/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 120 Food Intake of a Hamster. The en... [FREE SOLUTION] | 91Ó°ÊÓ

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Food Intake of a Hamster. The energy output of an animal engaged in an activity is called the basal metabolic rate (BMR) and is a measure of the conversion of food energy into other forms of energy. A simple calorimeter to measure the BMR consists of an insulated box with a thermometer to measure the temperature of the air. The air has density 1.20 \(\mathrm{kg} / \mathrm{m}^{3}\) and specific heat 1020 \(\mathrm{J} / \mathrm{kg} \cdot \mathrm{K}\) . A 50.0 -g hamster is placed in a calorimeter that contains 0.0500 \(\mathrm{m}^{3}\) of air at room temperature. (a) When the hamster is running in a wheel, the temperature of the air in the calorimeter rises 1.60 \(\mathrm{C}^{\circ}\) per hour. How much heat does the running hamster generate in an hour? Assume that all this heat goes into the air in the calorimeter. You can ignore the heat that goes into the walls of the box and into the thermometer, and assume that no heat is lost to the surroundings. (b) Assuming that the hamster converts seed into heat with an efficiency of 10\(\%\) and that hamster seed has a food energy value of 24 \(\mathrm{J} / \mathrm{g}\) , how many grams of seed must the hamster eat per hour to supply this energy?

Short Answer

Expert verified
The hamster generates 97.92 J of heat per hour and needs to eat 40.8 grams of seed per hour to meet this energy requirement.

Step by step solution

01

Calculate the mass of the air in the calorimeter

Given the density of air is 1.20 kg/m³ and the volume of air in the calorimeter is 0.0500 m³. The mass of the air can be calculated using the formula:\[ \text{mass} = \text{density} \times \text{volume} \]Substituting the values:\[ \text{mass} = 1.20 \, \text{kg/m}^3 \times 0.0500 \, \text{m}^3 = 0.0600 \, \text{kg} \]
02

Calculate the heat generated by the hamster

The formula for heat energy is:\[ Q = m \cdot c \cdot \Delta T \]where \( m \) is the mass of the air, \( c \) is the specific heat capacity, and \( \Delta T \) is the change in temperature. Substituting the values:\[ Q = 0.0600 \, \text{kg} \times 1020 \, \text{J/kg} \cdot \text{K} \times 1.60 \, \text{K} \]\[ Q = 97.92 \, \text{J} \]Therefore, the hamster generates 97.92 J of heat per hour.
03

Determine the amount of energy the hamster converts into food

The hamster has an efficiency of 10% in converting seed energy into heat energy. Thus, if \( Q \) is the heat generated, the food energy required is:\[ \text{Energy consumed} = \frac{Q}{\text{Efficiency}} = \frac{97.92 \, \text{J}}{0.10} \]\[ \text{Energy consumed} = 979.2 \, \text{J} \]
04

Calculate the grams of seed needed based on energy value

Each gram of seed provides 24 J of energy. To find out how many grams are needed:\[ \text{mass of seed} = \frac{\text{Energy consumed}}{\text{Energy per gram}} = \frac{979.2 \, \text{J}}{24 \, \text{J/g}} \]\[ \text{mass of seed} = 40.8 \, \text{g} \]
05

Conclusion

The hamster generates 97.92 J of heat per hour. To support this energy output, the hamster must consume approximately 40.8 grams of seed per hour.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Calorimetry
Calorimetry is the science of measuring the heat of chemical reactions or physical changes, and it provides vital insights into metabolic processes. In this exercise, a simple calorimeter is used to determine the Basal Metabolic Rate (BMR) of a hamster by measuring the heat generated while it runs in a wheel.
The calorimeter confines the hamster within an insulated box containing air, which acts as the medium for heat absorption. By observing the temperature increase of the air over time, one can deduce the amount of heat energy produced by the hamster.
Such measurements allow us to better understand energy transformations in biological systems. The calorimetry process in this context treats the air as a single system, assuming all heat generated is absorbed without loss. This simplification helps in focusing on the hamster's metabolic efficiency and energy requirements.
Heat Energy Calculation
Calculating the heat energy involves knowing the mass of the air inside the calorimeter, the specific heat capacity, and the change in temperature. The formula used is \[ Q = m \cdot c \cdot \Delta T \]where \( Q \) represents the heat energy, \( m \) is the mass of the air, \( c \) is the specific heat capacity, and \( \Delta T \) is the temperature change.

In this example, the air's density and the calorimeter's volume allow the computation of the air's mass, which combined with the given specific heat and temperature change, results in the total heat energy.
  • The density of air provides a basis to calculate its mass: \(1.20 \, \text{kg/m}^3\).
  • Given volume: \(0.0500 \, \text{m}^3\).
  • Resulting mass: \(0.0600 \, \text{kg}\).
This energy calculation is pivotal to understanding how organisms like the hamster utilize food energy.
Metabolic Efficiency
Metabolic efficiency refers to how effectively an organism can convert energy from food into other forms of energy, such as heat. This exercise addresses how efficiently a hamster converts the energy from seeds it consumes into the heat energy it produces when running.

The efficiency percentage given (10%) implies that only a fraction of the food energy is utilized for generating heat, while the rest may be used in other biological processes or stored. This concept ensures that we take into consideration not just the calories consumed, but how these calories are utilized in the body.
Understanding metabolic efficiency is crucial for assessing dietary needs and energy balance in living organisms.
Specific Heat Capacity
Specific heat capacity is a key concept in calculating how much the temperature of a substance changes as it absorbs or loses heat. It is defined as the amount of heat per unit mass required to raise the temperature by one degree Celsius.

The air in the calorimeter has a specific heat capacity of \(1020 \, \text{J/kg} \cdot \text{K}\). This means that it requires 1020 joules of heat to raise the temperature of one kilogram of air by one degree Kelvin.

Understanding specific heat capacity is essential in determining how different substances react to heat energy, which is vital for processes like calorimetry where heat changes are measured. Specific heat capacity plays a crucial role in energy transformations and is integral to understanding thermal exchanges in biological and physical systems.

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Most popular questions from this chapter

A tube leads from a \(0.150-\mathrm{kg}\) calorimeter to a flask in which water is boiling under atmospheric pressure. The calorimeter has specific heat capacity 420 \(\mathrm{J} / \mathrm{kg} \cdot \mathrm{K}\) , and it originally contains 0.340 \(\mathrm{kg}\) of water at \(15.0^{\circ} \mathrm{C}\) . Steam is allowed to condense in the calorimeter at atmospheric pressure until the temperature of the calorimeter and contents reaches \(71.0^{\circ} \mathrm{C}\) , at which point the total mass of the calorimeter and its contents is found to be 0.525 \(\mathrm{kg}\) . Compute the heat of vaporization of water from these data.

A 500.0 -g chunk of an unknown metal, which has been in boiling water for several minutes, is quickly dropped into an insulating Styrofoam beaker containing 1.00 \(\mathrm{kg}\) of water at room temperature \(\left(20.0^{\circ} \mathrm{C}\right)\) . After waiting and gently stirring for 5.00 minutes, you observe that the water's temperature has reached a constant value of \(22.0^{\circ} \mathrm{C}\) (a) Assuming that the Styrofoam absorbs a negligibly small amount of heat and that no heat was lost to the surroundings, what is the specific heat of the metal? (b) Which is more useful for storing thermal energy: this metal or an equal weight of water? Explain. (c) What if the heat absorbed by the Styrofoam actually is not negligible. How would the specific heat you calculated in part (a) be in error? Would it be too large, too small, or still correct? Explain.

One end of an insulated metal rod is maintained at \(100.0^{\circ} \mathrm{C}\) and the other end is maintained at \(0.00^{\circ} \mathrm{C}\) by an ice-water mixture. The rod is 60.0 \(\mathrm{cm}\) long and has a cross-sectional area of 1.25 \(\mathrm{cm}^{2}\) . The heat conducted by the rod melts 8.50 \(\mathrm{g}\) of ic. 0 min. Find the thermal conductivity \(k\) of the metal.

The density of water is 999.73 \(\mathrm{kg} / \mathrm{m}^{3}\) at a temperature of \(10^{\circ} \mathrm{C}\) and 958.38 \(\mathrm{kg} / \mathrm{m}^{3}\) at a temperature of \(100^{\circ} \mathrm{C} .\) Calculate the average coefficient of volume expansion for water in that range of temperature.

An electric kitchen range has a total wall area of 1.40 \(\mathrm{m}^{2}\) and is insulated with a layer of fiberglass 4.00 \(\mathrm{cm}\) thick. The inside surface of the fiberglass has a temperature of \(175^{\circ} \mathrm{C}\) , and its outside surface is at \(35.0^{\circ} \mathrm{C}\) . The fiberglass has a thermal conductivity of 0.040 \(\mathrm{W} / \mathrm{m} \cdot \mathrm{K}\) (a) What is the heat current through the insulation, assuming it may be treated as a flat slab with an area of 1.40 \(\mathrm{m}^{2} ?(\mathrm{b})\) What electric- power input to the heating element is required to maintain this temperature?

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