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A cockroach of mass \(m\) runs counterclockwise around the rim of a lazy Susan (a circular dish mounted on a vertical axle) of radius \(R\) and rotational inertia \(I\) and having frictionless bearings. The cockroach's speed (relative to the ground) is \(v\), whereas the lazy Susan turns clockwise with rotational speed \(\omega_{1}\). The cockroach finds a bread crumb on the rim and, of course, stops. (a) What is the rotational speed of the lazy Susan after the cockroach stops? (b) Is mechanical energy conserved?

Short Answer

Expert verified
The final rotational speed is \( \omega_{2} = \frac{m v R}{I} - \omega_{1} \). Mechanical energy is not necessarily conserved.

Step by step solution

01

Analyze Initial Angular Momentum

The total angular momentum of the system (cockroach and lazy Susan) is the sum of the individual angular momenta. Before the cockroach stops, the angular momentum of the cockroach is \[ L_{\text{cockroach}} = m v R \]. The angular momentum of the lazy Susan is \[ L_{\text{lazy Susan}} = - I \omega_{1} \] (negative because it is rotating clockwise).
02

Apply Conservation of Angular Momentum

Since there are no external torques acting on the system, the total angular momentum is conserved. Set up the conservation equation: \[ m v R - I \omega_{1} = I \omega_{2} \], where \omega_{2} is the new angular speed of the lazy Susan after the cockroach stops.
03

Solve for \omega_{2}

Rearrange the conservation equation to solve for \omega_{2}: \[ \omega_{2} = \frac{m v R}{I} - \omega_{1} \]. This represents the rotational speed of the lazy Susan after the cockroach stops.
04

Analyze Mechanical Energy Conservation

Calculate the initial and final kinetic energies to check if mechanical energy is conserved. Initial kinetic energy: \[ K_{\text{initial}} = \frac{1}{2} m v^{2} + \frac{1}{2} I \omega_{1}^{2} \]. Final kinetic energy: \[ K_{\text{final}} = \frac{1}{2} I \omega_{2}^{2} \]. Compare both values.
05

Conclusion on Mechanical Energy

Since there is no friction, ideally mechanical energy should be conserved. However, Kinetic energy often decreases in such a scenario due to inelastic interactions (like the cockroach stopping). Therefore, mechanical energy is not necessarily conserved in terms of kinetic energy alone.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

kinetic energy
Kinetic energy is the energy possessed by an object due to its motion. For the cockroach, this is given by the formula \(\frac{1}{2} m v^2\). Here, \(m\) represents its mass and \(v\) its velocity.
For the lazy Susan, which is a rotating object, the kinetic energy is described by \(\frac{1}{2} I \omega_1^2\), where \(I\) stands for its rotational inertia and \(\omega_1\) its angular speed.
When we analyze mechanical systems, it’s crucial to understand both translational kinetic energy (as in the cockroach's movement) and rotational kinetic energy (as in the spinning lazy Susan). This knowledge helps us understand how energy is distributed and transformed within the system.
Initially, both the cockroach and lazy Susan have their kinetic energies, which combine to form the system's total initial kinetic energy. When the cockroach stops, only the lazy Susan has kinetic energy, thus the focus shifts.
rotational dynamics
Rotational dynamics deals with the motion of objects rotating around an axis. It’s governed by principles similar to linear motion but adapted for rotation. A key aspect here is angular momentum, which is the rotational counterpart of linear momentum.
The angular momentum of the cockroach running around the rim is \(m v R\). It accounts for its mass \(m\), speed \(v\), and the radius \(R\) of the lazy Susan.
The lazy Susan's angular momentum is defined by \(-I \omega_1\), where the negative sign indicates it rotates in the opposite direction.
When the cockroach stops, its angular momentum drops to zero, but conservation of angular momentum requires that the total angular momentum before and after remains the same. Hence, the lazy Susan's rotational speed changes to \(\omega_2\). Using \(\omega_2 = \frac{m v R}{I} - \omega_1\), we calculate the new angular speed, showing how the system adapts to maintain overall balance despite internal changes.
mechanical energy conservation
Mechanical energy conservation is a principle stating that the total mechanical energy in a system remains constant if only conservative forces act on the system. There are two main forms of mechanical energy to consider: kinetic and potential energy. However, in this context, we mainly discuss kinetic energy because we are dealing with motion.
Initially, the system's mechanical energy is the sum of the cockroach's and lazy Susan's kinetic energies: \(K_{\text{initial}} = \frac{1}{2} m v^2 + \frac{1}{2} I \omega_1^2\).
When the cockroach stops, the final kinetic energy becomes \(K_{\text{final}} = \frac{1}{2} I \omega_2^2\).
Comparing initial and final kinetic energies helps evaluate energy changes and identify if non-conservative interactions (like energy dissipation during the cockroach's stop) influenced the system. Ideally, without external forces, mechanical energy should be conserved. However, practical scenarios, like the cockroach stopping, introduce factors that can lead to changes in kinetic energy, implying mechanical energy might not always be conserved in terms of kinetic energy alone.

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