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Two identical point charges \(q_1\) and \(q_2\) are at a distance \(r\) apart. If the size of \(q_1\) is doubled and the distance between them tripled, the strength of the electrical force between them (A) goes up by a factor of 3 . (B) goes down by a factor of 3 . (C) goes down by a factor of 9 . (D) goes down by a factor of \(2 / 3\). (E) goes down by a factor of \(2 / 9\)

Short Answer

Expert verified
Question: After doubling the size of one of the point charges and tripling the distance between them, the electrical force between the two point charges will: (A) remain the same (B) go up by a factor of 2 (C) go up by a factor of 6 (D) go down by a factor of 6 (E) go down by a factor of 2/9

Step by step solution

01

Understanding Coulomb's Law

Coulomb's law states that the electrical force (\(F\)) between two point charges \(q_1\) and \(q_2\) is proportional to the product of their charges and inversely proportional to the square of the distance (\(r\)) between them. Mathematically, this is expressed as: $$ F = k \frac{q_1q_2}{r^2} $$ Where \(k\) is Coulomb's constant.
02

Calculate the initial electrical force

We can use Coulomb's law to calculate the initial electrical force between \(q_1\) and \(q_2\): $$ F_1 = k \frac{q_1q_2}{r^2} $$
03

Calculate the electrical force after the changes

Now, let's double the size of \(q_1\) (i.e., \(2q_1\)) and triple the distance between them (i.e., \(3r\)). We will now calculate the new electrical force \(F_2\) using these changes: $$ F_2 = k \frac{(2q_1)q_2}{(3r)^2} $$
04

Simplify the new electrical force equation

We can simplify the fraction in the equation: $$ F_2 = k \frac{2q_1q_2}{9r^2} $$
05

Compare initial and new electrical force

Notice that the initial electrical force equation was: $$ F_1 = k \frac{q_1q_2}{r^2} $$ Comparing the two equations, we can see the relationship between the initial electrical force \(F_1\) and the new electrical force \(F_2\): $$ F_2 = \frac{2}{9} F_1 $$ This means that the new electrical force \(F_2\) is reduced by a factor of \(2/9\) as compared to the initial electrical force \(F_1\). So, the correct answer is: (E) goes down by a factor of \(2/9\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Electrical Force
The concept of electrical force is a fundamental principle in physics, describing the interaction between two charged objects. When two charges are present, whether positive or negative, they exert a force on each other. This force is known as the electrical force. It can attract or repel depending on whether the charges are opposite (attractive) or similar (repulsive). This force plays an essential role in the behavior of objects at the atomic and molecular levels, making it crucial for understanding other fields such as chemistry and biology. - **Key Points:** - Electrical force can be both attractive and repulsive. - It is one of the four fundamental forces of nature. - This force significantly impacts the positioning and behavior of charged particles. Understanding electrical force helps explain phenomena like how atoms bond to form molecules, which is vital for all matter that constitutes our world.
Point Charges
Point charges are a simplification used in physics to model charged objects on a theoretical level. In reality, point charges don't exist as they would imply all of a charge's matter is concentrated at a singular point in space. However, this concept is useful for simplifying complex equations and understanding the basic interactions of charged particles. By considering charges as "points," calculations become less complicated, allowing us to focus on the main factors affecting electrical interactions, such as distance and charge magnitude. This is particularly handy in scenarios where the actual size of the charged objects is negligible compared to the space between them. - **Key Uses:** - Simplifying calculations in electrostatics. - Modeling interactions in fields like circuitry and electromagnetism. - Understanding the behavior of electrons around an atom. The use of point charges allows researchers and students to visualize and predict how charged particles behave within the framework of physics laws.
Proportional Relationship
Understanding the proportional relationship in Coulomb's law is key to predicting how changes will impact electrical force. Coulomb's Law, given by the formula \( F = k \frac{q_1q_2}{r^2} \), shows that electrical force is directly proportional to the product of the magnitudes of the two charges and inversely proportional to the square of the distance between them. This means:- **Doubling the charge**: If one charge is doubled, the electrical force will also double because the product of the charges becomes twice as large.- **Changing the distance**: Increasing the distance diminishes the force. If the distance triples, the force decreases to one-ninth, as distance is squared in the denominator.By understanding these proportions, one can predict how the electrical force will change, ensuring seamless application of physics laws when examining more complex systems. Recognizing these relationships helps explain why particles behave as they do under varied conditions.

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Most popular questions from this chapter

Two identical plastic balls of mass \(10 \mathrm{gm}\) each are hung by threads with length \(30 \mathrm{~cm}\) from a common point, as shown below. The balls are each charged with the same charge \(q\) and repel each other until they come to rest with a horizontal separation of \(30 \mathrm{~cm}\). a) Sketch the electric field produced by the two balls. b) Draw the force vectors on the right-hand ball. c) What is the charge \(q\) in each ball?

A circular loop rotates around a horizontal axis coming out of the page (side view shown, below). The loop is rotating in a uniform \(B\)-field, pointed downward. For every two full rotations, how often does the induced current change direction? (A) Twice (B) Four times (C) Eight times (D) Twelve time (E) Sixteen times

The positively charged rod is brought near the large sphere, but without touching it. The two spheres are separated and lastly the rod removed to a distance. We can then say that (A) the big sphere will be positively charged and the smaller sphere will be negatively charged. (B) both spheres will be positively charged. (C) the big sphere will be negatively charged and the smaller sphere will be positively charged. (D) both spheres will be negatively charged. (E) all the charge will migrate to the smaller sphere.

Two long, parallel wires separated by a distance \(r\) carry equal currents \(I\) in opposite directions, as shown. The direction of the field caused by the top wire at the position of the bottom wire and the direction of the force exerted by the top wire on the bottom wire are (A) \(B\) into the page; \(F\) down (B) \(B\) up; \(F\) into the page (C) \(B\) into the page; \(F\) up (D) \(B\) out of the page; \(F\) down (E) \(B\) down; \(F\) out of the page

Two masses of \(10^{-9} \mathrm{~kg}\) each carry a charge of \(+3 \mathrm{nC}\) and are initially held motionless by a massless thread at a distance of \(9 \mathrm{~m}\). a) Draw the electric field produced by the two charges. b) What is the tension in the thread? c) The thread is cut by a magic wand. What is the initial acceleration of each of the charges? d) How does the acceleration change with \(r\) ? Graph the behavior. Explain qualitatively how the velocity will change with \(r\). In particular, what happens to the velocity when \(r\) goes to infinity. Where is the maximum velocity?

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