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Question:The first law of thermodynamics is sometimes whimsically stated as, 鈥淵ou can鈥檛 get something for nothing,鈥 and the second law as, 鈥淵ou can鈥檛 even break even.鈥 Explain how these statements could be equivalent to the formal statements.

Short Answer

Expert verified

The statement 鈥淵ou can鈥檛 get something for nothing鈥 implies that energy is conserved. The other statement, 鈥淵ou can鈥檛 even break even,鈥 tells us that it is impossible to have a 100% effective heat engine.

Step by step solution

01

Understanding the second law of thermodynamics 

From the second law of thermodynamics, it can be obtained that there is no such heat engine that gives 100 percent efficiency without any losses or limitations.

02

Explanation of the statement “You can’t get something for nothing” in terms of the first law of thermodynamics

The statement 鈥淵ou can鈥檛 get something for nothing鈥 correlates to the first law of thermodynamics because it could be a way of saying that energy is conserved.

The work performed by a specific system does require heat from an outside source or its internal energy. So, to obtain work done, something is applied by the system.

Thus, it is equivalent to the formal statement of the first law of thermodynamics.

03

Explanation of the statement “You can’t even break even” in terms of the second law of thermodynamics

The statement, 鈥淵ou can鈥檛 even break even,鈥 relates to the second law of thermodynamics because it indicates that a certain heat engine cannot produce 100 percent efficiency.

For example, if the engine takes heat through the input, it is impractical to give an exact amount of energy at the output because some energy will be lost.

Thus, it is equivalent to the formal statement of the second law of thermodynamics.

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Most popular questions from this chapter

Question:(II) A four-cylinder gasoline engine has an efficiency of 0.22 and delivers 180 J of work per cycle per cylinder. If the engine runs at 25 cycles per second (1500 rpm), determine (a) the work done per second, and (b) the total heat input per second from the gasoline. (c) If the energy content of gasoline is 130 MJ per gallon, how long does one gallon last?

A particular car does work at the rate of about\({\bf{7}}{\bf{.0}}\;{\bf{kJ/s}}\)when traveling at a steady\({\bf{21}}{\bf{.8}}\;{\bf{m/s}}\)along a level road. This is the work done against friction. The car can travel 17 km on 1.0 L of gasoline at this speed (about 40 mi/gal). What is the minimum value for\({{\bf{T}}_{\bf{H}}}\)if\({{\bf{T}}_{\bf{L}}}\)is 25掳C? The energy available from 1.0 L of gas is\({\bf{3}}{\bf{.2 \times 1}}{{\bf{0}}{\bf{7}}}\;{\bf{J}}\).

Question:(I) What is the maximum efficiency of a heat engine whose operating temperatures are 560掳C and 345掳C?

Question:(II) Which will improve the efficiency of a Carnot engine more: a 10 掳C increase in the high-temperature reservoir, or a 10 掳C decrease in the low temperature reservoir? Give detailed results. Can you state a generalization?

(III) A bowl contains many red, orange, and green jelly beans, in equal numbers. You are to make a line of 3 jelly beans by randomly taking 3 beans from the bowl.

(a) Construct a table showing the number of microstates that correspond to each macrostate. Then determine the probability of

(b) all 3 beans red, and

(c) 2 greens, 1 orange.

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