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In each of the following, we specify the Fourier series coefficients of a continuous time signal that is periodic with period \(4 .\) Determine the signal \(x ( t\) ) in each case. (a) \(a_{k}=\left\\{\begin{array}{ll}0, & k=0 \\ (j)^{k} \frac{\sin k \pi^{14}}{k \pi}, & \text { otherwise }\end{array}\right.\) (b) \(a_{k}=(-1)^{k} \frac{\sin k \pi / 8}{2 k \pi}\) (c) \(a_{k}=\left\\{\begin{array}{ll}j k, & |k|<3 \\ 0, & \text { otherwise }\end{array}\right.\) (d) \(a_{k}=\left\\{\begin{array}{ll}1, & k \text { even } \\ 2, & k \text { odd }\end{array}\right.\)

Short Answer

Expert verified
For each part, derive \( x(t) \) by plugging \( a_k \) into the Fourier series formula and simplify using properties of complex exponentials and symmetry.

Step by step solution

01

Understanding the Problem

We are given the Fourier series coefficients for a periodic signal with period \( T = 4 \). The task is to determine the signals \( x(t) \) corresponding to each given coefficient. Recall that if a signal is periodic with period \( T \), its Fourier series is expressed as: \[ x(t) = \, \sum_{k=-\infty}^{\infty} a_k e^{j\frac{2\pi}{T}kt} \] where \( a_k \) are the Fourier coefficients.
02

Solving Part (a)

The coefficients are given by \( a_k = 0 \) for \( k=0 \), and \( a_k = (j)^k \frac{\sin(k\pi/14)}{k\pi} \) otherwise. Substitute into the Fourier series expression: \[ x(t) = \sum_{k=-\infty}^{\infty} (j)^{k} \frac{\sin(k\pi/14)}{k\pi} e^{j\frac{\pi}{2}kt} \] Recognize \( j^k \) as a complex exponential to simplify the expression further, leading to a synthesis using sinusoidal terms based on the symmetry properties of \( \sin \).
03

Solving Part (b)

Here, \( a_k = (-1)^k \frac{\sin(k\pi/8)}{2k\pi} \). Insert this into the Fourier series: \[ x(t) = \sum_{k=-\infty}^{\infty} (-1)^k \frac{\sin(k\pi/8)}{2k\pi} e^{j\frac{\pi}{2}kt} \] The factor \((-1)^k\) causes changes in phase by \( \pi \) every other term, creating alternating symmetry. This signal primarily consists of alternating sinusoidal elements.
04

Solving Part (c)

Given \( a_k = j k \) for \( |k|<3 \) and 0 otherwise. As the signal only has finite non-zero harmonics \((-2, -1, 0, 1, 2)\), it is a combination of these terms: \[ x(t) = -2j e^{-j\pi t} - j e^{-j\pi/2 t} + j e^{j\pi/2 t} + 2j e^{j\pi t} \] Simplify each term considering \( e^{j\theta} = \cos(\theta) + j\sin(\theta) \). This combination results in a signal confined to its fundamental harmonics.
05

Solving Part (d)

Here, \( a_k = 1 \) for even \( k \) and \( 2 \) for odd \( k \). This implies \[ x(t) = \sum_{k=-\infty}^{\infty} (1 + (1 - (-1)^k)) e^{j\pi/2 kt} \] Analyzing the sine and cosine components indicates it contains a more complex pattern from weighted harmonics at each multiple of the fundamental frequency \( \pi/2 \).
06

Putting it Together

For each part, the outcomes are built upon the complex sinusoidal solutions where specific harmonics and symmetry determine the behavior of the time-domain signal. By identifying the pattern of coefficients, expressions for \( x(t) \) are formed from the Fourier series synthesis.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Continuous-Time Signal
In the study of signal processing, a continuous-time signal is a function that has an associated value at every point in time. Unlike discrete signals, which are defined only at specified intervals, continuous-time signals are smooth and unbroken over time. This is key in modeling real-world phenomena like sound waves or electrical currents.

Continuous-time signals can be represented mathematically using functions, usually denoted as \( x(t) \), where \( t \) represents time. These signals are integral in systems and models as they help to simulate and analyze how different inputs interact with a system over time.

For example, when dealing with signals that are periodic, having a complete set of continuous-time signals enables engineers and scientists to form a comprehensive understanding of how a system behaves across various time intervals.
Periodic Signal
A periodic signal is one that repeats itself at regular intervals over time. Understanding periodic signals is crucial for analyzing systems that exhibit repetitive behavior.

Periodic signals have a period \( T \), which is the time duration over which the signal completes one full cycle and begins to repeat. Mathematically, a signal \( x(t) \) is periodic if:
  • \( x(t) = x(t + nT) \)
  • for all \( t \) and any integer \( n \)

In the context of Fourier series, these periodic signals can be decomposed into a sum of sinusoidal functions. Each sine or cosine component corresponds to a specific frequency, which is a harmonic of the fundamental frequency \( f_0 = 1/T \). This property makes periodic signals important in the analysis and synthesis of signals, particularly when considering their frequency content and characteristics.
Fourier Coefficients
Fourier coefficients are essential in expressing periodic signals as Fourier series. They determine the amplitude and phase of each harmonic in the signal's frequency spectrum.

For a periodic signal \( x(t) \) with period \( T \), the Fourier coefficients \( a_k \) are calculated to describe the behavior of the signal in terms of its harmonics. These coefficients are derived using the formula:
  • \( a_k = \frac{1}{T} \int_{0}^{T} x(t) e^{-j\frac{2\pi}{T}kt} dt \)

Each coefficient \( a_k \) corresponds to a unique frequency \( \frac{k}{T} \). The magnitude of \( a_k \) indicates the contribution of the cosine and sine components at that frequency, while the argument determines the phase shift.

This set of coefficients ultimately facilitates the construction of the original signal using these fundamental harmonics, providing a useful toolkit for signal analysis and manipulation.
Signal Synthesis
Signal synthesis involves constructing a complex waveform by superimposing different sinusoidal functions. This process is fundamental when applying the Fourier series to reconstruct a signal from its Fourier coefficients.

The synthesis of a signal \( x(t) \) from its Fourier series can be expressed as:
  • \( x(t) = \sum_{k=-\infty}^{\infty} a_k e^{j\frac{2\pi}{T}kt} \)

This series combines harmonic components that each correspond to a part of the Fourier coefficient sequence \( a_k \). By carefully summing these harmonics, we recreate the waveform of the original periodic signal.

Signal synthesis is incredibly useful not only for analyzing existing signals but also for designing new signals that meet specific frequency criteria. It's widely used in fields such as telecommunications, audio processing, and control systems, where precise waveform generation is often required.

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Most popular questions from this chapter

Let \(x(t)\) be a periodic signal whose Fourier series coefficients are \(a_{k}=\left\\{\begin{array}{ll}2, & k=0 \\ j\left(\frac{1}{2}\right)^{|k|}, & \text { othervise }\end{array}\right.\). Use Fourier series properties to answer the following questions: (a) Is \(x(t)\) real? (b) Is \(x(t)\) even? (c) Is \(d x(t) / d t\) even?

Suppose that a continuous-time periodic signal is the input to an LTI system. The signal has Fourier series representation \(x(t)=\sum_{k=-\infty}^{\infty} \alpha^{|k|} e^{j k(\pi / 4)}\), where \(\alpha\) is a real number between 0 and \(1,\) and the frequency response of the system is \(H(j \omega)=\left\\{\begin{array}{ll}1, & \\{\omega \leq W \\ 0, & |\omega|>W\end{array}\right.\). How large must \(W\) be in order for the output of the system to have at least \(90 \%\) of the average energy per period of \(x(f) ?\)

Let \(x(t)\) be a real-valued signal with fundamental period \(T\) and Fourier series coefficients \(a_{k}\). (a) Show that \(a_{k}=a_{-k}^{*}\) and \(a_{0}\) must be real. (b) Show that if \(x(t)\) is even, then its Fourier series coefficients must be real and even. (c) Show that if \(x(f)\) is odd, then its Fourier series coefficients are imaginary and odd and \(a_{0}=0\).

Consider a continuous-time ideal lowpass filter \(S\) whose frequency response is $$H(j \omega)=\left\\{\begin{array}{ll}1, & |\omega| \leq 100 \\\0, & |\omega|>100\end{array}\right.$$. When the input to this filter is a signal \(x(t)\) with fundamental period \(T=\pi / 6\) and Fourier series coefficients \(a_{k},\) it is found that \(x(t) \stackrel{s}{\longrightarrow} y(t)=x(t)\). For what values of \(k\) is it guaranteed that \(a_{k}=0 ?\)

Suppose we are given the following information about a signal \(x(t)\): 1\. \(x(t)\) is real and odd. 2\. \(x(t)\) is periodic with period \(T=2\) and has Fourier coefficients \(a_{k}\). 3\. \(a_{k}=0\) for \(|k|>1\). 4\. \(\left.\frac{1}{2}\right|_{0} ^{2}|x(t)|^{2} d t=1\). Specify two different signals that satisfy these conditions.

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