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31.41. A coil has a resistance of 48.0\(\Omega\) . At a frequency of 80.0 \(\mathrm{Hz}\) the voltage across the coil leads the current in it by \(52.3^{\circ} .\) Determine the inductance of the coil.

Short Answer

Expert verified
Inductance \(L\) is determined to be 99.7 mH.

Step by step solution

01

Understanding Impedance in AC Circuits

In an AC circuit, the voltage can lead or lag the current due to the presence of inductance or capacitance. The impedance in an AC circuit is a complex quantity that has both a real part (resistance \(R\)) and an imaginary part (reactance \(X\)). For inductance \(L\), the reactance is \(X_L = 2\pi f L\), where \(f\) is the frequency of the AC supply.
02

Calculating the Total Impedance

We know that the voltage leads the current by an angle of \(\theta = 52.3^\circ\). In terms of impedance \(Z\), we can use the tangent of the phase angle: \(\tan(\theta) = \frac{X_L}{R}\). Substitute the given values \(\theta = 52.3^\circ\) and \(R = 48.0\,\Omega\) into this formula.
03

Solving for Inductive Reactance

Calculate \(X_L\) using the formula \(X_L = R \times \tan(\theta)\). First, convert \(\theta\) from degrees to radians: \(\theta = 52.3^\circ \times \frac{\pi}{180}\). Then compute \(X_L = 48.0 \times \tan(52.3^\circ)\).
04

Calculating Inductance

Use the formula \(X_L = 2\pi f L\) to find the inductance \(L\). Rearrange it to \(L = \frac{X_L}{2\pi f}\). Substitute the computed \(X_L\) and the given frequency \(f = 80.0\,\text{Hz}\) into this formula to find \(L\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Impedance
Impedance is a fundamental concept when dealing with AC circuits. It represents the total opposition that a circuit presents to the flow of alternating current. Unlike resistance, which only accounts for resistors and is measured in ohms (\(\Omega\)), impedance combines the effects of resistors, capacitors, and inductors. It is represented as a complex number \(Z\), defined as \(Z = R + jX\), where \(R\) is the real part (resistance) and \(X\) is the imaginary part (reactance).

  • Resistance \(R\): Always opposes current, unchanged by frequency.
  • Reactance \(X\): Varies with frequency, capable of leading or lagging the current relative to the voltage.
In the context of AC circuits, impedance is crucial for analyzing how voltage and current behave across different components. Typically, if the circuit comprises inductors, capacitors, or both, the phase difference between current and voltage arises, characterized by an angle \(\theta\). This angle signifies how much the current is leading or lagging the voltage. By examining impedance, we gain valuable insight into the "health" and efficiency of AC systems.
Inductive Reactance
Inductive reactance \(X_L\) is a measure of the opposition that an inductor presents to the AC current. It specifically arises from the inductor's ability to store energy in the magnetic field produced by the current flowing through it. This causes a phase shift in the AC circuit.Inductive reactance is calculated using the formula:\[ X_L = 2\pi f L \]Here, \(f\) represents the frequency of the AC supply, and \(L\) denotes the inductance of the coil.
  • Higher frequency results in greater inductive reactance.
  • An increase in inductance \(L\) will also increase \(X_L\).
Inductive reactance is responsible for the voltage leading the current by an angle \(\theta\). This phase difference can be computed using the tangent function: \(\tan(\theta) = \frac{X_L}{R}\), where \(R\) is the resistance of the coil in the circuit.

Understanding inductive reactance is vital when working with AC circuits, as it affects how electrical energy is stored and transferred, impacting the circuit's performance.
Frequency in AC Circuits
Frequency is a defining characteristic of AC (alternating current) circuits. It refers to the number of cycles of the alternating current that occur per second, measured in hertz (Hz). The frequency impacts various properties of the circuit components, especially inductors and capacitors.

  • Increased frequency raises inductive reactance \(X_L\), which increases impedance and thus affects the circuit's current flow.
  • Conversely, for capacitors, an increased frequency decreases capacitive reactance.
In the case of the exercise, the frequency was set at 80.0 Hz. This frequency dictates how much the coil's inductive reactance (hence impedance) impacts the current flow and phase angle. As frequency changes, it affects energy transfer within the circuit, shaping interactions between voltage and current.
In practical applications, engineers must choose the frequency wisely since different electronic components respond differently based on their inherent reactive characteristics. Frequency selection can optimize circuit performance for a specific application, ensuring desired outcomes.

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Most popular questions from this chapter

31.37. A Step-Down Transformer. A transformer connected to a \(120-\mathrm{V}(\mathrm{rms})\) ac line is to supply 12.0 \(\mathrm{V}\) (mns) to a portable electronic device. The load resistance in the secondary is 5.00\(\Omega\) (a) What should the ratio of primary to secondary turns of the transformer be? (b) What rms current must the secondary supply? (c) What average power is delivered to the load? (d) What resistance connected directly across the \(120-\mathrm{V}\) line would draw the same power as the transformer? Show that this is equal to 5.00\(\Omega\) times the square of the ratio of primary to secondary turns.

31.66. A transformer consists of 275 primary windings and 834 secondary windings. If the potential difference across the primary coil is \(25.0 \mathrm{V},\) (a) what is the voltage across the secondary coil, and (b) what is the effective load resistance nf the secondary coil if it is connected across a \(125-\Omega\) resistor?

31.65. An inductor, a capacitor, and a resistor are all connected in series across an ac source. If the resistance, inductance, and capacitance are all doubled, by what factor does each of the following quantities change? Indicate whether they increase or decrease: (a) the resonance angular frequency; (b) the inductive reactance; (c) the capacitive reactance. (d) Does the impedance double?

31.45. A series circuit has an impedance of 60.0\(\Omega\) and a power factor of 0.720 at 50.0 \(\mathrm{Hz}\) . The source voltage lags the current. (a) What circuit element, an inductor or a capacitor, should be placed in series with the circuit to raise its power factor? (b) What size element will raise the power factor to unity?

31.62. A series circuit consists of a \(1.50-\mathrm{mH}\) inductor, a \(125-\Omega\) resistor, and a \(25.0-\mathrm{nF}\) capacitor connected across an ac source having an rms voltage of 35.0 \(\mathrm{V}\) and variable frequency. (a) At what angular frequency will the current amplitude be equal to \(\frac{1}{3}\) of its maximum possible value? (b) At the frequency in part (a) what are the current amplitude and the voltage amplitude across each of the circuit elements (including the ac source)?

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