/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q23P (II) What fraction of iron will ... [FREE SOLUTION] | 91影视

91影视

(II) What fraction of iron will be submerged when it floats in mercury?

Short Answer

Expert verified

The fraction of iron in mercury is 0.57.

Step by step solution

01

Understanding the floatation of a solid

For equilibrium, during floatation, the weight of the substance will be equal to the buoyant force of the fluid.

02

Calculation the fraction of the iron

The buoyant force due to the Vin part of the iron inside mercury is,

FB = Vin蚁驳

Here, 蟻f = 13.6 x 103 kg/m3 is the density of the mercury, and g is the gravitational acceleration.

The weight of iron of volume V is,

W = V蟻sg

Here, 蟻s = 7.8 x 103 Kg/m3 is the density of the iron.

Equate these two forces for equilibrium and get,

Substitute the given values and get,

Hence, the submerged fraction of iron is 0.57.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

You need to siphon water from a clogged sink. The sink has an area of and is filled to a height of 4.0 cm. Your siphon tube rises 45 cm above the bottom of the sink and then descends 85 cm to a pail as shown in Fig. 10鈥59. The siphon tube has a diameter of 2.3 cm. (a) Assuming that the water level in the sink has almost zero velocity, use Bernoulli鈥檚 equation to estimate the water velocity when it enters the pail. (b) Estimate how long it will take to empty the sink. Ignore viscosity.

Water at a gauge pressure of \({\bf{3}}{\bf{.8}}\;{\bf{atm}}\) at street level flows into an office building at a speed of \({\bf{0}}{\bf{.78}}\;{\bf{m/s}}\) through a pipe \({\bf{5}}{\bf{.0}}\;{\bf{cm}}\)in diameter. The pipe tapers down to \({\bf{2}}{\bf{.8}}\;{\bf{cm}}\) in diameter by the top floor, \({\bf{16}}\;{\bf{m}}\) above (Fig. 10鈥53), where the faucet has been left open. Calculate the flow velocity and the gauge pressure in the pipe on the top floor. Assume no branch pipes and ignore viscosity.

Figure 10-53

(II) A house at the bottom of a hill is fed by a full tank of water 6.0 m deep and connected to the house by a pipe that is 75 m long at an angle of 61掳 from the horizontal (Fig. 10鈥49). (a) Determine the water gauge pressure at the house. (b) How high could the water shoot if it came vertically out of a broken pipe in front of the house?

A hurricane-force wind of \({\bf{180}}\;{\bf{km/h}}\) blows across the face of a storefront window. Estimate the force on \({\bf{2}}{\bf{.0}}\;{\bf{m \times 3}}{\bf{.0}}\;{\bf{m}}\) the window due to the difference in air pressure inside and outside the window. Assume the store is airtight so the inside pressure remains at 1.0 atm. (This is why you should not tightly seal a building in preparation for a hurricane.)

What diameter must a \({\bf{15}}{\bf{.5}}\;{\bf{m}}\)-long air duct have if the ventilation and heating system is to replenish the air in a \({\bf{8}}{\bf{.0}}\;{\bf{m \times 14}}{\bf{.0}}\;{\bf{m \times 4}}{\bf{.0}}\;{\bf{m}}\) room every \({\bf{15}}{\bf{.0}}\;{\bf{min}}\)? Assume the pump can exert a gauge pressure of \({\bf{0}}{\bf{.710 \times 1}}{{\bf{0}}^{\bf{3}}}\;{\bf{atm}}\).

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.