/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} 11-47P Two earthquake waves of the same... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Two earthquake waves of the same frequency travel through the same portion of the Earth, but one is carrying 5.0 times the energy. What is the ratio of the amplitudes of the two waves?

Short Answer

Expert verified

The ratio of the amplitudes of the two waves is \(\sqrt 5 \).

Step by step solution

01

Understanding about the kinetic energy

The term kinetic energy is described as the form of an energy that exists due to the motion of an object.If the object is not moving means the velocity is equal to zero then the value of kinetic energy of the object would be zero.

02

Identification of given data

The given data can be listed below as,

  • The energy of one wave is \({E_1} = 5{E_2}\).
03

Defining the expression of kinetic energy of a wave

The expression of the kinetic energy of the wave is given by,

\(E = \frac{1}{2}k{A^2}\)

Here,\(E\)is the total mechanical energy of the wave,\(A\)is the amplitude and\(k\)is wave number.

04

Determining the ratio of the amplitudes of the two waves

From the above equation, kinetic energy is directly proportional to the square of the amplitude. Hence,

\(\frac{{{E_1}}}{{{E_2}}} = {\left( {\frac{{{A_1}}}{{{A_2}}}} \right)^2}\)

Here, \(\left( {\frac{{{A_1}}}{{{A_2}}}} \right)\) is the ratio of the amplitudes of the two waves.

Substitute all the known values in the above equation.

\(\begin{aligned}{c}\frac{{5{E_2}}}{{{E_2}}} &= {\left( {\frac{{{A_1}}}{{{A_2}}}} \right)^2}\\5 &= {\left( {\frac{{{A_1}}}{{{A_2}}}} \right)^2}\\\frac{{{A_1}}}{{{A_2}}} &= \sqrt 5 \end{aligned}\)

So, the ratio of the amplitudes of the two waves is \(\sqrt 5 \).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

An object with mass 2.7 kg is executing simple harmonic motion, attached to a spring with spring constant k =310 N/m.When the object is 0.020 m from its equilibrium position, it is moving with a speed of 0.55 m/s. (a) Calculate the amplitude of the motion. (b) Calculate the maximum speed attained by the object.

A 62 kg person jumps from a window to a fire net 20.0 m directly below, which stretches the net 1.4 m. Assume that the net behaves like a simple spring. (a) Calculate how much it would stretch if the same person were lying in it. (b) How much would it stretch if the person jumped from 38 m?

A clock pendulum oscillates at a frequency of 2.5 Hz. At t= 0, it is released from rest starting at an angle of\(12^\circ \)to the vertical. Ignoring friction, what will be the position (angle in radians) of the pendulum at (a)t= 0.25 s, (b) t = 1.60 s, and (c) t = 500 s?

(III) Consider two objects, A and B, both undergoing SHM, but with different frequencies, as described by the equations \({{\bf{x}}_{\bf{A}}}{\bf{ = }}\left( {{\bf{2}}{\bf{.0}}\;{\bf{m}}} \right){\bf{sin(4}}{\bf{.0t)}}\) and \({{\bf{x}}_{\bf{B}}}{\bf{ = }}\left( {{\bf{5}}{\bf{.0}}\;{\bf{m}}} \right){\bf{sin(3}}{\bf{.0t)}}\), where t is in seconds. After t = 0, find the next three times t at which both objects simultaneously pass through the origin.

A standard baseball has a circumference of approximately 23 cm. If a baseball had the same mass per unit volume (see Tables in section 1–5) as a neutron or a proton, about what would its mass be?

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.