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Pipe \(A\), which is \(1.80 \mathrm{~m}\) long and open at both ends, oscillates at its third lowest harmonic frequency. It is filled with air for which the speed of sound is \(343 \mathrm{~m} / \mathrm{s}\). Pipe \(B\), which is closed at one end, oscillates at its second lowest harmonic frequency. This frequency of \(B\) happens to match the frequency of \(A\). An \(x\) axis extends along the interior of \(B\), with \(x=0\) at the closed end. (a) How many nodes are along that axis? What are the (b) smallest and (c) second smallest value of \(x\) locating those nodes? (d) What is the fundamental frequency of \(B\) ?

Short Answer

Expert verified
Two nodes; smallest at 0.9 m, second at 2.7 m; fundamental frequency is 95.28 Hz.

Step by step solution

01

Calculate Fundamental Frequency of Pipe A

Pipe A is open at both ends, so its fundamental frequency is determined by its length and the speed of sound. The fundamental frequency (first harmonic) is given by \( f_{1A} = \frac{v}{2L} \), where \( v = 343 \; \mathrm{m/s} \) is the speed of sound and \( L = 1.8 \; \mathrm{m} \) is the length of the pipe. We calculate this as:\[f_{1A} = \frac{343}{2 \times 1.8} = 95.28 \; \mathrm{Hz}\] Thus, the third harmonic is \( f_{3A} = 3 \times 95.28 = 285.84 \; \mathrm{Hz} \).
02

Understand Harmonics in Pipe B

Pipe B is closed at one end, meaning its harmonics are only odd-numbered, and the second lowest harmonic is the third harmonic (n=3). This harmonic must match the third harmonic of pipe A: \( f_{3B} = 285.84 \; \mathrm{Hz} \).
03

Calculate Fundamental Frequency of Pipe B

The third harmonic frequency of a pipe closed at one end is given by \( f_{3B} = 3 \cdot f_{1B} = \frac{3v}{4L} \). Since \( f_{3B} = 285.84 \; \mathrm{Hz} \), solve for \( f_{1B} \):\[f_{1B} = \frac{285.84}{3} = 95.28 \; \mathrm{Hz}\]This is the fundamental frequency of pipe B.
04

Determine Number of Nodes in Pipe B

For a closed pipe at the third harmonic (n=3), there are \( (n+1) \/ 2 \) nodes. Thus, for pipe B, there are \( (3+1) \/ 2 = 2 \) nodes.
05

Locate the Nodes

In a pipe that is closed at one end, nodes occur at distances \( x_n = \frac{(2k-1)\lambda}{4} \) from the closed end, where \( k \) is the harmonic number, starting from \( k = 1 \). First, find the wavelength \( \lambda \) using \( \lambda = \frac{v}{f} = \frac{343}{95.28} = 3.6 \; \mathrm{m} \).The smallest value of \( x \) (node position) is:\[x_1 = \frac{\lambda}{4} = \frac{3.6}{4} = 0.9 \; \mathrm{m}\]The second smallest value of \( x \) is:\[x_2 = \frac{3\lambda}{4} = \frac{3 \times 3.6}{4} = 2.7 \; \mathrm{m}\]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Harmonic Frequencies
Harmonic frequencies are essential to understanding how musical tones and sounds are produced in various objects, such as musical instruments or pipes. When we talk about harmonics, we refer to the integer multiples of a fundamental frequency. For example, in the case of pipes:
  • A pipe open at both ends supports harmonics at frequencies that are integer multiples (1st, 2nd, 3rd, etc.) of the fundamental frequency.
  • A pipe closed at one end supports only odd harmonics (1st, 3rd, 5th, etc.).
Let's make it clearer with an example. If a pipe open at both ends has a fundamental frequency (or first harmonic) of 100 Hz, the third harmonic in that pipe would be at 300 Hz (3 times 100 Hz). For a closed pipe, if its fundamental is 100 Hz too, you would find harmonics at 300 Hz and 500 Hz, but not at 200 Hz, because even-numbered harmonics are absent.
Speed of Sound
The speed of sound is a crucial factor in determining the frequency and wavelength of sound waves in air or other media. In air, standardized at room temperature, it is approximately 343 meters per second. This factor drives how quickly sound waves travel through the air, and it influences the pitches we hear.
In the context of pipes and tubes, the speed of sound helps us calculate frequencies as it functions in equations like this:
  • For a tube open at both ends: \[ f = \frac{nv}{2L} \]where \( n \) is the harmonic number, \( v \) is the speed of sound, and \( L \) is the length of the pipe.
  • For a tube closed at one end: \[ f = \frac{nv}{4L} \]allowing only odd values of \( n \).
Understanding the speed of sound in different mediums is vital, explaining why sounds are heard differently underwater, in solids, or in gases like helium compared to air.
Wavelength
Wavelength is the spatial period of a wave, determining the distance over which a wave's shape repeats. It is inversely related to frequency: higher frequencies have shorter wavelengths, and lower frequencies have longer wavelengths. In pipes, whether they are open or closed, the wavelength governs the standing wave pattern produced inside:
  • In a pipe open at both ends, the wavelength of the fundamental frequency is twice the length of the pipe: \( \lambda = 2L \).
  • In a pipe closed at one end, the fundamental wavelength is four times the length of the pipe: \( \lambda = 4L \).
For harmonics, intuitively, the wave must "fit" within the pipe properly. This concept manifests in determining nodes and antinodes along the pipe's length. In practical terms, if you know the speed of sound and frequency, you can find wavelength with the formula:\[ \lambda = \frac{v}{f} \]This equation allows us to measure or predict the wavelength from known values of speed and frequency.
Standing Waves
Standing waves are fascinating phenomena that occur when two waves of the same frequency and amplitude travel in opposite directions through the same medium. This setup results in a wave that appears to be "standing still," with points that do not move, known as nodes, and points that oscillate with maximum amplitude, known as antinodes.
In acoustics:
  • In a pipe open at both ends, nodes occur at intervals of half a wavelength and antinodes at the ends of the pipe.
  • In a pipe closed at one end, a node is at the closed end, and an antinode is at the open end, with additional nodes and antinodes forming based on the harmonic in question.
The concept of standing waves is crucial because it explains how instruments, like organ pipes, produce sound at specific pitches. It's all about the positioning of these nodes and antinodes, which result in the particular sounds we hear. Whether examining instruments or acoustics in architectural design, understanding standing waves lets us manipulate and harness sound to our needs.

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Most popular questions from this chapter

The pressure in a traveling sound wave is given by the equation $$ \Delta p=(2.00 \mathrm{~Pa}) \sin \pi\left[\left(0.900 \mathrm{~m}^{-1}\right) x-\left(450 \mathrm{~s}^{-1}\right) t\right] $$ Find the (a) pressure amplitude, (b) frequency, (c) wavelength, and (d) speed of the wave.

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