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A beam of polarized light passes through a polarizing filter. When the angle between the polarizing axis of the filter and the direction of polarization of the light is \(\theta,\) the intensity of the emerging beam is \(I .\) If you now want the intensity to be \(I / 2\) , what should be the angle (in terms of \(\theta )\) between the polarizing angle of the filter and the original direction of polarization of the light?

Short Answer

Expert verified
The angle should be \(45^\circ\) or \(135^\circ\).

Step by step solution

01

Understand Malus's Law

Malus's Law states that the intensity of polarized light passing through a polarizing filter is given by the equation \( I = I_0 \cos^2(\theta) \), where \( I_0 \) is the initial light intensity and \( \theta \) is the angle between the light's initial polarization direction and the polarizing axis of the filter.
02

Set up the equation for the desired intensity

We want the intensity to be \( I/2 \). We can express this using Malus's Law: \( \frac{I_0}{2} = I_0 \cos^2(\theta') \), where \( \theta' \) is the new angle we need to find. Notice that \( \cos^2(\theta') = \frac{1}{2} \).
03

Solve for \( \theta' \)

To solve \( \cos^2(\theta') = \frac{1}{2} \), take the square root of both sides to find \( \cos(\theta') = \pm \frac{1}{\sqrt{2}} \). Simplifying gives \( \cos(\theta') = \pm \frac{\sqrt{2}}{2} \).
04

Determine the angle values

The standard angles where \( \cos(\theta') = \frac{\sqrt{2}}{2} \) are \( \theta' = 45^\circ \) and \( \theta' = 315^\circ \). Since we are considering positive angles within a range often restricted to \( 0^\circ \) to \( 180^\circ \), we select \( \theta' = 45^\circ \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Malus's Law
Malus's Law is a key principle in optics that explains how light behaves when it passes through a polarizing filter. This law is named after the French physicist Étienne-Louis Malus who formulated this relationship. According to Malus’s Law, the intensity of polarized light after passing through a polarizing filter is determined by the equation \( I = I_0 \cos^2(\theta) \). Here, \( I_0 \) represents the initial intensity of the light, and \( \theta \) is the angle between the direction of the light's polarization and the axis of the filter.
Malus's Law helps us understand how the light intensity changes based on the angle \( \theta \). The cosine function, \( \cos^2(\theta) \), describes how light intensity decreases as the angle increases. This equation is crucial when dealing with problems involving polarized light, helping us predict and calculate the resulting intensity under various conditions.
  • The intensity is maximized when the angle \( \theta = 0^\circ \), meaning the light is perfectly aligned with the filter.
  • Intensity is minimized or zero when \( \theta = 90^\circ \), where the light is perpendicular to the filter.
Understanding the mathematical foundation laid by Malus's Law allows for accurate manipulation of light in numerous scientific and practical applications.
Polarizing Filter
A polarizing filter is a device used to alter the polarization state of light passing through it. It is often used in photography and scientific instruments to manage light intensity and reduce glare. When unpolarized light hits a polarizing filter, only the light waves aligned with the filter's axis emerge from the other side. This filtered light is then polarized.
The filter works by allowing only certain vibrations of the light waves to pass through, effectively reducing unwanted light and enhancing clarity. Suppose you rotate a polarizing filter in the path of polarized light, the intensity of the light changes according to the angle of rotation. This is where Malus's Law comes into play, as it provides a mathematical basis for predicting these intensity changes.
  • Polarizing filters in cameras can help reduce reflections and improve color saturation.
  • In scientific studies, they are crucial for experiments involving light behavior and electromagnetic waves.
Understanding how polarizing filters work helps in the effective management of light in both artistic and scientific contexts.
Light Intensity
Light intensity refers to the energy carried by light per unit area, and it is often perceived as brightness. It is a key factor in various fields like physics, photography, and ophthalmology. In the context of polarized light, the intensity is crucial in determining how much light emerges after passing through a filter.
When a beam of polarized light travels through a polarizing filter, the intensity outcome relies heavily on the angle between the filter and the light's original polarization direction. Using Malus’s Law gives us the equation \( I = I_0 \cos^2(\theta) \), which predicts the emerging light intensity. Solving this equation allows us to determine the angle necessary for achieving a desired light intensity, such as in the problem where it needs to be reduced by half.
  • Greater alignment between the filter and light direction results in higher intensity.
  • Partial misalignment decreases the intensity, based on cosine squared of the angle.
Understanding light intensity and its dependencies help in efficiently controlling light environments, whether in complex experiments or daily applications like photography.

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Most popular questions from this chapter

Three Polarizing filters. Three polarizing filters are stacked with the polarizing axes of the second and third at \(45.0^{\circ}\) and \(90.0^{\circ}\) , respectively, with that of the first. (a) If unpolarized light of intensity \(I_{0}\) is incident on the stack, find the intensity and state of polarization of light emerging from each filter \((b)\) If the second filter is removed, what is the intensity of the light emerging from each remaining filter?

A ray of light is incident on a plane surface separating two sheets of glass with refractive indexes 1.70 and 1.58 . The angle of incidence is \(62.0^{\circ}\) , and the ray originates in the glass with \(n=1.70 .\) Compute the angle of refraction.

(a) Light passes through three parallel slabs of different thicknesses and refractive indexes. The light is incident in the first slab and finally refracts into the third slab. Show that the middle slab has no effect on the final direction of the light. That is, show that the direction of the light in the third slab is the same as if the light had passed directly from the first slab into the third slab. Generalize this result to a stack of \(N\) slabs. What determines the final direction of the light in the last slab?

Three polarizing filters are stacked, with the polarizing axis of the second and third filters at \(23.0^{\circ}\) and 62.0 ' respectively, to that of the first. If unpolarized light is incident on the stack, the light has intensity 75.0 \(\mathrm{W} / \mathrm{cm}^{2}\) after it passes through the stack. If the incident intensity is kept constant, what is the intensity of the light after it has passed through the stack if the second polarizer is removed?

Bending Around Corners. Traveling particles do not bend around corners, but waves do. To see why, suppose that a plane wave front strikes the edge of a sharp object traveling perpendicular to the surface (Fig. 33.44\()\) . Use Huygens's principle to show that this wave will bend around the upper edge of the object. (Note: This effect, called diffraction, can easily be seen for water waves, but it also occurs for light, as you will see in Chapters 35 and 36 . However due to the very short wavelength of visible light, it is not so apparent in daily life.)

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