91Ó°ÊÓ

When a gas undergoes expansion or compression, it can do work on its surroundings or have work done on it.
In an isobaric process, which means the pressure remains constant, we need to calculate the work done during the expansion of the gas. The formula for work done in an isobaric process is: \[W = P \times \Delta V\]Where:- \(W\) is the work done by the gas, - \(P\) is the constant pressure, and - \(\Delta V\) is the change in volume of the gas.
The work done is positive if the system (gas) does work on the surroundings, as in expansion. Conversely, it is negative if work is done on the system.
In the given exercise, the gas expands from 3.00 L to 5.00 L under a constant pressure of 2.00 atm, doing 405.3 Joules of work on its surroundings.

A quasistatic process is a hypothetical process that happens infinitely slowly, so that the system is always in equilibrium.
This idealization allows us to assume each state of the gas as a state of thermal and mechanical equilibrium. In practice, a true quasistatic process can't occur because processes take time and systems achieve equilibrium gradually.
For calculations, however, assuming quasistatic conditions simplifies analysis and provides good approximations.
During the quasistatic isobaric expansion of the gas, it goes from one volume to another at equilibrium, allowing the direct application of the work formula for isobaric processes. Thus, it enables straightforward application of the work done formula for this case.

Pressure-volume work is a key concept in thermodynamics related to the energy transferred in the form of work. When a system expands or is compressed, the energy exchange involves pressure and volume change.
In the formula \(W = P \times \Delta V\), pressure-volume work is specifically related to scenarios where there's a volume change at constant pressure (isobaric process).
The important details in calculating this work:

• Ensure the pressure is in the correct units (e.g., converting atm to J/L if volume is in liters).
• Calculate the change in volume by subtracting the initial volume from the final volume.
• Multiply the consistent pressure by the calculated change in volume.

This approach allows for a straightforward calculation of the work done, as demonstrated in the example where 405.3 J of work is calculated for the given gas expansion.