91Ó°ÊÓ

The constant volume process may be defined as the thermodynamic process in which the system's volume stays constant and pressure changes accordingly.

Given data:

The heat flows out of the system is \(Q = - 465\;{\rm{kJ}}\).

(a)

Since the walls of the container are rigid, therefore, there will be no change in the volume. That is \(\Delta V = 0\).

The work done during this process can be calculated as:

\(\begin{aligned}{c}W &= P\Delta V\\W &= P\left( 0 \right)\\W &= 0\end{aligned}\)

Thus, the work done during this process is \(0\).

(b)

The change in internal energy of the gas during this process can be calculated as:

\(\begin{aligned}{c}\Delta U &= Q - W\\\Delta U &= \left( { - 465\;{\rm{kJ}}} \right) - 0\\\Delta U &= - 465\;{\rm{kJ}}\end{aligned}\)

Thus, the change in internal energy of the gas during this process is \( - 465\;{\rm{kJ}}\).