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Chapter 19: Problem 13

When you blow hard on your hand, it feels cool, but when you breathe softly, it feels warm. Why?

Short Answer

Expert verified
Answer: The difference in perception of temperature when blowing hard and breathing softly on your hand is due to the different rates of heat transfer caused by the difference in air speed. Faster air speed when blowing hard leads to a faster evaporation rate and higher heat transfer rate, making your hand feel cooler. Conversely, slower air speed when breathing softly results in a lower evaporation rate and slower heat transfer rate, making your hand feel warmer.

Step by step solution

01

Describe the perception of temperature

When you blow hard on your hand, it feels cool, and when you breathe softly, it feels warm. This difference is related to the rate of evaporation and heat transfer between the air and your hand.
02

Discuss the role of evaporation

Evaporation is a process in which liquid turns into vapor. In our bodies, sweat is produced by sweat glands, and when it evaporates, it absorbs heat from the skin, providing a cooling effect. The faster the sweat evaporates, the cooler your hand will feel.
03

Compare heat transfer rates with different air speeds

When you blow on your hand with a high speed, the air moves over your skin more quickly, leading to a higher evaporation rate. This faster evaporation rate increases the heat transfer rate from your hand to the air, making your hand feel cooler. When you breathe softly on your hand, the air speed is slower, resulting in a lower evaporation rate. Therefore, the heat transfer rate from your hand to the air is also slower, allowing the warm moisture in your breath to accumulate near your skin and make your hand feel warmer.
04

Explain the difference in perception of temperature

The difference in perception of temperature when blowing hard and breathing softly on your hand is due to the different rates of heat transfer caused by the difference in air speed. When blowing hard on your hand, the faster air speed leads to a faster evaporation rate, which causes a higher heat transfer rate and makes your hand feel cooler. When breathing softly, the slower air speed and lower evaporation rate result in a slower heat transfer rate, making your hand feel warmer.

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Most popular questions from this chapter

One \(1.00 \mathrm{~mol}\) of an ideal gas is held at a constant volume of \(2.00 \mathrm{~L}\). Find the change in pressure if the temperature increases by \(100 .{ }^{\circ} \mathrm{C}\).

Air in a diesel engine cylinder is quickly compressed from an initial temperature of \(20.0^{\circ} \mathrm{C}\), an initial pressure of \(1.00 \mathrm{~atm}\), and an initial volume of \(600 . \mathrm{cm}^{3}\) to a final volume of \(45.0 \mathrm{~cm}^{3}\). Assuming the air to be an ideal diatomic gas, find the final temperature and pressure.

Liquid bromine \(\left(\mathrm{Br}_{2}\right)\) is spilled in a laboratory accident and evaporates. Assuming the vapor behaves as an ideal gas, with a temperature \(20.0^{\circ} \mathrm{C}\) and a pressure of \(101.0 \mathrm{kPa}\), find its density.

In a diesel engine, the fuel-air mixture is compressed rapidly. As a result, the temperature rises to the spontaneous combustion temperature for the fuel, causing the fuel to ignite. How is the temperature rise possible, given the fact that the compression occurs so rapidly that there is not enough time for a significant amount of heat to flow into or out of the fuel-air mixture?

Consider nitrogen gas, \(\mathrm{N}_{2}\), at \(20.0^{\circ} \mathrm{C}\). What is the root-mean-square speed of the nitrogen molecules? What is the most probable speed? What percentage of nitrogen molecules have a speed within \(1.00 \mathrm{~m} / \mathrm{s}\) of the most probable speed? (Hint: Assume the probability of neon atoms having speeds between \(200.00 \mathrm{~m} / \mathrm{s}\) and \(202.00 \mathrm{~m} / \mathrm{s}\) is constant. \()\)
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