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Let \(x(t)\) be a real-valued signal with fundamental period \(T\) and Fourier series coefficients \(a_{k}\). (a) Show that \(a_{k}=a_{-k}^{*}\) and \(a_{0}\) must be real. (b) Show that if \(x(t)\) is even, then its Fourier series coefficients must be real and even. (c) Show that if \(x(f)\) is odd, then its Fourier series coefficients are imaginary and odd and \(a_{0}=0\).

Short Answer

Expert verified
(a) Real signals have symmetric Fourier coefficients: \(a_k = a_{-k}^{*}\), \(a_0\) is real. (b) Even signals have real, even coefficients. (c) Odd signals have imaginary, odd coefficients; \(a_0 = 0\).

Step by step solution

01

Understanding Fourier Series

Fourier series represents any periodic function as a sum of sines and cosines. For a real-valued signal, its Fourier series is represented as \(x(t) = \sum_{k=-\infty}^{\infty} a_k e^{j\frac{2\pi kt}{T}}\), where \(T\) is the fundamental period and \(a_k\) are the Fourier coefficients.
02

Prove for Real-valued Signals

The Fourier coefficients for real-valued functions have a symmetric property: \(a_k = a_{-k}^{*}\). This follows from the property of the complex exponential terms, \(e^{-j\omega t}\), shared for negative index terms in Fourier series.
03

Show Re{ ablak ak { 0} form ak coefficients

Since the signal is real-valued, its average power or DC component is \(a_0 = \frac{1}{T} \int_{T_0}^{T_0 + T} x(t) dt \). Since the integral of a real function is real, \(a_0\) is real.
04

Addresses Even Function Coefficients

If \(x(t)\) is even, then \(x(-t) = x(t)\). Substituting in the Fourier series, all sine terms vanish (since sine is odd), and we are left with only cosine terms. Hence, \(a_k\) becomes real and \(a_{k} = a_{-k}\), establishing them as even.
05

Investigates Odd Function Coefficients

For \(x(t)\) as an odd function \(x(-t) = -x(t)\), cosine terms vanish leaving sine terms. This results in \(a_k\) being pure imaginary (since they result in multiplication of sine's imaginary term in the coefficient), and \(a_k = -a_{-k}\). Also, \(a_0 = 0\) because the average of an odd function over its period is zero.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Real Signal Representation
A real signal can be effectively represented using the Fourier series. The Fourier series decomposes a periodic function into a sum of sine and cosine terms. This series can be represented for a real-valued function as:
  • \[ x(t) = \sum_{k=-\infty}^{\infty} a_k e^{j\frac{2\pi kt}{T}} \]
Here, \(x(t)\) is the signal, \(T\) its fundamental period, and \(a_k\) represents the Fourier coefficients. Each term in the sum reflects a basic oscillation occurring within the signal, whether sinusoidal or cosinusoidal, thus building the waveform through their superposition.

The Fourier series allows us to fully define the signal characteristics in the frequency domain through these coefficients. This expansion is possible for any real periodic signal, making it a pivotal tool in signal processing.
Symmetry of Coefficients
For real-valued signals, the Fourier coefficients exhibit symmetry referred to as "conjugate symmetry." This means:
  • \[ a_k = a_{-k}^* \]
The asterisk denotes the complex conjugate, meaning that coefficients for positive and negative frequencies are reflections across the real axis. Additionally, the coefficient for the zero frequency, \(a_0\), must be a real number because it represents the average value or the DC component of the signal.

This symmetric nature arises from the relationship between the sinusoidal functions and the complex exponentials used in the Fourier framework. Understanding this symmetry is vital for analyzing signal behaviors and reducing computational efforts by observing redundant calculations for negative frequencies.
Even and Odd Functions
When analyzing signals, distinguishing whether the function is even or odd can significantly simplify the process. An even function is characterized by:
  • \(x(t) = x(-t)\): The function mirrors evenly around the vertical axis.
For even functions, Fourier coefficients are purely real, as sine terms become zero (because sine is an odd function). This leads to:
  • \( a_k = a_{-k} \)
Odd functions are defined by:
  • \(x(-t) = -x(t)\): They reflect across the origin.
Here, cosine terms vanish, and Fourier coefficients are purely imaginary and odd. Moreover, the coefficient \(a_0 = 0\) because the integral of an odd function over a symmetric interval is zero. Recognizing these attributes simplifies the calculation of Fourier coefficients and enhances computational efficiency in signal processing.
Periodic Functions
A fundamental aspect of Fourier series is their application to periodic functions, which repeat their values at regular intervals. In mathematical terms, a periodic function satisfies:
  • \(x(t + T) = x(t)\) for all \(t\) and some period \(T\).
Fourier series harness this periodicity to depict functions as sums of harmonically related sine and cosine waves. Each successive wave (or harmonic) in the series corresponds to a multiple of the fundamental frequency \(f = \frac{1}{T}\).

Understanding periodic functions is crucial because they allow us to transform complex time-domain signals into simpler frequency-domain representations. These representations can be more intuitive and easier to manipulate, enabling efficient analysis and processing of real-world signals in various engineering and physics applications.

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Most popular questions from this chapter

Consider three continuous-time systems \(S_{1}, S_{2},\) and \(S_{3}\) whose responses to a cornplex exponential input \(e^{j \text { 5t }}\) are specified as $$\begin{array}{l}S_{1}: e^{j 5 t} \longrightarrow t e^{j 5 t,} \\\S_{2}: e^{j 5 t} \longrightarrow e^{j 5(t-1),} \\\S_{3}: e^{j 5 t} \longrightarrow \cos (5 t).\end{array}$$ For each system, determine whether the given information is sufficient to conclude that the system is definitely not LTI.

For the continuous-time periodic signal \(x(t)=2+\cos \left(\frac{2 \pi}{3} t\right)+4 \sin \left(\frac{5 \pi}{3} t\right)\), determine the fundamental frequency \(\omega_{0}\) and the Fourier series coefficients \(a_{k}\) such that \(x(t)=\sum_{k=-\infty}^{\infty} a_{k} e^{j k \omega_{0} t}\).

One technique for building a dc power supply is to take an ac signal and full- wave rectify it. That is, we put the ac signal \(x(t)\) through a system that produces \(y(t)=\) \(|x(t)|\) as its output. (a) Sketch the input and output wave forms if \(x(t)=\cos t .\) What are the fundamental periods of the input and output? (b) If \(x(t)=\cos t,\) determine the coefficients of the Fourier series for the output \(y(t)\). (c) What is the amplitude of the de component of the input signal? What is the amplitude of the de component of the output signal?

A continuous-time periodic signal \(x(t)\) is real valued and has a fundamental period \(T=8 .\) The nonzero Fourier series coefficients for \(x(t)\) are specified as \(a_{1}=a_{-1}^{*}=j, a_{5}=a_{-5}=2\). Express \(x(t)\) in the form \(x(t)=\sum_{k=0}^{\infty} A_{k} \cos \left(w_{k} t+\phi_{k}\right)\).

Consider three continuous-time periodic signals whose Fourier series representations are as follows: $$x_{1}(t)=\sum_{k=0}^{100}\left(\frac{1}{2}\right)^{k} e^{j k \frac{2 \pi}{50}}$$, $$x_{2}(t)=\sum_{k=-100}^{100} \cos (k \pi) e^{j k \frac{2 \pi}{50} t}$$, $$x_{3}(t)=\sum_{k=-100}^{100} j \sin \left(\frac{k \pi}{2}\right) e^{j k \frac{2 \pi}{50} t}$$. Use Forurier series properties to help answer the following questions: (a) Which of the three signals is/are real valued? (b) Which of the three signals is/are even?

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