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Question: (I) A piano tuner hears one beat every 2.0 s when trying to adjust two strings, one of which is sounding 350 Hz. How far off in frequency is the other string?

Short Answer

Expert verified

The far-off in frequency from the other string is \( \pm 0.5\;{\rm{Hz}}\).

Step by step solution

01

Determination of the frequency

The frequency gap of the other string from the first string can be obtained by taking the inverse of time occupied by a single beat.

02

Given information

Given data:

The time occupied by a single beat is \(t = 2.0\;{\rm{s}}\).

The frequency of a single beat is \(f = 350\;{\rm{Hz}}\).

03

Evaluation of the frequency gap

The frequency gap of the other string from the first string can be calculated below,

\(\begin{array}{c}f = \frac{1}{{2.0\;{\rm{s}}}}\\f = \pm 0.5\;{\rm{Hz}}\end{array}\)

Thus, the other frequency is \( \pm 0.5\;{\rm{Hz}}\) far off in frequency.

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