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An oscillating \(L C\) circuit consisting of a \(1.0 \mathrm{nF}\) capacitor and a \(9.0 \mathrm{mH}\) coil has a maximum voltage of \(3.0 \mathrm{~V}\). What are (a) the maximum charge on the capacitor, (b) the maximum current through the circuit, and (c) the maximum energy stored in the magnetic field of the coil?

Short Answer

Expert verified
(a) \(3.0 \times 10^{-9} \, \text{C}\), (b) \(1.0 \times 10^{-3} \, \text{A}\), (c) \(4.5 \times 10^{-9} \, \text{J}\).

Step by step solution

01

Analyze the Given Data

The exercise provides specific values:- Capacitance, \( C = 1.0 \, \text{nF} = 1.0 \times 10^{-9} \, \text{F} \).- Inductance, \( L = 9.0 \, \text{mH} = 9.0 \times 10^{-3} \, \text{H} \).- Maximum voltage across the capacitor, \( V_{max} = 3.0 \, \text{V} \).These values will be used to find the maximum charge, current, and stored energy.
02

Calculate Maximum Charge on the Capacitor

The maximum charge \( Q_{max} \) on the capacitor is given by the formula:\[ Q_{max} = C \times V_{max} \]Substitute the given values:\[ Q_{max} = (1.0 \times 10^{-9} \, \text{F}) \times (3.0 \, \text{V}) = 3.0 \times 10^{-9} \, \text{C} \]
03

Calculate Maximum Current Through the Circuit

The maximum current \( I_{max} \) in the circuit can be computed using the formula:\[ I_{max} = \frac{Q_{max}}{\sqrt{L C}} \]First, find \( \sqrt{L C} \):\[ \sqrt{L C} = \sqrt{(9.0 \times 10^{-3} \, \text{H}) \times (1.0 \times 10^{-9} \, \text{F})} \]\[ = \sqrt{9.0 \times 10^{-12}} = 3.0 \times 10^{-6} \]Now calculate the maximum current:\[ I_{max} = \frac{3.0 \times 10^{-9} \, \text{C}}{3.0 \times 10^{-6}} = 1.0 \times 10^{-3} \, \text{A} \]
04

Calculate Maximum Energy Stored in the Coil

The maximum energy stored in the magnetic field of the coil, \( U_{L,max} \), can be calculated using:\[ U_{L,max} = \frac{1}{2} L I_{max}^2 \]Substitute the known values:\[ U_{L,max} = \frac{1}{2} (9.0 \times 10^{-3} \, \text{H}) (1.0 \times 10^{-3} \, \text{A})^2 \]\[ = \frac{1}{2} \times 9.0 \times 10^{-3} \times 1.0 \times 10^{-6} \]\[ = 4.5 \times 10^{-9} \, \text{J} \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Oscillating Circuit
An oscillating circuit, often referred to as an LC circuit, is a fundamental component in electronics that consists of a capacitor (C) and an inductor (L). These circuits are known for their ability to store energy and are widely used in different applications such as radio transmitters and oscillators. The energy within the circuit oscillates between the inductor and capacitor. Here’s how it works:
  • Initially, the capacitor is charged, building up electric potential energy.
  • Once connected to the inductor, the charge flows through the coil, creating a magnetic field, and transforming electric energy into magnetic energy.
  • This oscillating process continues back and forth, producing a sinusoidal voltage and current.
This continuous oscillation results in alternating currents and voltages, pivotal for tuning purposes in electronic devices.
Understanding the behavior of an LC circuit underpins many advanced concepts in electrical engineering, making it an important subject for students.
Capacitor Charge
In any LC circuit, the charge stored in the capacitor is crucial. It determines the potential difference across the capacitor and impacts the current flow in the circuit. For a fully charged capacitor, its voltage directly relates to the amount of charge it holds, defined by the equation:
\[ Q_{max} = C \times V_{max} \]
Where,
  • \(Q_{max}\) represents the maximum charge.
  • \(C\) stands for capacitance, in farads.
  • \(V_{max}\) is the maximum voltage, in volts.
This relationship helps calculate the charge given the capacitance and voltage, showcasing the energy stored in its electric field. In our exercise, this charge equates to \(3.0 \times 10^{-9} \, ext{C}\) when the capacitor holds its maximum potential of 3 volts. Grasping this connection equips students with the foundation to evaluate and troubleshoot capacitive elements in circuits.
Current Calculation
Calculating the maximum current in an LC circuit involves understanding how charge movement translates into current. Current \(I\), measured in amperes, is essentially the flow of electric charge over time. In our oscillating circuit, the maximum current is where the charge transfer rate reaches its peak. This is given by:
\[ I_{max} = \frac{Q_{max}}{\sqrt{L C}} \]
Where:
  • \(I_{max}\) is the peak current value.
  • \(\sqrt{L C}\) denotes the characteristic angular frequency of the circuit.
Knowing this can simplify tracing current behavior in circuits. In our case, when the maximum charge is \(3.0 \times 10^{-9} \, ext{C}\), the resultant peak current becomes \(1.0 \times 10^{-3} \, ext{A}\). Therefore, understanding this computation is crucial for electronics involving varying currents.
Magnetic Field Energy
In an LC circuit, the inductor's magnetic field accumulates energy as current flows through it. This energy is pivotal for the oscillatory behavior of the circuit, switching between electric and magnetic forms. The maximum energy stored in the inductor is expressed through:
\[ U_{L,max} = \frac{1}{2} L I_{max}^2 \]
This relationship provides insights into how effectively the inductance can store energy. In the example, with
  • \(L = 9.0 \times 10^{-3} \, ext{H}\)
  • \(I_{max} = 1.0 \times 10^{-3} \, ext{A}\)
We find that the maximal energy captured in the magnetic field is \(4.5 \times 10^{-9} \, ext{J}\). Possessing this understanding not only helps in energy evaluations but is also essential for designing efficient energy reservoirs in oscillatory circuits.

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Most popular questions from this chapter

Figure 31-23 shows an ac generator connected to a "black box" through a pair of terminals. The box contains an \(R L C\) circuit, possibly even a multiloop circuit, whose ele- ments and connections we do not know. Measurements outside the box reveal that $$ \mathscr{E}(t)=(61.4 \mathrm{~V}) \sin \omega_{a} t $$ and \(i(t)=(0.930 \mathrm{~A}) \sin \left(\omega_{u} t+42.0^{\circ}\right) .\) (a) What is the power factor? (b) Does the current lead or lag the emf? (c) Is the circuit in the box largely inductive or largely capacitive? (d) Is the circuit in the box in resonance? (e) Must there be a capacitor in the box? (f) An inductor? (g) A resistor? (h) At what average rate is energy delivered to the box by the generator? (i) Why don't you need to know \(\omega_{d}\) to answer all these questions?

In an oscillating \(L C\) circuit, \(L=25.0 \mathrm{mH}\) and \(C=2.89 \mu \mathrm{F}\). At time \(t=0\) the current is \(9.20 \mathrm{~mA}\), the charge on the capacitor is \(3.80 \mu \mathrm{C}\), and the capacitor is charging. What are (a) the total energy in the circuit, (b) the maximum charge on the capacitor, and (c) the maximum current? (d) If the charge on the capacitor is given by \(q=Q \cos (\omega t+\phi)\), what is the phase angle \(\phi\) ? (e) Suppose the data are the same, except that the capacitor is discharging at \(t=0\). What then is \(\phi\) ?

In a certain oscillating \(L C\) circuit, the total energy is converted from clectrical cnergy in the capacitor to magnetie cnergy in the inductor in \(2.50 \mu \mathrm{s}\). What are (a) the period of oscillation and (b) the frequency of oscillation? (c) How long after the magnetic energy is a maximum will it be a maximum again? (d) In one full cycle, how many times will the electrical energy be maximum?

A transformer has 400 primary turns and 10 secondary turns. (a) If \(V_{p}\) is \(120 \mathrm{~V}\) (rms), what is \(V_{s}\) with an open circuit? If the secondary now has a resistive load of \(27 \Omega\), what is the current in the (b) primary and (c) secondary?

In an oscillating series \(R L C\) circuit, show that \(\Delta U / U\), the fraction of the energy lost per cycle of oscillation, is given to a close approximation by \(2 \pi R / \omega L\). The quantity \(\omega L / R\) is often called the \(Q\) of the circuit (for quality). A high- \(Q\) circuit has low resistance and a low fractional energy loss \((=2 \pi / Q)\) per cycle.

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