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Figure 16–50 shows electric field lines due to a point charge. What can you say about the field at point 1 compared with the field at point 2?

(a) The field at point 2 is larger, because point 2 is on a field line.

(b) The field at point 1 is larger, because point 1 is not on a field line.

(c) The field at point 1 is zero, because point 1 is not on a field line.

(d) The field at point 1 is larger, because the field lines are closer together in that region.

Short Answer

Expert verified

The correct answer is option (d) The field at point 1 is larger because the field lines are closer together in that region.

Step by step solution

01

Understanding the electric field lines

The electric field lines indicate the direction of the electric field. The magnitude of the electric field depends on the density of field lines. More density of field lines indicates the stronger electric field.

02

Comparison of the electric field at different points

You can assume the field is zero as there is not any field line through point 1. But your assumption is wrong.

You can think that in the nearest point 1, the field line's density is more than the density of field lines at point 2.

In addition, you know the more the density of field lines, the more the electric field is. Therefore, the field at point 1 is larger as the field lines are closer together in that region.

The electric field due to a point charge is given as:

\(E = \frac{{kQ}}{r}\) … (i)

Here, k is the Coulomb’s constant, Q is the charge and r is the distance from the charge.

From equation (i), it is also clear that the magnitude of the electric field is inversely proportional to the distance from the charge. Since the distance of point 2 is more than that of point 1 therefore, the electric field at point 1 is larger.

Thus, the correct option is (d).

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Most popular questions from this chapter

(II) A charge of 6.15 mC is placed at each corner of a square 0.100 m on a side. Determine the magnitude and direction of the force on each charge.

We are usually not aware of the electric force acting between two everyday objects because

(a) the electric force is one of the weakest forces in nature.

(b) the electric force is due to microscopic-sized particles such as electrons and protons.

(c) the electric force is invisible.

(d) most everyday objects have as many plus charges as minus charges.

Question: (II) In Fig. 16–62, two objects, \({{\bf{O}}_{\bf{1}}}\) and \({{\bf{O}}_{\bf{2}}}\) have charges \({\bf{ + 1}}{\bf{.0}}\;{\bf{\mu C}}\) and \({\bf{ - 2}}{\bf{.0}}\;{\bf{\mu C}}\), respectively, and a third object, \({{\bf{O}}_{\bf{3}}}\), is electrically neutral. (a) What is the electric flux through the surface \({A_1}\) that encloses all three objects? (b) What is the electric flux through the surface \({A_2}\) that encloses the third object only?

FIGURE 16–62 Problem 39.

(II) Determine the direction and magnitude of the electric field at the point P in Fig. 16–56. The charges are separated by a distance 2a, and point P is a distance x from the midpoint between the two charges. Express your answer in terms of Q, x, a, and k.

(II) Two point charges, \({{\bf{Q}}_{\bf{1}}}{\bf{ = - 32}}\;{\bf{\mu C}}\) and \({{\bf{Q}}_{\bf{2}}}{\bf{ = + 45}}\;{\bf{\mu C}}\) are separated by a distance of 12 cm. The electric field at point P (see Fig. 16–57) is zero. How far from \({{\bf{Q}}_{\bf{1}}}\) is P?

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