light in the plastic is approximately \( 2.13 \times 10^8 \) m/s.

Step by step solution

01

Understand the Problem

The problem describes light traveling from air into a plastic medium, changing angles due to refraction. We need to find the speed of light in the plastic.
02

Apply Snell's Law

Snell's Law relates the angles and speeds of light in different media using the formula: \( n_1 \sin \theta_1 = n_2 \sin \theta_2 \). Here, \( n_1 \) and \( n_2 \) are the indices of refraction of air and plastic, respectively, and \( \theta_1 \) and \( \theta_2 \) are the angles with the normal.
03

Use Index of Refraction for Air

The index of refraction for air is approximately 1. Therefore, \( n_1 = 1 \) and \( \sin \theta_1 = \sin 62.7^{\circ} \).
04

Calculate Index of Refraction for Plastic

Rearrange Snell's Law to find \( n_2 \): \( n_2 = \frac{n_1 \sin \theta_1}{\sin \theta_2} = \frac{1 \cdot \sin 62.7^{\circ}}{\sin 48.1^{\circ}} \). Calculate the values to find \( n_2 \).
05

Calculate Speed of Light in the Plastic

The speed of light in a medium is calculated using \( v = \frac{c}{n_2} \), where \( c = 3 \times 10^8 \) m/s is the speed of light in a vacuum and \( n_2 \) is the index of refraction of the plastic. Use \( n_2 \) from Step 4 to find the speed.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Refraction
Refraction is the bending of light as it travels from one medium to another, changing its speed in the process. When light crosses the boundary between two different substances, such as air to plastic, it changes direction based on the relative densities of the two materials. This bending occurs because light travels at different speeds in different materials. Understanding refraction is crucial in optics and is widely applied in designing lenses, glasses, and various optical instruments.

The core principle governing refraction is Snell's Law, which quantifies how much light will bend. This law tells us that:
  • When light travels from a less dense medium (like air) to a denser medium (like plastic), it bends towards the normal.
  • Conversely, moving from a denser to a less dense medium, light bends away from the normal line.
Refraction not only makes objects submerged in water appear bent or at different depths than they really are but is also responsible for various optical phenomena such as mirages. Fully grasping refraction helps in understanding how Snell's Law applies practically in various scientific and technological contexts.
Speed of Light
The speed of light is one of the fundamental constants of nature and is crucial for understanding refraction and how light behaves in different media. In a vacuum, light travels at the ultimate speed limit of approximately 299,792,458 meters per second, or simply, about 3 x 10^8 m/s. This high speed decreases when light travels through any material, such as air, water, or plastic.

The reduction in the speed of light when it passes through a material is due to the interaction of light with the atoms in the medium. The decreased speed of light in various substances is what causes refraction to occur. When using Snell's Law, the speed of light is an important factor as it directly affects the refraction index. The speed of light in a medium is given by the formula:\[ v = \frac{c}{n} \]Here, \( v \) is the speed of light in the medium, \( c \) is the speed of light in a vacuum, and \( n \) is the index of refraction. This equation shows that the speed of light in any medium can be calculated if the index of refraction is known. Thus, the speed of light is a pivotal concept in understanding how light will behave when it encounters different substances.
Index of Refraction
The index of refraction, often denoted by \( n \), is a measure of how much light slows down when it enters a material. Each material has a specific index of refraction which indicates how much it will bend a ray of light. The index is defined as the ratio of the speed of light in a vacuum to the speed of light in the material:\[ n = \frac{c}{v} \]In this formula, \( c \) is the speed of light in a vacuum, and \( v \) is the speed of light in the material.

A higher index means that light will slow down more in that material. For example, the index of refraction for air is about 1.0003, while for plastic, it is typically between 1.3 and 1.6. This indicates that light travels slower in plastic than in air, resulting in more significant bending of light rays.

Understanding the index of refraction is key for predicting how much light will refract when transitioning between materials. It is widely used in lens-making and fiber optics to ensure correct focusing and transmission of light. Calculating the index of refraction using Snell's Law allows one to anticipate and design optical applications with precision.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Light traveling in water strikes a glass plate at an angle of incidence of \(53.0^{\circ}\) : part of the beam is reflected and part is refracted. If the refiected and refracted portions make an angle of \(90.0^{\circ}\) with each other, what is the index of refraction of the glass?

A beam of polarized light passes through a polarizing filter. When the angle between the polarizing axis of the filter and the direction of polarization of the light is \(\theta,\) the intensity of the emerging beam is \(I .\) If you now want the intensity to be \(I / 2\) , what should be the angle (in terms of \(\theta )\) between the polarizing angle of the filter and the original direction of polarization of the light?

A glass plate 2.50 \(\mathrm{mm}\) thick, with an index of refraction of \(1.40,\) is placed between a point source of light with wavelength 540 \(\mathrm{nm}\) (in vacuum) and a screen. The distance from source to screen is 1.80 \(\mathrm{cm}\) . How many wavelengths are there between the source and the screen?

A beaker with a mirrored bottom is filled with a liquid whose index of refraction is \(1.63 .\) A light beam strikes the top surface of the liquid at an angle of \(42.5^{\circ}\) from the normal. At what angle from the normal will the beam exit from the liquid after traveling down through the liquid, reflecting from the mirrored bottom, and returning to the surface?

Using a fast-pulsed laser and electronic timing circuitry, you find that light travels 2.50 \(\mathrm{m}\) within a plastic rod in 11.5 \(\mathrm{ns}\) . What is the refractive index of the plastic?

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.