/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q26P Question: (I) What would you est... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Question: (I) What would you estimate for the length of a bass clarinet, assuming that it is modeled as a closed tube and that the lowest note that it can play is a \({{\bf{D}}^{\rm{b}}}\) whose frequency is 69 Hz?

Short Answer

Expert verified

The length of the bass clarinet is \(1.25{\rm{ m}}\).

Step by step solution

01

Step-1:-Length of a closed tube

In this problem, the relation of length in the case of the closed tube will be equivalent to one-fourth of the wavelength.

02

Step-2:-Given data

The frequency of the clarinet is \({f_1} = 69{\rm{ Hz}}\).

The speed of sound at room temperature is \(\nu = 346{\rm{ m/s}}\).

03

Step-3:-Calculation of length of clarinet

The length of the bass clarinet is calculated as:

\(l = \frac{\nu }{{4{f_1}}}\)

Substitute the values in the above relation.

\(\begin{array}{c}l = \frac{{346{\rm{ m/s}}}}{{4 \times 69{\rm{ Hz}}}}\\l = 1.25{\rm{ m}}\end{array}\)

Thus, the length of the clarinet is \(1.25{\rm{ m}}\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Study anywhere. Anytime. Across all devices.