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A \(0.25 \mathrm{~kg}\) body oscillates in SHM on a spring that, when extended \(2.0 \mathrm{~mm}\) from its equilibrium position, has an \(8.0 \mathrm{~N}\) restoring force. What are (a) the angular frequency of oscillation, (b) the period of oscillation, and (c) the capacitance of an \(L C\) circuit with the same period if \(L\) is \(5.0 \mathrm{H}\) ?

Short Answer

Expert verified
(a) \(126.49 \text{ rad/s}\), (b) \(0.0497 \text{ s}\), (c) \(6.27 \times 10^{-5} \text{ F}\).

Step by step solution

01

Calculate Spring Constant (k)

The spring constant, denoted by \( k \), is calculated using Hooke's Law, which states \( F = kx \). Here, \( F = 8.0 \text{ N} \) and \( x = 2.0 \text{ mm} = 0.002 \text{ m} \).\[ k = \frac{F}{x} = \frac{8.0}{0.002} = 4000 \text{ N/m} \]
02

Calculate Angular Frequency (ω)

The angular frequency \( \omega \) of a mass-spring system in SHM is given by:\[ \omega = \sqrt{\frac{k}{m}} \]Given \( k = 4000 \text{ N/m} \) and \( m = 0.25 \text{ kg} \), we find:\[ \omega = \sqrt{\frac{4000}{0.25}} = \sqrt{16000} = 126.49 \text{ rad/s} \]
03

Calculate Period of Oscillation (T)

The period of oscillation \( T \) is related to the angular frequency by the formula \( T = \frac{2\pi}{\omega} \).Substitute \( \omega = 126.49 \text{ rad/s} \):\[ T = \frac{2\pi}{126.49} \approx 0.0497 \text{ seconds} \]
04

Calculate Capacitance (C) in LC Circuit

For an \( LC \) circuit, the period \( T \) is given by:\[ T = 2\pi \sqrt{LC} \]Rearranging for capacitance \( C \):\[ C = \frac{T^2}{4\pi^2L} \]Insert \( T = 0.0497 \text{ s} \) and \( L = 5.0 \text{ H} \):\[ C = \frac{(0.0497)^2}{4\pi^2 \times 5.0} \approx 6.27 \times 10^{-5} \text{ F} \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Angular Frequency
Angular frequency, denoted by \( \omega \), is a key concept in simple harmonic motion (SHM). It represents how many oscillations occur in one second, measured in radians per second. In the context of a mass-spring system, it is determined by the formula \( \omega = \sqrt{\frac{k}{m}} \), where \( k \) is the spring constant and \( m \) is the mass of the object attached to the spring.
Understanding angular frequency helps predict the system's behavior. A higher angular frequency implies quicker oscillations. This can alter the dynamics of systems like mass-springs and electrical circuits. By effectively using the angular frequency formula, we can deduce essential attributes of oscillating systems, providing insights into their motion.
Hooke's Law
Hooke's Law is pivotal in understanding the forces involved in simple harmonic motion. It states that the force \( F \) required to extend or compress a spring by a distance \( x \) is proportional to that distance. Mathematically, it is represented as \( F = kx \), where \( k \) is the spring constant.
In practical terms, Hooke's Law tells us that a stiffer spring (higher \( k \)) requires more force to stretch or compress, compared to a softer one. It allows us to calculate the spring constant by measuring the force exerted over a known extension. This constant is crucial in determining other properties of the system, such as angular frequency, as it defines the spring's stiffness.
Understanding Hooke's Law is foundational for anyone studying dynamics of systems involving springs or even broader applications in engineering and physics.
Mass-Spring System
The mass-spring system is a classic example of simple harmonic motion. It consists of a mass attached to a spring that can stretch and compress. The system oscillates back and forth, and its behavior can be predicted using the principles of SHM.
Key features of a mass-spring system include:
  • The restoring force that brings the mass back to equilibrium, explained by Hooke's Law.
  • Its natural oscillation frequency, determined by the mass and the spring constant.
The system's ability to store and transfer energy between kinetic and potential forms makes it particularly interesting in physics and engineering. By varying the mass or spring constant, different oscillation characteristics can be explored, providing a rich ground for studying harmonic motion.
LC Circuit
An \( LC \) circuit, comprising inductance \( L \) and capacitance \( C \), can exhibit oscillations akin to those in mechanical systems. These oscillations arise because of energy transfer between the inductor and capacitor.
In an \( LC \) circuit:
  • Energy shifts between the magnetic field of the inductor and the electric field of the capacitor.
  • It can resonate at a natural frequency, establishing conditions for SHM.
This is analogous to the mass-spring system, but with energy moving between two electrical components. The concept of resonance is crucial here, as it allows the circuit to operate efficiently at specific frequencies, making \( LC \) circuits invaluable in radio communications and signal processing.
Capacitance
Capacitance is a fundamental property of an electrical component that reflects its ability to store charge. In a capacitor, the capacitance \( C \) is defined by the amount of charge it can store per unit voltage, expressed in farads (F).
In the context of an \( LC \) circuit, capacitance plays a vital role in determining the oscillation period and frequency. A high capacitance means more charge storage, affecting how quickly the circuit can oscillate.
Capacitance is not only crucial for energy storage but also determines how reactive a circuit can be. By adjusting capacitance, we can fine-tune the frequency response of \( LC \) circuits, making them adaptable to various applications like filtering and tuning in electronics.

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Most popular questions from this chapter

A series circuit containing inductance \(L_{1}\) and capacitance \(C_{1}\) oscillates at angular frequency \(\omega\). A second series circuit, containing inductance \(L_{2}\) and capacitance \(C_{2}\), oscillates at the same angular frequency. In terms of \(\omega\), what is the angular frequency of oscillation of a series circuit containing all four of these elements? Neglect resistance. (Hint: Use the formulas for equivalent capacitance and equivalent inductance; see Module 25-3 and Problem 11 in Chapter 30.)

An electric motor has an effective resistance of \(61.0 \Omega\) and an inductive reactance of \(52.0 \Omega\) when working under load. The rms voltage across the alternating source is 420 V. Calculate the rms current.

An oscillating \(L C\) circuit consisting of a \(1.0 \mathrm{nF}\) capacitor and a \(9.0 \mathrm{mH}\) coil has a maximum voltage of \(3.0 \mathrm{~V}\). What are (a) the maximum charge on the capacitor, (b) the maximum current through the circuit, and (c) the maximum energy stored in the magnetic field of the coil?

What is the maximum value of an ac voltage whose rms value is \(220 \mathrm{~V}\) ?

Figure 31-23 shows an ac generator connected to a "black box" through a pair of terminals. The box contains an \(R L C\) circuit, possibly even a multiloop circuit, whose ele- ments and connections we do not know. Measurements outside the box reveal that $$ \mathscr{E}(t)=(61.4 \mathrm{~V}) \sin \omega_{a} t $$ and \(i(t)=(0.930 \mathrm{~A}) \sin \left(\omega_{u} t+42.0^{\circ}\right) .\) (a) What is the power factor? (b) Does the current lead or lag the emf? (c) Is the circuit in the box largely inductive or largely capacitive? (d) Is the circuit in the box in resonance? (e) Must there be a capacitor in the box? (f) An inductor? (g) A resistor? (h) At what average rate is energy delivered to the box by the generator? (i) Why don't you need to know \(\omega_{d}\) to answer all these questions?

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