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A device called an insolation meter is used to measure the intensity of sunlight. It has an area of \(100 \mathrm{cm}^{2}\) and registers \(6.50 \mathrm{W}\). What is the intensity in \(\mathrm{W} / \mathrm{m}^{2}\) ?

Short Answer

Expert verified
The intensity of sunlight measured by the insolation meter is \(650 W/m^2\).

Step by step solution

01

Convert area from cm² to m²

To convert the given area from cm² to m², we can use the conversion factor: 1 m² = 10^4 cm². So, we have: \( Area_{m^2} = Area_{cm^2} \times \frac{1 m^2}{10^4 cm^2} \)
02

Calculate the intensity

Now that we have the area in m², we can use the equation for intensity to find the intensity in W/m². The equation for intensity is: \( Intensity (W/m^2) = \frac{Power (W)}{Area (m^2)} \)
03

Substitute values and solve for intensity

Using the given values for area and power in the equation, we can find the intensity: \( Intensity (W/m^2) = \frac{6.5 W}{100 \times \frac{1 m^2}{10^4 cm^2}} \) \( Intensity (W/m^2) = \frac{6.5 W}{\frac{100}{10^4} m^2} \)
04

Remove the fraction within the fraction

In the expression, we have a fraction within a fraction. We can eliminate this by multiplying the numerator and denominator of the main fraction by \(10^4\): \(Intensity (W/m^2) = \frac{6.5 W \times 10^4}{100 m^2} \)
05

Simplify and get the final result

Now, we just need to simplify the expression and get the intensity in W/m²: \( Intensity (W/m^2) = \frac{6.5 \times 10^4 W}{100 m^2} \) \( Intensity (W/m^2) = \frac{65000 W}{100 m^2} \) \( Intensity (W/m^2) = 650 W/m^2 \) So, the intensity of sunlight measured by the insolation meter is \(650 W/m^2\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Unit Conversion
Unit conversion is a fundamental step in many scientific calculations, ensuring that measurements are represented in the correct units for analysis. In the context of physics, unit conversion often involves converting areas, lengths, masses, or other quantities between various measurement systems.
One common conversion is between square centimeters and square meters. Since there are 10,000 square centimeters in one square meter, converting from cm² to m² requires dividing by 10,000.
  • To convert an area of 100 cm² to m², use the conversion factor: \(1 \text{ m}^2 = 10^4 \text{ cm}^2\)
  • The calculation then becomes: \(\text{Area (m}^2) = 100 \text{ cm}^2 \times \frac{1 \text{ m}^2}{10^4 \text{ cm}^2} = 0.01 \text{ m}^2\)
Understanding unit conversion is crucial in physics, as it allows one to interpret results in standardized units, which is vital for further calculations and coherence across scientific disciplines.
Mathematics in Physics
Mathematics serves as the backbone for expressing and solving problems in physics. It allows for precise modeling of physical phenomena and provides tools to analyze various scenarios.
In the example of determining solar intensity, mathematics helps establish the relationship between power, area, and intensity.
  • The formula used is: \( \text{Intensity (W/m}^2) = \frac{\text{Power (W)}}{\text{Area (m}^2)} \)
  • This relationship is derived from the concept of power per unit area, a key component in understanding energy flux.
Breaking down the equation, we compute the intensity by dividing the measured power output (in watts) by the converted area (in m²). This step demonstrates how mathematical equations in physics are set up to ensure accurate and meaningful results.
Additionally, simplifying expressions like fractions within fractions is a critical skill in making calculations straightforward.
Thus, mathematics in physics is about translating real-world data into solvable problems, ensuring clarity and accuracy in solutions.
Insolation Measurement
Insolation measurement refers to the quantification of solar radiation energy received on a given surface area over a specific period. This measurement is crucial for applications like solar panel placement, climate studies, and ecological modeling.
An insolation meter measures the solar energy incident on its surface and provides data often expressed in watts per square meter (W/m²).
  • This device helps quantify the solar power received per unit area, a metric known as intensity.
  • Understanding intensity aids in determining how much energy is available for conversion into electricity or heat.
The process involves calculating the energy registered by the meter and normalizing it over the area exposed to sunlight. For instance, if an insolation meter with an area of 0.01 m² measures 6.5 watts, the intensity is calculated as 650 W/m². This value provides insight into the local solar energy potential.
Insolation measurement forms the basis for efficient solar energy utilization and environmental assessments, highlighting its significance in sustainable energy solutions.

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