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Find the equation of state of a solid that has an isobaric expansion coefficient \(d V / d T=2 c T-b p \quad\) and \(\quad\) an isothermal pressure- volume coefficient \(d V / d p=-b T\).

Short Answer

Expert verified
The equation of state for the solid is \( V = cT^2 - bTp \)

Step by step solution

01

Solve the first partial derivative equation

Because \(d V / d T=2 c T-b p\) is given, rewrite it as \( dV = (2cT - bp) dT \). The integral of both sides with respect to T gives the partial solution for V as function of T and p: \( V = cT^2 - bTp + A(p) \), where A(p) is an integration constant which can be a function of p.
02

Solve the second partial derivative equation

Given \(d V / d p=-b T\) which can be rewritten as \( dV = -bT dp \). Substitute V from the solution of step 1 into this equation, it gets \( cT^2 - bTp + A(p) = -bT dp \). The integral of both sides with respect to p gives the partial solution for V as function of p and T: \( V = -bT^2p + B(T) \), where B(T) is the integration constant, which can be function of T.
03

Combine the two solutions to formulate the equation of state

By comparing the results from step 1 and step 2, which are equations for the volume V, one could find the equation of state. Here \( A(p) \) equals to zero, because there is no p function term at the right side of equation in step 2. Therefore, the equation of state of the solid could be expressed as: \( V = cT^2 - bTp \)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Isobaric Expansion Coefficient
The isobaric expansion coefficient is an important concept in thermodynamics, which refers to the rate at which the volume of a material changes with temperature, while the pressure remains constant. It is represented by the equation, \( \frac{dV}{dT} \), and quantifies how much volume variation we can expect for a given substance when subjected to a temperature change under isobaric conditions—that is, without a change in pressure.

In the context of the exercise, the solid’s volume change with temperature at constant pressure is given by the expression \( 2cT - bp \), where \( c \) and \( b \) are material-specific constants, \( T \) represents temperature, and \( p \) designates pressure. Understanding the isobaric expansion coefficient allows us to predict how materials behave when heated or cooled, which is critical in various engineering applications, where materials undergo thermal stress.
Isothermal Compressibility
Isothermal compressibility is a measure of the relative volume change of a substance at constant temperature when pressure is varied. Mathematically, it’s represented by \( \frac{dV}{dp} \) under isothermal conditions. For a given material, it describes how compressible the material is; in other words, how much it will shrink or expand when the pressure is increased or decreased without altering the temperature.

From the exercise, we understand that the solid's volume responds to the pressure change at a constant temperature by the coefficient \( -bT \) where \( T \) stands for temperature and \( b \) is a constant characteristic of the material. Knowledge of the isothermal compressibility is vital for applications such as hydraulics, where pressures change but temperatures are intended to remain constant.
Thermodynamics
Thermodynamics is the branch of physics that deals with the relationships between heat and other forms of energy. In essence, it's the study of how thermal energy is converted to and from other forms of energy and how it affects matter. The field sets the foundational principles for understanding phenomena such as energy transfer, the efficiency of engines, and the properties of gases and solids under varying conditions of pressure, temperature, and volume.

The exercise we are considering defines an equation of state for a solid, which is a thermodynamic function describing the state of matter under a given set of physical conditions. By combing the isobaric expansion coefficient and the isothermal compressibility, we arrive at an equation of state:\( V = cT^2 - bTp \). This nonlinear relationship illustrates how thermodynamic principles are applied to relate macroscopic properties (volume, in this case) to temperature and pressure, offering invaluable insights into material behavior and system design in the practical world of engineering and physical sciences.

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Most popular questions from this chapter

(a) An ideal gas expands adiabatically from a volume of \(2.0 \times 10^{-3} \mathrm{m}^{3}\) to \(2.5 \times 10^{-3} \mathrm{m}^{3}\). If the initial pressure and temperature were \(5.0 \times 10^{5} \mathrm{Pa}\) and \(300 \mathrm{K}\) respectively, what are the final pressure and temperature of the gas? Use \(\gamma=5 / 3\) for the gas. (b) In an isothermal process, an ideal gas expands from a volume of \(2.0 \times 10^{-3} \mathrm{m}^{3}\) to \(2.5 \times 10^{-3} \mathrm{m}^{3} .\) If the initial pressure and temperature were \(5.0 \times 10^{5} \mathrm{Pa}\) and \(300 \mathrm{K}\), respectively, what are the final pressure and temperature of the gas?

A gas at a pressure of 2.00 atm undergoes a quasistatic isobaric expansion from 3.00 to 5.00 L. How much work is done by the gas?

Two moles of a monatomic ideal gas such as oxygen is compressed adiabatically and reversibly from a state (3 atm, 5 L) to a state with a pressure of 4 atm. (a) Find the volume and temperature of the final state. (b) Find the temperature of the initial state. (c) Find work done by the gas in the process. (d) Find the change in internal energy in the process. Assume \(C_{V}=5 R\) and \(C_{p}=C_{V}+R\) for the diatomic ideal gas in the conditions given.

A gas in a cylindrical closed container is adiabatically and quasi-statically expanded from a state \(A\) (3 MPa, 2 L) to a state \(B\) with volume of 6 L along the path \(1.8 p V=\) constant. \((\text { a) Plot the path in the } p V\) plane. (b) Find the amount of work done by the gas and the change in the internal energy of the gas during the process.

In an adiabatic process, oxygen gas in a container is compressed along a path that can be described by the following pressure in atm as a function of volume \(\mathrm{V}\), with \(V_{0}=1 L: p=(3.0 \mathrm{atm})\left(V / V_{0}\right)^{-1.2} .\) The initial and final volumes during the process were 2 L and 1.5 L, respectively. Find the amount of work done on the gas.

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