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Wind turbines and hydraulic turbines develop mechanical power from moving streams of air and water, respectively. In each case, what aspect of the stream is tapped for power?

Short Answer

Expert verified
Wind turbines use kinetic energy of air. Hydraulic turbines use both kinetic and potential energy of water.

Step by step solution

01

- Understand the Basics of Turbines

Begin by understanding that turbines convert the energy of a moving fluid into mechanical power. This fluid can either be air in the case of wind turbines or water in the case of hydraulic turbines.
02

- Identify the Energy Source for Wind Turbines

Wind turbines harness the kinetic energy of moving air. The blades of the wind turbine capture the energy from wind and convert it into mechanical power through rotation.
03

- Identify the Energy Source for Hydraulic Turbines

Hydraulic turbines, on the other hand, utilize the kinetic and potential (elevation) energy of moving or falling water. This mechanical power is generated by water flowing over the turbine blades.
04

- Compare the Energy Sources

Both types of turbines tap into the kinetic energy of moving fluids, but hydraulic turbines can also convert potential energy from the elevation of water.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

wind turbine power generation
Wind turbines are designed to convert the kinetic energy of the wind into mechanical power. This process involves the following steps:
The blades of the wind turbine catch the wind, and this causes them to rotate.
The rotation of the blades turns a rotor that is connected to a generator.
The generator then converts the mechanical energy from the rotor into electrical energy, which can be used to power homes and businesses.
Wind speed is crucial for this process. The amount of electricity generated is directly proportional to the cube of the wind speed, meaning that small increases in wind speed can lead to a substantial increase in power production. To maximize efficiency, wind turbines are often placed in locations with consistent and strong winds, such as coastal areas or open plains.
hydraulic turbine energy conversion
Hydraulic turbines work by converting the energy of moving water into mechanical power. There are two main types of energy converted in this process: kinetic energy and potential energy.
In rivers or streams, the kinetic energy of flowing water is used to turn the turbine blades.
In dams or reservoirs, the potential energy of water stored at a height is harnessed. When this water is released, it flows down and gains kinetic energy which is then used to turn the turbine blades.
The mechanical power produced by hydraulic turbines is then transferred to generators, which convert it into electrical energy.
This type of energy conversion is highly efficient and hydraulic turbines are a major source of renewable energy worldwide.
kinetic energy utilization
Kinetic energy is the energy of motion. Both wind and hydraulic turbines utilize kinetic energy to generate power, but the processes are slightly different:
Wind turbines harness the kinetic energy of moving air. The faster the wind, the more kinetic energy is available for conversion.
Hydraulic turbines use the kinetic energy of moving water. This can be from a natural river flow or water released from a dam.
In both cases, the natural movement of the fluid (air or water) is essential. The fluid's motion drives the rotation of the turbine blades, which in turn produces mechanical power.
Understanding how both systems utilize kinetic energy helps to appreciate the efficiency and effectiveness of these renewable energy sources.
potential energy in hydraulic systems
Potential energy is stored energy based on the position of an object. In hydraulic systems, potential energy primarily comes from water stored at a height in a dam or reservoir.
When the water is released, its stored potential energy is converted into kinetic energy as it flows downward.
This flowing water drives the turbine blades, converting the potential energy into mechanical power.
The beauty of potential energy in hydraulic systems is that it can be controlled and released as needed, making it a reliable source of energy.
By managing the water levels and flow rates, engineers can ensure a steady and controllable power output.

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Most popular questions from this chapter

Refrigerant 134 a enters an air-conditioner compressor at \(3.2\) bar, \(10^{\circ} \mathrm{C}\), and is compressed at steady state to 10 bar, \(70^{\circ} \mathrm{C}\). The volumetric flow rate of refrigerant entering is \(3.0 \mathrm{~m}^{3} / \mathrm{min}\). The power input to the compressor is \(55.2 \mathrm{~kJ}\) per \(\mathrm{kg}\) of refrigerant flowing. Neglecting kinetic and potential energy effects, determine the heat transfer rate, in \(\mathrm{kW}\).

Ammonia enters a control volume operating at steady state at \(p_{1}=14\) bar, \(T_{1}=28^{\circ} \mathrm{C}\), with a mass flow rate of \(0.5 \mathrm{~kg} / \mathrm{s}\). Saturated vapor at 4 bar leaves through one exit, with a volumetric flow rate of \(1.036 \mathrm{~m}^{3} / \mathrm{min}\), and saturated liquid at 4 bar leaves through a second exit. Determine (a) the minimum diameter of the inlet pipe, in \(\mathrm{cm}\), so the ammonia velocity does not exceed \(20 \mathrm{~m} / \mathrm{s}\). (b) the volumetric flow rate of the second exit stream, in \(\mathrm{m}^{3} / \mathrm{min} .\)

Propane vapor enters a valve at \(1.6 \mathrm{MPa}, 70^{\circ} \mathrm{C}\), and leaves at \(0.5 \mathrm{MPa}\). If the propane undergoes a throttling process, what is the temperature of the propane leaving the valve, in \({ }^{\circ} \mathrm{C} ?\)

By introducing enthalpy \(h\) to replace each of the \((u+p v)\) terms of Eq. 4.13, we get Eq. 4.14. An even simpler algebraic form would result by replacingeach of the \(\left(u+p v+\mathrm{V}^{2} / 2+g z\right)\) terms by a single symbol, yet we have not done so. Why not?

Steam at \(11032 \mathrm{kPa}, 538^{\circ} \mathrm{C}\), and a velocity of \(0.6 \mathrm{~m} / \mathrm{s}\) enters a turbine operating at steady state. As shown in Fig. P4.43, \(22 \%\) of the entering mass flow is extracted at \(1103 \mathrm{kPa}, 232^{\circ} \mathrm{C}\), with a velocity of \(3 \mathrm{~m} / \mathrm{s}\). The rest of the steam exits as a two-phase liquid-vapor mixture at \(7 \mathrm{kPa}\), with a quality of \(85 \%\) and a velocity of \(45 \mathrm{~m} / \mathrm{s}\). The turbine develops a power output of \(2.6 \times 10^{5} \mathrm{~kW}\). Neglecting potential energy effects and heat transfer between the turbine and its surroundings, determine (a) the mass flow rate of the steam entering the turbine, in \(\mathrm{kg} / \mathrm{h}\). (b) the diameter of the extraction duct, in \(\mathrm{m}\).

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