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Chapter 11: 11-48P (page 292)

The two pulses shown in Fig. 11鈥�54 are moving toward each other. (a) Sketch the shape of the string at the moment they directly overlap. (b) Sketch the shape of the string a few moments later. (c) In Fig.11鈥�37a, at the moment the pulses pass each other, the string is straight. What has happened to the energy at this moment?

Short Answer

Expert verified

(a)

(b)

(c)

At this moment, the elastic potential energy would be zero because displacement is zero, and only kinetic energy exists.

Step by step solution

01

Understanding about the interference

Whenever two different waves pass through the same region of space at the same time refers as interference.The value of amplitudes of both waves would be added together to give the result as the final amplitude of the resultant wave.

02

Identification of given figure

From the mentioned figure, the two waves have the same magnitude, but the direction is opposite, so both waves will meet and pass right by each other. The meeting point of both waves refers to overlap.

03

Sketch the shape of the string when they directly overlap

(a) Theshape of the string at the moment they directly overlap is given as,

04

Sketch the shape of the string a few moments latter

(b) Theshape of the string after a few moments where two pulse directly overlap is given as,

05

Determining the energy at the moment the pulses pass each other

(c) Whenever the two wave pulses pass each other, then the total energy would be in the form of kinetic energy, and at this moment, the displacement in the string would be equal to zero.

So, at this moment, the elastic potential energy would be zero because displacement is zero, and there would be only kinetic energy exists.

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Most popular questions from this chapter

Carbon dioxide is a linear molecule. The carbon鈥搊xygen bonds in this molecule act very much like springs. Figure 11鈥�58 shows one possible way the oxygen atoms in this molecule can oscillate: the oxygen atoms oscillate symmetrically in and out, while the central carbon atom remains at rest. Hence each oxygen atom acts like a simple harmonic oscillator with a mass equal to the mass of an oxygen atom. It is observed that this oscillation occurs at a frequency \(f{\bf{ = 2}}{\bf{.83 \times 1}}{{\bf{0}}^{{\bf{13}}}}\;{\bf{Hz}}\). What is the spring constant of the C-O bond?

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