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A proton \(\left( {{\bf{Q = + e}}} \right)\) and an electron \(\left( {{\bf{Q = - e}}} \right)\) are in a constant electric field created by oppositely charged plates. You release the proton from near the positive plate and the electron from near the negative plate. Which feels the larger electric force?

(a) The proton.

(b) The electron.

(c) Neither鈥攖here is no force.

(d) The magnitude of the force is the same for both and in the same direction.

(e) The magnitude of the force is the same for both but in opposite directions.

Short Answer

Expert verified

The correct answer is option (e) The magnitude of the force is the same for both but in opposite directions.

Step by step solution

01

Understanding the electric force

One of the major misconceptions is that an electron will have greater electric force because it experiences higher acceleration. However, the electric force relies on the electric field as well as the charge.

02

Evaluation of the magnitude of the force

The relation of electric force is given by,

\(F = QE\)

Here, Qis the charge and Eis the electric field.

The magnitude of charge for both electron and proton is the same, but they have opposite signs. Since the particles are in the same electric field, the magnitude of electric force will be equal on both particles, and only the direction is opposite.

Thus, the correct option is (e).

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Most popular questions from this chapter

Question: (I) Write the decimal number 116 in binary.

Question66:(III) In a given CRT, electrons are accelerated horizontally by 9.0 kV. They then pass through a uniform electric field E for a distance of 2.8 cm, which deflects them upward so they travel 22 cm to the top of the screen, 11 cm above the center. Estimate the value of E.

(II) If a capacitor has opposite \({\bf{4}}{\bf{.2}}\;{\bf{\mu C}}\) charges on the plates, and an electric field of \({\bf{2}}{\bf{.0}}\;{\bf{kV/mm}}\) is desired between the plates, what must each plate鈥檚 area be?

A parallel-plate capacitor with plate area\({\bf{A = 2}}{\bf{.0}}\;{{\bf{m}}{\bf{2}}}\)and plate separation\({\bf{d = 3}}{\bf{.0}}\;{\bf{mm}}\)is connected to a 35-V battery (Fig. 17鈥51a).

(a) Determine the charge on the capacitor, the electric field, the capacitance, and the energy stored in the capacitor.

(b) With the capacitor still connected to the battery, a slab of plastic with dielectric strength K =3.2 is placed between the plates of the capacitor, so that the gap is completely filled with the dielectric (Fig. 17鈥51b). What are the new values of charge, electric field, capacitance, and the energy stored in the capacitor?\(\left( {{\bf{1}}\;{\bf{byte = 8}}\;{\bf{bits}}{\bf{.}}} \right)\)

FIGURE 17-51 Problem 96

In the dynamic random access memory (DRAM) of a computer, each memory cell contains a capacitor for charge storage. Each of these cells represents a single binary bit value of 鈥1鈥 when its 35-fF capacitor \(\left( {{\bf{1}}\;{\bf{fF = 1}}{{\bf{0}}^{{\bf{ - 15}}}}\;{\bf{F}}} \right)\) is charged at 1.5 V, or 鈥0鈥 when uncharged at 0 V.

(a) When fully charged, how many excess electrons are on a cell capacitor鈥檚 negative plate?

(b) After charge has been placed on a cell capacitor鈥檚 plate, it slowly 鈥渓eaks鈥 off at a rate of about \({\bf{0}}{\bf{.30}}\;{\bf{fC/s}}\). How long does it take for the potential difference across this capacitor to decrease by 2.0% from its fully charged value? (Because of this leakage effect, the charge on a DRAM capacitor is 鈥渞efreshed鈥 many times per second.) Note: A DRAM cell is shown in Fig. 21鈥29.

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