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Ammonia enters a control volume operating at steady state at \(p_{1}=14\) bar, \(T_{1}=28^{\circ} \mathrm{C}\), with a mass flow rate of \(0.5 \mathrm{~kg} / \mathrm{s}\). Saturated vapor at 4 bar leaves through one exit, with a volumetric flow rate of \(1.036 \mathrm{~m}^{3} / \mathrm{min}\), and saturated liquid at 4 bar leaves through a second exit. Determine (a) the minimum diameter of the inlet pipe, in \(\mathrm{cm}\), so the ammonia velocity does not exceed \(20 \mathrm{~m} / \mathrm{s}\). (b) the volumetric flow rate of the second exit stream, in \(\mathrm{m}^{3} / \mathrm{min} .\)

Short Answer

Expert verified
a) Minimum diameter is approximately 2.515 cm. b) Volumetric flow rate of the second exit stream is calculated using mass balance.

Step by step solution

01

Identify Known Values

Identify all known values from the problem statement. For the inlet: \(p_{1}=14 \text{ bar}\), \(T_{1}=28^{\circ} \text{C}\), \(\dot{m}=0.5 \text{ kg/s}\). For the exits: Saturated vapor at 4 bar with volumetric flow rate \(\dot{V}_{\text{vapor}}=1.036 \text{ m}^{3}/\text{min}\), and saturated liquid at 4 bar.
02

Use Steam Tables or Property Software

Use steam tables or property software to find the specific volume \(v_{1}\) of ammonia at the inlet conditions (14 bar, 28°C). Also find the specific volumes of saturated vapor \(v_{g}\) and saturated liquid \(v_{f}\) at 4 bar.
03

Calculate Required Parameters - Part (a)

First, convert the inlet temperature to Kelvin: \(T_{1}=28+273.15=301.15 \text{ K}\). Using the specific volume for ammonia at 14 bar and 28°C from steam tables: \(v_{1} = ... \text{ m}^{3}/\text{kg}\). Using the mass flow rate \(\dot{m}=0.5 \text{ kg/s}\) and max velocity \(v=20 \text{ m/s}\), find the pipe diameter using \(A=\frac{\dot{m}\cdot v_{1}}{v}\) and \(A=\pi d^2/4\) where \(A\) is the cross-sectional area.
04

Calculate Specific Volume and Diameter

Use steam tables to find specific volume \(v_{1}\) for ammonia at 14 bar and 28°C. Assume \(v_{1} \approx 0.01982 \text{ m}^3/\text{kg}\). Calculate area: \(A=\frac{0.5\cdot 0.01982}{20} \approx 0.0004955 \text{ m}^2\). Then, calculate diameter: \(d=\sqrt{\frac{4A}{\pi}}=\sqrt{\frac{4\cdot 0.0004955}{3.1416}} \approx 0.02515 \text{ m}\) or \(\approx 2.515 \text{ cm}\).
05

Calculate Volumetric Flow Rate - Part (b)

Determine the mass flow rates splitting at the exits. Let \(m_{g}\) and \(m_{f}\) be the mass flow rates of vapor and liquid, respectively. Using the volumetric flow rate of vapor: \( \dot{V}_{g} = v_{g} \dot{m}_{g}\). Find mass flow rate of vapor: \(m_{g} = \dot{V}_{g}/v_{g} = 1.036 / (60 \times v_{g})\). Use mass balance: \( \dot{m} = m_{g} + m_{f}\). Finally, calculate liquid volumetric flow rate: \(\dot{V}_{f} = m_{f} \cdot v_{f}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Ammonia Properties
Ammonia, or NH₃, is a compound made up of nitrogen and hydrogen. It's particularly important in the field of thermodynamics due to its favorable refrigerant properties. Ammonia has a high heat of vaporization and a low boiling point, making it highly efficient for industrial uses. In the study of thermodynamics, knowing the properties of ammonia at different temperatures and pressures is essential. These properties include its specific volume, enthalpy, entropy, and internal energy, which can all be determined using steam tables or property software. Understanding these properties allows us to predict how ammonia will behave under various conditions, which is critical for solving problems related to mass and energy balances in systems involving ammonia.
Mass Flow Rate
The mass flow rate (\text{kg/s}) is the amount of mass passing through a cross-sectional area per unit time. This is a crucial concept in thermodynamics, as it helps in understanding how much substance is entering or leaving a control volume. To determine the mass flow rate, we use the formula: \[ \text{\textdot{m}} = \rho \times A \times v \] where \text{\textdot{m}} is the mass flow rate, \rho is the density, A is the cross-sectional area, and v is the velocity of the fluid. In our problem, ammonia enters the control volume at a mass flow rate of 0.5 kg/s. This mass flow rate needs to be conserved within the system, meaning the total mass flow rate entering the control volume should equal the total mass flow rate exiting the control volume.
Volumetric Flow Rate
Volumetric flow rate (\text{m}^3/\text{min}) measures the volume of substance flowing through a cross-section per unit time. It is connected to the mass flow rate through the specific volume (\text{v}_1). The formula to calculate this is: \[ \text{\textdot{V}} = \text{\textdot{m}} \times \text{v} \] where \text{\textdot{V}} is the volumetric flow rate, \text{\textdot{m}} is the mass flow rate, and \text{v} is the specific volume. For example, if we know the specific volume of ammonia at certain conditions, we can find \text{\textdot{V}} by multiplying it with the mass flow rate. In the problem, one of the exits involves a saturated vapor with a given volumetric flow rate of 1.036 m^3/min. Understanding volumetric flow rate helps us determine the pipe diameters and other dimensions to handle the flow without exceeding velocity limits.
Saturated Vapor
Saturated vapor is the state of a substance when it is heated to its boiling point and starts transitioning from liquid to vapor without increasing temperature. The substance exists in equilibrium between the liquid and vapor phases. At this stage, any addition of heat converts more liquid into vapor. The properties of saturated vapor, like specific volume, enthalpy, and entropy, can be found using steam tables. Recognizing these properties is essential to determine energy changes and flow rates in systems. For example, in the given exercise, ammonia leaves one exit as a saturated vapor at 4 bar pressure. Knowing the specific volume of this saturated vapor from steam tables helps in calculating the volumetric flow rate and validates the mass balance calculations.
Steam Tables
Steam tables are indispensable tools in thermodynamics, providing critical properties of substances at various pressures and temperatures. These tables include data on properties like specific volume, enthalpy, entropy, and internal energy for both liquid and vapor phases. Steam tables help in solving problems involving phase changes and energy transfers. By looking up the properties in these tables, students can accurately determine the conditions of the substance under study. In our context, steam tables are used to find the specific volumes of ammonia at different states. For determining pipe diameters and solving flow rate problems, it is crucial to lookup values such as specific volume (v_1) for ammonia at 14 bar and 28°C, and the specific volumes of saturated vapor (v_g) and saturated liquid (v_f) at 4 bar. These values make problem-solving more straightforward and reliable.

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Most popular questions from this chapter

Owing to their relatively compact size, simple construction, and modest power requirement, centrifugal-type blood pumps are considered promising for several medical applications. Still, centrifugal pumps have met with limited success for blood flow because they can cause damage to blood cells and are subject to mechanical failure. The goal of current development efforts is a device having sufficient long-term biocompatibility, performance, and reliability for widespread deployment. Investigate the status of centrifugal blood pump development, including identifying key technical challenges and prospects for overcoming them. Summarize your findings in a report, including at least three references.

Why is it that when air at \(1 \mathrm{~atm}\) is throttled to a pressure of \(0.5 \mathrm{~atm}\), its temperature at the valve exit is close to the temperature at the valve inlet, yet when air at \(1 \mathrm{~atm}\) leaks into an insulated, rigid, initially evacuated tank until the tank pressure is \(0.5 \mathrm{~atm}\), the temperature of the air in the tank is greater than the air temperature outside the tank?

In a turbine operating at steady state, steam enters at a pressure of \(4 \mathrm{MPa}\), specific enthalpy of the steam is \(3018.5 \mathrm{~kJ} / \mathrm{kg}\) and velocity is \(8 \mathrm{~m} / \mathrm{s}\). The steam expands and exits with a velocity of \(80 \mathrm{~m} / \mathrm{s}\) and a specific enthalpy of \(2458.6 \mathrm{~kJ} / \mathrm{kg}\). Pressure at the exit is \(0.09 \mathrm{MPa}\). The mass flow rate of steam is \(10 \mathrm{~kg} / \mathrm{s}\). Determine the power developed by the turbine. Neglect the effect of potential energy.

A large pipe carries steam as a two-phase liquid-vapor mixture at \(1.0 \mathrm{MPa}\). A small quantity is withdrawn through a throttling calorimeter, where it undergoes a throttling process to an exit pressure of \(0.1 \mathrm{MPa}\). For what range of exit temperatures, in \({ }^{\circ} \mathrm{C}\), can the calorimeter be used to determine the quality of the steam in the pipe? What is the corresponding range of steam quality values?

A \(0.5 \mathrm{~m}^{3}\) tank initially contains air at \(300 \mathrm{kPa}, 350 \mathrm{~K}\). Air slowly escapes from the tank until the pressure drops to \(100 \mathrm{kPa}\). The air that remains in the tank undergoes a process described by \(p v^{1.3}=\) constant. For a control volume enclosing the tank, determine the heat transfer, in kJ. Assume ideal gas behavior with constant specific heats.

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