/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 65 31.65. An inductor, a capacitor,... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

31.65. An inductor, a capacitor, and a resistor are all connected in series across an ac source. If the resistance, inductance, and capacitance are all doubled, by what factor does each of the following quantities change? Indicate whether they increase or decrease: (a) the resonance angular frequency; (b) the inductive reactance; (c) the capacitive reactance. (d) Does the impedance double?

Short Answer

Expert verified
(a) Decreases by factor of 2 (b) Increases by factor of 2 (c) Decreases by factor of 2 (d) Impedance doubles

Step by step solution

01

Understanding Resonance Angular Frequency

The resonance angular frequency \( \omega_0 \) for an LCR circuit is given by the formula \( \omega_0 = \frac{1}{\sqrt{LC}} \). When the inductance \( L \) and the capacitance \( C \) are both doubled, the new resonance angular frequency becomes \( \omega_0' = \frac{1}{\sqrt{2L \times 2C}} = \frac{1}{2} \times \omega_0 \). Thus, the resonance angular frequency decreases by a factor of 2.
02

Calculating the Inductive Reactance

Inductive reactance \( X_L \) is calculated using the formula \( X_L = \omega L \), where \( \omega \) is the angular frequency of the AC source. Doubling the inductance \( L \) results in a new inductive reactance \( X_L' = \omega (2L) = 2\omega L = 2X_L \). Therefore, the inductive reactance increases by a factor of 2.
03

Determining the Capacitive Reactance

The capacitive reactance \( X_C \) is given by \( X_C = \frac{1}{\omega C} \). Upon doubling the capacitance \( C \), the capacitive reactance becomes \( X_C' = \frac{1}{\omega (2C)} = \frac{1}{2} \times \frac{1}{\omega C} = \frac{1}{2} X_C \). Hence, the capacitive reactance decreases by a factor of 2.
04

Evaluating the Impedance

The impedance \( Z \) of the circuit at resonance is \( Z = R \). After doubling the resistance \( R \), inductance \( L \), and capacitance \( C \), the total impedance becomes \( Z' = 2R \text{ at resonance because we assume resonance condition for comparison of impedance.} \) Consequently, the impedance also doubles. Thus, the impedance increases by a factor of 2.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Resonance Angular Frequency
In an LCR circuit, the resonance angular frequency is a crucial concept. It determines the frequency at which the circuit naturally oscillates with maximum amplitude. This frequency, represented by \( \omega_0 \), can be calculated using the formula \( \omega_0 = \frac{1}{\sqrt{LC}} \). As seen, both the inductance \( L \) and the capacitance \( C \) play an integral role.

When both these quantities are doubled, the formula becomes \( \omega_0' = \frac{1}{\sqrt{2L \times 2C}} \). Simplifying, we find \( \omega_0' = \frac{1}{2} \times \omega_0 \). This means that the resonance angular frequency decreases by a factor of 2. The decrease makes it crucial for engineers to adjust other circuit parameters when designing systems that operate at specific frequencies.
  • Resonance creates optimal conditions for maximum energy transfer.
  • Affects the design and functionality of the circuit.
  • Necessary to consider changes in \( L \) and \( C \) for system efficiency.
Inductive Reactance
Inductive reactance is another vital concept in the analysis of LCR circuits. It measures how the inductor resists changes in current and is calculated by the formula \( X_L = \omega L \), with \( \omega \) symbolizing the angular frequency. Importantly, the inductive reactance depends directly on both the frequency and the inductance.

When the inductance \( L \) is doubled, the reactance becomes \( X_L' = \omega (2L) = 2X_L \). Thus, the inductive reactance increases by a factor of 2. This rise in reactance implies a greater opposition to current changes, which can affect the current's phase and amplitude within the circuit. As such, doubling inductance changes how energy is stored and released.
  • Influences the timing of current changes within the circuit.
  • Important in tuning circuits to specific frequencies.
  • Directly proportional to both frequency and inductance.
Capacitive Reactance
Capacitive reactance is the counterpart to inductive reactance within an LCR circuit. It measures the opposition a capacitor presents to a change in voltage. The formula used is \( X_C = \frac{1}{\omega C} \), demonstrating the inverse relationship with frequency \( \omega \) and capacitance \( C \).

Upon doubling the capacitance, the capacitive reactance adjusts to \( X_C' = \frac{1}{\omega (2C)} = \frac{1}{2}X_C \). This means the capacitive reactance decreases by a factor of 2, allowing easier voltage changes. The inverse relationship highlights how increased capacitance reduces opposition to voltage shifts, making it significant in circuits focusing on voltage control.
  • Decreases with increased capacitance and frequency.
  • Critical in controlling voltage and phase in AC circuits.
  • Impacts the circuit's voltage characteristics during operation.
Impedance in Circuits
Impedance combines both resistance and reactance, offering a complete picture of how an AC circuit resists current. It is typically represented by \( Z \) and at resonance, where frequency effects are balanced, it simplifies to \( Z = R \). At this point, impedance solely depends on the resistance \( R \).

When resistance \( R \), inductance \( L \), and capacitance \( C \) are all doubled, the impedance becomes \( Z' = 2R \) during resonance. Therefore, impedance increases by a factor of 2. Doubling these parameters underlines the reliance of impedance on total circuit characteristics, beyond just simple resistance or reactance measures.
  • Combines resistive effects with reactive properties.
  • Requires balance to achieve desired circuit performance.
  • Changes to impedance affect power consumption and distribution.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

31.11. Kitchen Capacitance. The wiring for a refrigerator contains a starter capacitor. A voltage of amplitude 170 \(\mathrm{V}\) and frequency 60.0 \(\mathrm{Hz}\) applied across the capacitor is to produce a current amplitude of 0.850 A through the capacitor. What capacitance \(C\) is required?

31\. 27. (a) Show that for an \(L-R-C\) series circuit the power factor is equal to \(R / Z\) . (Hint: Use the phasor diagram; see Fig. \(31.13 b . )\) (b) Show that for any ac circuit, not just one containing pure resistance only, the average power delivered by the voltage source is given by \(P_{\mathrm{av}}=I_{\mathrm{rms}}^{2} R\)

31.23. In an \(L-R-C\) series circuit, the rms voltage across the resistor is 30.0 \(\mathrm{V}\) , across the capacitor it is 90.0 \(\mathrm{V}\) , and across the inductor it is 50.0 \(\mathrm{V}\) . What is the rms voltage of the source?

31.13. A \(150-\Omega\) resistor is connected in series with a \(0.250-\mathrm{H}\) inductor. The voltage across the resistor is \(v_{R}=(3.80 \mathrm{V}) \cos [(720 \mathrm{rad} / \mathrm{s}) t]\) (a) Derive an expression for the circuit current. (b) Determine the inductive reactance of the inductor. (c) Derive an expression for the voltage \(v_{L}\) across the inductor.

31.6. A capacitance \(C\) and an inductance \(L\) are operated at the same angular frequency. (a) At what angular frequency will they have the same reactance? (b) If \(L=5.00 \mathrm{mH}\) and \(C=3.50 \mu \mathrm{F}\) , what is the numerical value of the angular frequency in part (a), and what is the reactance of each element?

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.