91Ó°ÊÓ

The efficiency of the Carnot engine is dependent on two temperatures, namely the temperatures of the hot source and the cold sink.

It is the ratio of the difference between both temperatures to the hot reservoir temperature.

The given data can be listed below as:

• Theefficiency of the Carnot engine is\(e = 34\% \left( {\frac{1}{{100}}} \right) = 0.34\).
• The temperature of the cold reservoir is \({T_{\rm{L}}} = 230^\circ {\rm{C}} = \left( {230^\circ {\rm{C}} + 273} \right){\rm{ K}} = 503{\rm{ K}}\).

The efficiency of the Carnot engine can be expressed as:

\(\begin{aligned}{c}e &= \left( {1 - \frac{{{T_{\rm{L}}}}}{{{T_{\rm{H}}}}}} \right)\\\frac{{{T_{\rm{L}}}}}{{{T_{\rm{H}}}}} &= 1 - e\\{T_{\rm{H}}} &= \frac{{{T_{\rm{L}}}}}{{\left( {1 - e} \right)}}\end{aligned}\)

Substitute the values in the above equation.

\(\begin{aligned}{c}{T_{\rm{H}}} &= \frac{{503{\rm{ K}}}}{{\left( {1 - 0.34} \right)}}\\ &= 762.12{\rm{ K}}\\ &= \left( {762.12{\rm{ K}} - {\rm{273}}} \right)^\circ {\rm{C}}\\ &= 489.12^\circ {\rm{C}}\end{aligned}\)

Thus, the high temperature of the Carnot engine is \(489.12^\circ {\rm{C}}\).