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A heavy crate rests on the bed of a flatbed truck. When the truck accelerates, the crate stays fixed on the truck, so it, too, accelerates. What force causes the crate to accelerate?

Short Answer

Expert verified

The static frictional force causes the crate to accelerate.

Step by step solution

01

Step 1. Conditions of friction

In order to determine the force between the crate and the truck, you have to use the properties of friction. Basically, three situations cause friction, which are as follows:

(1) Surface roughness

(2) Plowing effect

(3) Molecular adhesion

02

Step 2. Determine the force that causes the crate to accelerate

A heavy crate rests on the bed of a truck when it starts to accelerate. This causes the heavy crate to accelerate because of the static friction between the truck and the crate. Since they are in contact with each other, friction is developed between them due to surface roughness.

Thus, the crate accelerates due to static frictional force.

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Most popular questions from this chapter

To pull an old stump out of the ground, you and a friend tie two ropes to the stump. You pull on it with a force of 500 N to the north while your friend pulls with a force of 450 N to the northwest. The total force from the two ropes is

(a) less than 950 N.

(b) exactly 950 N.

(c) more than 950 N.

On an icy day, you worry about parking your car in your driveway, which has an incline of 12°. Your neighbor’s driveway has an incline of 9.0°, and the driveway across the street is at 6.0°. The coefficient of static friction between tire rubber and ice is 0.15. Which driveway(s) will be safe to park in?

For the system of Fig. 4–32 (Example 4–20), how large a mass would box A have to have to prevent any motion from occurring? Assumeμs=0.30.

FIGURE 4-32 Example 4–20.

Three blocks on a frictionless horizontal surface are in contact with each other, as shown in Fig. 4–54. A forceF→is applied to block A (mass mA). (a) Draw a free-body diagram for each block. Determine (b) the acceleration of the system (in terms of mA, mB, and mC), (c) the net force on each block, and (d) the force of contact that each block exerts on its neighbor. (e) IfmA=mB=mC=10.0kg,andF=96.0N,give numerical answers for (b), (c), and (d). Explain how your answers make sense intuitively.

FIGURE 4-54 Problem 34

A skier moves down a 12° slope at constant speed. What can you say about the coefficient of friction,μk? Assume the speed is low enough that air resistance can be ignored.

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