Chapter 4: Q1. (page 101)
What force is needed to accelerate a sled ( mass = 55 kg) aton horizontal frictionless ice?
Short Answer
The force needed to accelerate the sled is 77 N.
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Chapter 4: Q1. (page 101)
What force is needed to accelerate a sled ( mass = 55 kg) aton horizontal frictionless ice?
The force needed to accelerate the sled is 77 N.
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(a) If,andin Fig. 4–53, determine the acceleration of each block. (b) If initially, it is at rest at 1.250 m from the edge of the table, how long does it take to reach the edge of the table if the system is allowed to move freely? (c) If, how large mustbe if the acceleration of the system is to be kept at?
A person stands on a scale in an elevator. His apparent weight will be the greatest when the elevator
(a) is standing still.
(b) is moving upward at a constant velocity.
(c) is accelerating upward.
(d) is moving downward at a constant velocity.
(e) is accelerating downward.
An elevator (mass 4850 kg) is to be designed so that the maximum acceleration is 0.0680 g. What are the maximum and minimum forces that the motor should exert on the supporting cable?
The coefficient of static friction between hard rubber and a normal street pavement is about 0.90. On how steep a hill (maximum angle) can you leave a car parked?
A 50-N crate sits on a horizontal floor where the coefficient of static friction between the crate and the floor is 0.50. A 20-N force is applied to the crate acting to the right. What is the resulting static friction force acting on the crate?
(a) 20 N to the right.
(b) 20 N to the left.
(c) 25 N to the right.
(d) 25 N to the left.
(e) None of the above; the crate starts to move.
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