/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 110 A wood ceiling with thermal resi... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

A wood ceiling with thermal resistance \(R_{1}\) is covered with a layer of insulation with thermal resistance \(R_{2} .\) Prove that the effective thermal resistance of the combination is \(R=R_{1}+R_{2}\) .

Short Answer

Expert verified
The effective thermal resistance of two layers in series is \(R = R_1 + R_2\).

Step by step solution

01

Understand Thermal Resistance

Thermal resistance is a measure of a material's ability to resist the flow of heat. It is analogous to electrical resistance in circuits, where higher resistance means less heat flow. The unit for thermal resistance is Kelvin per Watt (K/W).
02

Identify Components and Setup

The problem involves two layers: a wood ceiling and an insulating layer. Each layer has its own thermal resistance, denoted as \(R_1\) for the wood and \(R_2\) for the insulation.
03

Add Resistances in Series

When thermal resistances are in series, like our two layers, the total resistance \(R\) is found by summing the individual resistances. Thus, the formula for the effective thermal resistance is given by \(R = R_1 + R_2\).
04

Derivation and Explanation

By considering the heat flow through each layer, the temperature drop across the entire assembly is the sum of the temperature drops across each layer due to their resistances. Therefore, \(R = R_1 + R_2\) gives an effective total resistance, maintaining the analogy to resistors in an electrical circuit.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Heat Flow
Heat flow is the movement of thermal energy from an area of higher temperature to one of lower temperature. Understanding this concept is essential when evaluating materials and structures in thermal applications. In the context of the exercise, imagine heat flowing through a ceiling from the interior of a building to the outside environment. This flow is influenced by thermal resistance, which opposes heat transfer.
Important points include:
  • Heat always moves from hot to cold areas.
  • Higher thermal resistance means less heat flow.
  • Materials like wood and insulation act to slow down this heat flow.
Visualize heat flow as water moving through a pipe, where resistance is like a narrowing of the pipe, reducing the amount of water (or heat) that can pass through.
Insulation
Insulation is a material used to reduce the transfer of heat, aimed at keeping interiors warm in the winter and cool in the summer. It acts by introducing high thermal resistance, thereby minimizing unnecessary heat loss or gain.
For instance, in our exercise involving a wood ceiling with a layer of additional insulation, each material acts as a barrier. The wood has its thermal resistance, but adding insulation significantly boosts the overall resistance to heat flow. Key functions of insulation:
  • Prevents heat from escaping or entering a building.
  • Enhances energy efficiency for cost savings.
  • Can be made from various materials like fiberglass, foam, and even natural materials.
Overall, insulation is a simple, yet effective way to manage energy use, maintain comfort, and reduce energy costs.
Series Resistance
Series resistance pertains to the combined effect of multiple thermal resistances lined up one after another, like the multiple materials in a ceiling's structure. When resistances are placed in series, you add up their values for a total resistance.
In our example, the wood ceiling and the insulation layer each have their own resistance, denoted as \(R_1\) and \(R_2\), respectively. These resistances add up when stacked in series:\[R = R_1 + R_2\]This principle mirrors electrical circuits where resistors in series are additive, providing an easy way to calculate total resistance along a heat path. This method simplifies analyzing the thermal performance of composite structures like walls, floors, and roofs.
Effective Thermal Resistance
Effective thermal resistance is an inclusive measure of how well a composite material or structure resists heat flow. It is crucial for understanding the overall thermal performance of combined layers. In the problem where a wood ceiling is covered by insulation, the effective thermal resistance determines how well the entire assembly manages heat transfer. It is simply the sum of the individual resistances of each layer, as resistance in series adds up: \[R = R_1 + R_2\]Understanding this concept helps when designing for energy efficiency, as it underscores the cumulative effect of layered materials. Benefits of calculating effective thermal resistance include:
  • Accurate estimation of energy loss or gain.
  • Enhanced design for thermal management.
  • Improved selection of materials for specific insulation needs.
By using effective thermal resistance, you can make well-informed decisions to optimize energy efficiency and comfort within buildings.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Before going in for his annual physical, a \(70.0-\mathrm{kg}\) man whose body temperature is \(37.0^{\circ} \mathrm{C}\) consumes an entire \(0.355-\mathrm{L}\) can of a soft drink (mostly water) at \(12.0^{\circ} \mathrm{C}\) . (a) What will his body temperature be after equilibrium is attained? Ignore any heating bythe man's metabolism. The specific heat of the man's body is 3480 \(\mathrm{J} / \mathrm{kg} \cdot \mathrm{K}\) . (b) Is the change in his body temperature great enough to be measured by a medical themometer?

"The Ship of the Desert" Camels require very little water because they are able to tolerate relatively large changes in their body temperature. While humans keep their body temperatures constant to within one or two Celsius degrees, a dehydrated camel permits its body temperature to drop to \(34.0^{\circ} \mathrm{C}\) overnight and rise to \(40.0^{\circ} \mathrm{C}\) during the day. To see how effective this mechanism is for saving water, calculate how many liters of water a 400 \(\mathrm{kg}\) camel would have to drink if it attempted to keep its body temperature at a constant \(34.0^{\circ} \mathrm{C}\) by evaporation of sweat during the day \(\left(12 \text { hours) instead of letting it rise to } 40.0^{\circ} \mathrm{C} \text { . (Note: The }\right.\) specific heat of a camel or other mammal is about the same as that of a typical human, 3480 \(\mathrm{J} / \mathrm{kg} \cdot \mathrm{K}\) . The heat of vaporization of water at \(34^{\circ} \mathrm{C}\) is \(2.42 \times 10^{6} \mathrm{J} / \mathrm{kg} .\) )

A carpenter builds an exterior house wall with a layer of wood 3.0 \(\mathrm{cm}\) thick on the outside and a layer of Styrofoam insulation 2.2 \(\mathrm{cm}\) thick on the inside wall surface. The wood has \(k=0.080 \mathrm{W} / \mathrm{m} \cdot \mathrm{K}\) , and the Styrofoam has \(k=0.010 \mathrm{W} / \mathrm{m} \cdot \mathrm{K}\) . The interior surface temperature is \(19.0^{\circ} \mathrm{C}\) , and the exterior surface temperature is \(-10.0^{\circ} \mathrm{C}\) (a) What is the temperature at the plane where the wood meets the Styrofoam? (b) What is the rate of heat flow per square meter through this wall?

(a) A wire that is 1.50 \(\mathrm{m}\) long at \(20.0^{\circ} \mathrm{C}\) is found to increase in length by 1.90 \(\mathrm{cm}\) when warmed to \(420.0^{\circ} \mathrm{C}\) . Compute its average coefficient of linear expansion for this temperature range. (b) The wire is stretched just (zero tension) at \(420.0^{\circ} \mathrm{C}\) . Find the stress in the wire if it is cooled to \(20.0^{\circ} \mathrm{C}\) without being allowed to contract. Young's modulus for the wire is \(20 \times 10^{11} \mathrm{Pa}\) .

Suppose that a steel hoop could be constructed to fit just around the earth's equator at a temperature of \(20.0^{\circ} \mathrm{C}\) . What would be the thickness of space between the hoop and the earth if the temperature of the hoop were increased by 0.500 \(\mathrm{C}^{\circ} ?\)

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.