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The density of water is 999.73 \(\mathrm{kg} / \mathrm{m}^{3}\) at a temperature of \(10^{\circ} \mathrm{C}\) and 958.38 \(\mathrm{kg} / \mathrm{m}^{3}\) at a temperature of \(100^{\circ} \mathrm{C} .\) Calculate the average coefficient of volume expansion for water in that range of temperature.

Short Answer

Expert verified
The average coefficient of volume expansion for water is approximately \( 2.07 \times 10^{-4} \, \mathrm{°C}^{-1} \).

Step by step solution

01

Understand the Formula for Volume Expansion

The formula for average volume expansion is given by \( \beta = \frac{\Delta V}{V_0 \times \Delta T} \), where \( \beta \) is the average coefficient of volume expansion, \( \Delta V \) is the change in volume, \( V_0 \) is the initial volume, and \( \Delta T \) is the change in temperature.
02

Understand the Relationship Between Volume and Density

The volume \( V \) is inversely proportional to the density \( \rho \), i.e., \( V = \frac{m}{\rho} \), where \( m \) is the mass of water. For unit mass, the volume is simply the reciprocal of the density \( V = \frac{1}{\rho} \).
03

Calculate Initial and Final Volume

For the initial temperature \( 10^{\circ} \mathrm{C} \), \( V_0 = \frac{1}{999.73} \, \mathrm{m}^3/\mathrm{kg} \). For \( 100^{\circ} \mathrm{C} \), \( V_f = \frac{1}{958.38} \, \mathrm{m}^3/\mathrm{kg} \).
04

Calculate Change in Volume

Find \( \Delta V = V_f - V_0 = \frac{1}{958.38} - \frac{1}{999.73} \). Calculate this value to find \( \Delta V \).
05

Calculate Change in Temperature

The change in temperature is given by \( \Delta T = 100^{\circ} \mathrm{C} - 10^{\circ} \mathrm{C} = 90^{\circ} \mathrm{C} \).
06

Substitute Values into Volume Expansion Formula

Substitute the values from steps 3, 4, and 5 into the formula: \( \beta = \frac{\Delta V}{V_0 \times \Delta T} = \frac{\left(\frac{1}{958.38} - \frac{1}{999.73}\right)}{\frac{1}{999.73} \times 90} \).
07

Compute the Coefficient

Perform the arithmetic computations to find \( \beta \). The final value will be the average coefficient of volume expansion over the given temperature range.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Density of Water
Density is a property that defines the mass per unit volume of a substance. For water, this density can change with temperature. At 10°C, water has a density of 999.73 kg/m³, and at 100°C, it becomes 958.38 kg/m³. As a liquid heats up, it usually expands, causing its density to decrease if the mass remains constant. Understanding the density changes with temperature helps us in calculating the thermal expansion, which is crucial for accurate thermal expansion calculations. This density-temperature relationship is particularly important in natural and engineering systems where precise measurements are vital. In systems where fluid density plays a critical role, such as climate modeling or engineering applications, acknowledging and accounting for these shifts ensures accuracy.
Volume-Temperature Relationship
The relationship between volume and temperature is fundamental to understanding thermal expansion. As temperature increases, most substances expand and their volume increases. For water, the volume at any given temperature can be calculated using the formula:
  • \( V = \frac{1}{\rho} \)
This equation shows that volume is inversely proportional to density. So, as the density of water decreases with an increase in temperature, it results in an increase in volume.This principle helps us calculate changes in volume when the temperature changes, which is essential for determining the coefficient of volume expansion. Knowing how volume changes with temperature allows us to anticipate and design for expansion in various scientific and industrial contexts.
Thermal Expansion Calculations
To calculate how much a substance's volume will change with temperature, we use the thermal expansion coefficient. This is where the formula comes into play:
  • \( \beta = \frac{\Delta V}{V_0 \times \Delta T} \)
Here, \( \Delta V \) is the change in volume, \( V_0 \) is the initial volume, and \( \Delta T \) is the change in temperature. Using this formula, we can derive \( \beta \), which represents the average coefficient of volume expansion. For the water example, \( \beta \) is calculated over a temperature change from 10°C to 100°C.Performing these calculations allows us to predict how much water will expand when heated. Such predictions are crucial for designing containers and systems that need to handle temperature changes without failure or leakage. Understanding thermal expansion calculations ensures safety and functionality in various applications.

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Most popular questions from this chapter

The Sizes of Stars. The hot glowing surfaces of stars emit energy in the form of electromagnetic radiation. It is a good approximation to assume \(e=1\) for these surfaces. Find the radii of the following stars (assumed to be spherical): (a) Rigel, the bright blue star in the constellation Orion, which radiates energy at a rate of \(2.7 \times 10^{32} \mathrm{W}\) and has surface temperature \(11,000 \mathrm{K} ;\) (b) Procyon \(\mathrm{B}\) (visible only using a telescope), which radiates energy at a rate of \(2.1 \times 10^{23} \mathrm{W}\) and has surface temperature \(10,000 \mathrm{K}\) . (c) Compare your answers to the radius of the earth, the radius of the sun, and the distance between the earth and the sun. (Rigel is an example of a supergiant star, and Procyon \(\mathrm{B}\) is an example of a white dwarf star.)

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(a) You feel sick and are told that you have a temperature of \(40.2^{\circ} \mathrm{C}\) . What is your temperature in "F? Should you be concerned? (b) The morning weather report in Sydney gives a current temperature of \(12^{\circ} \mathrm{C}\) . What is this temperature in \(^{\circ} \mathrm{F} ?\)

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