Chapter 17: Q60P (page 473)
Question: (I) Write the binary number 01010101 as a decimal number.
Short Answer
The decimal equivalent of 01010101 is 85.
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Chapter 17: Q60P (page 473)
Question: (I) Write the binary number 01010101 as a decimal number.
The decimal equivalent of 01010101 is 85.
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A proton \(\left( {{\bf{Q = + e}}} \right)\) and an electron \(\left( {{\bf{Q = - e}}} \right)\) are in a constant electric field created by oppositely charged plates. You release the proton from near the positive plate and the electron from near the negative plate. Which feels the larger electric force?
(a) The proton.
(b) The electron.
(c) Neither—there is no force.
(d) The magnitude of the force is the same for both and in the same direction.
(e) The magnitude of the force is the same for both but in opposite directions.
We have seen that the capacitance C depends on the size and position of the two conductors, as well as on the dielectric constant K. What then did we mean when we said that C is a constant in Eq. 17–7?
(II) Two point charges, \({\bf{3}}{\bf{.0}}\;{\bf{\mu C}}\) and \({\bf{ - 2}}{\bf{.0}}\;{\bf{\mu C}}\) are placed 4.0 cm apart on the x axis. At what points along the x axis is (a) the electric field zero and (b) the potential zero?
(II) Point a is 62 cm north of a \( - {\bf{3}}{\bf{.8}}\;{\bf{\mu C}}\) point charge, and point b is 88 cm west of the charge (Fig. 17–40). Determine (a) \({{\bf{V}}_{\bf{b}}} - {{\bf{V}}_{\bf{a}}}\) and (b) \({{\bf{\vec E}}_{\bf{b}}} - {{\bf{\vec E}}_{\bf{a}}}\) (magnitude and direction).

FIGURE 17–40 Problem 27.
Is there a point along the line joining two equal positive charges where the electric field is zero? Where the electric potential is zero? Explain.
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