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The balloon in Fig. 16鈥48 was rubbed on a student鈥檚 hair. Explain why the water drip curves instead of falling vertically.

Short Answer

Expert verified

The water drip curves instead of falling vertically due to the electrostatic force of attraction between the charged balloon and the charge of opposite polarity induced on the stream of water.

Step by step solution

01

Understanding charging by induction

When a charged object induces a charge on another uncharged object without actually coming in contact with it, the process is termed as charging by induction. The charges developed on the uncharged body are known as induced charges.

02

Explanation for curving of water drip

When the balloon is rubbed on the student鈥檚 hair, it gets charged due to rubbing. When this charged balloon is brought near the water drip, the charges get induced in the water stream. Consequently, the charges of the water that has a polarity opposite to that on the balloon start moving to the face of the water stream, which is closer to the balloon due to the electrostatic force of attraction between the charges.

The charges that are accumulated on the closer face of the water stream cannot move out of it. As a result of the accumulation of charges of opposite polarity on the closer face of the water stream, it gets attracted toward the balloon. It thus follows a curved path instead of falling vertically.

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Most popular questions from this chapter

A point charge \(\left( {m = 1.0 gram} \right)\) at the end of an insulating cord of length 55 cm is observed to be in equilibrium in a uniform horizontal electric field of \(9500 N/C\), when the pendulum鈥檚 position is as shown in Fig. 16鈥66, with the charge 12 cm above the lowest (vertical) position. If the field points to the right in Fig. 16鈥66, determine the magnitude and sign of the point charge.

FIGURE 16鈥66 Problem 57.

Two small, identical conducting spheres A and B are a distance Rapart; each carries the same charge Q. (a) What is the force sphere B exerts on sphere A? (b) An identical sphere with zero charge, sphere C, makes contact with sphere B and is then moved very far away. What is the net force now acting on sphere A? (c) Sphere C is brought back and now makes contact with sphere A and is then moved far away. What is the force on sphere A in this third case?

Figure 16鈥50 shows electric field lines due to a point charge. What can you say about the field at point 1 compared with the field at point 2?

(a) The field at point 2 is larger, because point 2 is on a field line.

(b) The field at point 1 is larger, because point 1 is not on a field line.

(c) The field at point 1 is zero, because point 1 is not on a field line.

(d) The field at point 1 is larger, because the field lines are closer together in that region.

(II) Three positive particles of equal charge, are located at the corners of an equilateral triangle of side 15.0 cm (Fig. 16鈥53). Calculate the magnitude and direction of the net force on each particle due to the other two.

(II) A large electroscope is made with 鈥渓eaves鈥 that are 78-cm-long wires with tiny 21-g spheres at the ends. When charged, nearly all the charge resides on the spheres. If the wires each make a 26掳 angle with the vertical (Fig. 16鈥55), what total charge Q must have been applied to the electroscope? Ignore the mass of the wires.

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