/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 22 A hungry \(700-\mathrm{N}\) bear... [FREE SOLUTION] | 91Ó°ÊÓ

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A hungry \(700-\mathrm{N}\) bear walks out on a beam in an attempt to retrieve some "goodies" hanging at the end (Fig. P8.22). The beam is uniform, weighs \(200 \mathrm{~N}\), and is \(6.00 \mathrm{~m}\) long; the goodies weigh \(80.0 \mathrm{~N}\). (a) Draw a free-body diagram of the beam. (b) When the bear is at \(x=1.00 \mathrm{~m}\), find the tension in the wire and the components of the reaction force at the hinge. (c) If the wire can withstand a maximum tension of \(900 \mathrm{~N}\), what is the maximum distance the bear can walk before the wire breaks?

Short Answer

Expert verified
The tension \(T\) and the vertical component of the hinge reaction \(R_y\) can be found by solving the equilibrium equations. The horizontal component of the hinge reaction \(R_x\) is equal to \(T\). The maximum distance \(x\) that the bear can walk before the wire breaks can be found when \(T\) is set to its maximum value of 900N.

Step by step solution

01

Free-body diagram

This step involves drawing a free-body diagram of the beam, showing all the forces acting on it. The bear, the goodies, the beam's weight are forces acting downward, the tension force in the wire acts upward and there is a reaction force at the hinge, pointing upwards. The bear's weight (700N), beam's weight (200N), and goodies' weight (80N) are all acting downwards. The beam's weight is acting at the center of the beam, which is 3m from the hinge. The goodies' weight is at the end of the beam and the bear's weight changes its position as it moves on the beam.
02

Equilibrium equations at x=1.00m

The equilibrium equations are based on the principle that for the system to be in balance, the sum of forces and the sum of the moments (torques) must be equal to zero. Set the hinge as the point about which moments are calculated (the rotation point). The sum of forces equation is: \(R_y + T - F_{bear} - F_{beam} - F_{goodies} = 0\), with \(R_y\) being the vertical component of the reaction at the hinge, and \(T\) the tension in the wire. The sum of moments equation is: \(R_x*6 - T*2 - F_{bear}*x - F_{beam}*3 - F_{goodies}*6 = 0\), with \(R_x\) being the horizontal component of the reaction at the hinge, and we assume that the wire is attached at a distance of 2m from the hinge. Here, the distance \(x\) of the bear from the hinge is given as 1.00m.
03

Solve for tension and hinge reaction components

Plug in the given values to the expressions obtained in Step 2 and solve the system of equations for \(T\) and \(R_y\). Then, the horizontal component of the hinge reaction, \(R_x\), can be found from the condition that the sum of horizontal forces must be zero, which gives \(R_x = T\).
04

Maximum distance for the bear

The maximum tension the wire can withstand is given as 900N. Using the equations above, the bear's distance \(x\) from the hinge can be found when the tension \(T\) is equal to the maximum allowable tension of 900N. Solve this for \(x\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Free-Body Diagram
Understanding the forces acting on an object is crucial in physics, and a free-body diagram (FBD) is an essential tool for visualizing these forces. An FBD is a graphical illustration that depicts all the forces acting on a single object. To create an FBD, you first isolate the object from its surroundings. Then, you represent each force with an arrow, pointing in the direction the force is applied, and label them to indicate their nature and magnitude.

To get a clear picture, start by drawing the object in question, which, in this case, is a beam. Next, draw arrows to represent the gravitational forces due to the weight of the bear, the beam, and the goodies, all acting downwards. Remember, the magnitude of these forces corresponds to their respective weights. Then, add the upward tension force in the wire and the reaction force at the hinge. It's important to note where each force is applied: the bear's weight varies with its position on the beam, the beam's weight acts at its center of gravity, and the reaction forces act at the hinge point.

For students, breaking down complex systems into free-body diagrams can significantly help in understanding the interaction of forces and effectively resolving problems in static equilibrium.
Equilibrium Equations
When an object is in static equilibrium, it is at rest or moving with constant velocity; that is, it's not experiencing any net force or net torque. To analyze such a state, we use equilibrium equations. These equations emerge from Newton's first law of motion, stating that an object will remain at rest or in uniform motion unless acted upon by a net force.

The equilibrium conditions for a static object are twofold: the net force must be zero, and the net torque must also be zero. Formally, this can be expressed as \(\sum F = 0\) and \(\sum \tau = 0\), where \(\sum\) represents the sum of the respective quantities. These conditions ensure that both the linear and rotational motions are in equilibrium.

In the scenario of the bear on a beam, applying the equilibrium conditions allows us to set up mathematical expressions. For instance, taking into account all the vertical forces results in an equation that can be used to find unknowns like the tension in the wire or the reaction force at the hinge. Similarly, considering all the moments around a pivot point provides another equation to solve for the same unknowns.
Tension in Physics
Tension is a force that passes through a flexible connector like a string, cable, or chain. In physics, it refers specifically to the pulling force transmitted axially by means of a string or other object. When a string or rope is attached to a body and pulled, the force exerted on the body is called tension. In our example with the bear and the beam, the wire holding up one end of the beam is in tension.

In the context of static equilibrium, tension plays a key role in balancing forces. The tension in the wire opposes the gravitational forces acting on the beam and the bear, maintaining equilibrium. Calculating this tension involves using equilibrium equations, where it stands as an unknown that must be determined from other given quantities, like weights and distances from the pivot.

Understanding tension is particularly important in real-world applications like construction and design, where materials must withstand certain loads without failing. Thus, knowing how to calculate it is essential for safety and functionality in structures.
Torque and Moments
Torque, also known as the moment of force, is the rotational equivalent of a linear force and plays an essential role in static equilibrium for objects that can rotate or pivot. It's a measure of the force causing an object to rotate around an axis. Torque is calculated by the cross product of the position vector (distance from the pivot point to the point where the force is applied) and the force vector, resulting in \(\tau = r \times F\), where \(\tau\) is the torque, \(\) is the position vector, and \(\(F\)\) is the force.

In the bear on the beam problem, when considering moments, you calculate the torque produced by each force with respect to the pivot point (hinge). This includes the weights of the bear, the beam, and the goodies, each multiplied by their respective distances from the hinge to where their force is applied. These torques must be counterbalanced by the torque due to the wire's tension for the beam to remain in equilibrium. Whenever we are analyzing systems involving rotations or the potential for rotation, understanding the concept of torque is essential for solving for unknowns and ensuring a system's stability.

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Most popular questions from this chapter

A painter climbs a ladder leaning against a smooth wall. At a certain height, the ladder is on the verge of slipping. (a) Explain why the force exerted by the vertical wall on the ladder is horizontal. (b) If the ladder of length \(L\) leans at an angle \(\theta\) with the horizontal, what is the lever arm for this horizontal force with the axis of rotation taken at the base of the ladder? (c) If the ladder is uniform, what is the lever arm for the force of gravity acting on the ladder? (d) Let the mass of the painter be \(80 \mathrm{~kg}, L=4.0 \mathrm{~m}\), the ladder's mass be \(30 \mathrm{~kg}, \theta=53^{\circ}\), and the coefficient of friction between ground and ladder be \(0.45\). Find the maximum distance the painter can climb up the ladder.

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