/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 32 Two sounds differ in sound level... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Two sounds differ in sound level by \(3.00 \mathrm{~dB}\). What is the ratio of the greater intensity to the smaller intensity?

Short Answer

Expert verified
The ratio of greater intensity to smaller intensity is 2:1.

Step by step solution

01

Understanding Decibel Difference

The decibel (dB) scale is a logarithmic scale used to measure sound intensity. A difference in sound level of 3.00 dB between two sounds means that the intensity ratio between the two sounds is given by the formula for difference in decibels: \[ ext{Difference in dB} = 10 imes ext{log}_{10} \,\left( \frac{I_1}{I_2} \right) \] where \(I_1\) is the greater intensity and \(I_2\) is the smaller intensity. Here, the difference is 3.00 dB.
02

Setting Up the Equation

Substituting the given 3.00 dB difference into the equation:\[ 3.00 = 10 imes \text{log}_{10} \,\left( \frac{I_1}{I_2} \right) \] Divide both sides by 10 to isolate the logarithm:\[ 0.30 = \text{log}_{10} \,\left( \frac{I_1}{I_2} \right) \]
03

Solving for Intensity Ratio

To solve for the intensity ratio \( \frac{I_1}{I_2} \), exponentiate both sides to eliminate the logarithm. This involves raising 10 to the power of each side:\[ 10^{0.30} = \frac{I_1}{I_2} \] Evaluate the expression on the left:\[ 10^{0.30} \approx 2.00 \] Thus, the ratio of the greater intensity to the smaller intensity is approximately \(2.00\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Decibel Scale
When we talk about the strength or intensity of sound, scientists and audiophiles alike often refer to the decibel scale. But what exactly is this? The decibel (dB) scale is a logarithmic scale used to quantify sound levels. It is particularly useful because the human ear perceives sound intensity in a logarithmic fashion; doubling the power of a sound does not double the perceived loudness. Instead, it slightly increases it. The decibel scale helps to express this change.

For example, a difference of 3 dB between two sounds indicates that one sound has twice the intensity of the other. This is crucial in audio engineering and various fields of physics where precision in sound measurement is needed. Remember, a higher number of decibels equals a louder sound.
Logarithmic Scale
A logarithmic scale is different from a typical linear scale. Instead of numbers increasing by addition, they increase by multiplication. This scale is extensively simplified using logarithms, a concept from mathematics.

In a logarithmic scale, each step represents a multiplication by a certain factor rather than just an addition. For example, on a base-10 logarithmic scale, each step up corresponds to a tenfold increase over the previous step. The base-10 logarithmic scale is commonly used for sound because it matches how we perceive sound changes: each 10 dB increase feels about twice as loud but represents ten times the power.

This non-linear approach offers a practical way to represent large ranges of values. This is why the decibel scale utilizes it, making it easier to work with values ranging from the quietest sounds humans can hear to the loudest they can tolerate without harm.
Intensity Measurement
Sound intensity measures the power per unit area where the sound is propagating. It's an important concept in understanding and comparing different sounds. When measuring intensity, the units are typically watts per square meter (W/m²).

The decibel system simplifies how we discuss intensity differences. Instead of working directly with raw intensity values, we convert them into decibels, simplifying complex comparisons. For example, when a sound increases in intensity by approximately 2.00 (like in the exercise above), this is a clear and easily understandable change, even though the actual numbers might not appear immediately graspable.

This conversion to decibels helps audiologists, engineers, and anyone interested in sound to effectively and efficiently communicate sound levels and their differences.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A sound wave of frequency \(280 \mathrm{~Hz}\) has an intensity of \(1.00 \mu \mathrm{W} / \mathrm{m}^{2} .\) What is the amplitude of the air oscillations caused by this wave?

The pressure in a traveling sound wave is given by the equation $$ \Delta p=(2.00 \mathrm{~Pa}) \sin \pi\left[\left(0.900 \mathrm{~m}^{-1}\right) x-\left(450 \mathrm{~s}^{-1}\right) t\right] $$ Find the (a) pressure amplitude, (b) frequency, (c) wavelength, and (d) speed of the wave.

A point source emits sound waves isotropically. The intensity of the waves \(6.00 \mathrm{~m}\) from the source is \(4.50 \times 10^{-4} \mathrm{~W} / \mathrm{m}^{2}\). Assuming that the energy of the waves is conserved, find the power of the source.

A plane flies at \(2.00\) times the speed of sound. Its sonic boom reaches a man on the ground \(35.4 \mathrm{~s}\) after the plane passes directly overhead. What is the altitude of the plane? Assume the speed of sound to be \(330 \mathrm{~m} / \mathrm{s}\).

A sound source \(A\) and a reflecting surface \(B\) move directly toward each other. Relative to the air, the speed of source \(A\) is \(20.0 \mathrm{~m} / \mathrm{s}\), the speed of surface \(B\) is \(80.0 \mathrm{~m} / \mathrm{s}\), and the speed of sound is \(329 \mathrm{~m} / \mathrm{s}\). The source emits waves at frequency \(2000 \mathrm{~Hz}\) as measured in the source frame. In the reflector frame, what are the (a) frequency and (b) wavelength of the arriving sound waves? In the source frame, what are the (c) frequency and (d) wavelength of the sound waves reflected back to the source?

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.