/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 63 A hunter wishes to cross a river... [FREE SOLUTION] | 91Ó°ÊÓ

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A hunter wishes to cross a river that is \(1.5 \mathrm{~km}\) wide and flows with a speed of \(5.0 \mathrm{~km} / \mathrm{h}\) parallel to its banks. The hunter uses a small powerboat that moves at a maximum speed of \(12 \mathrm{~km} / \mathrm{h}\) with respect to the water. What is the minimum time necessary for crossing?

Short Answer

Expert verified
The minimum time necessary for crossing the river is approximately \(0.14 \mathrm{hours}\).

Step by step solution

01

Determine the speed of the boat relative to the river bank

As the boat crosses the river, it will be affected by the river current, which will push the boat downstream. We are given the speed of the boat relative to the water, not relative to the river bank. We need to calculate the speed of the boat relative to the river bank. To get the speed relative to the river bank, we can use the Pythagorean theorem, since the speed of the boat and the speed of the river form a right angle. Hence the speed of the boat relative to the river bank, \(V_{BR}\), is \(\sqrt{\(V_{BW}^{2} - V_{R}^{2}\)}\), where \(V_{BW}\) is the speed of the boat with respect to the water, and \(V_{R}\) is the speed of the river. Substituting the given values we get \(V_{BR} = \sqrt{\(12^{2} - 5^{2}\)} = \sqrt{119} \approx 10.9 \mathrm{km/h}\).
02

Calculate the time taken to cross the river

Once we have the speed of the boat relative to the bank, we can calculate the time it takes for the boat to cross the river. The equation for time is \(t = \frac{d}{v}\) where \(d\) is the distance and \(v\) is the speed. The river is 1.5 km wide and the boat's speed relative to the bank is approximately 10.9 km/h, so the time taken is \(t = \frac{1.5}{10.9} \approx 0.14 \mathrm{hours}\)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Relative Velocity
When tackling problems involving movement, like the river crossing problem posed to the hunter, it's crucial to comprehend the concept of relative velocity. Relative velocity is the velocity that an object, like our hunter's boat, has in relation to another object, which in this case is the river bank.

To visualize this, imagine you're on a moving walkway at an airport. Your speed relative to the walkway might be 2 km/h if you stand still, but relative to the airport building, you’re moving at the speed of the walkway plus your own speed if you also walk. Similarly, the boat has its own speed, and the river current acts like the moving walkway, adding or subtracting from the boat’s speed depending on the direction of the flow and how the boat navigates.

  • The boat's speed with respect to water is given as 12 km/h.
  • The river’s speed is given as 5 km/h.
If the hunter aims straight across to the other side, the current pushes the boat downstream; hence we look for the boat's speed relative to the river bank using vector addition. An efficient way to solve this is by applying the Pythagorean theorem, since the movement of the boat and the flow of the river are at right angles to each other.
Applying the Pythagorean Theorem
The Pythagorean theorem is a cornerstone of geometry, especially useful when dealing with right-angled triangles. The theorem states that in a right triangle, the square of the length of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the lengths of the other two sides.

For the river crossing problem, the hunter’s boat forms a figurative right triangle when moving across the river. Here’s how the sides align:
  • The hypotenuse represents the boat's speed relative to water (12 km/h).
  • One side represents the boat's intended direction straight across the river (which is what we are trying to find).
  • The other side represents the river current downstream (5 km/h).
By using the theorem, we aim to find the velocity of the boat relative to the river bank, which is the side of the triangle we need to cross the river effectively. The formula derived from this theorem helps us calculate this magnitude precisely and is the first mathematical step towards solving our problem.
Calculating Time for the Journey
The final piece of the puzzle in our river crossing scenario is the time calculation. Time is a measure of the duration of an event, and in physics, we frequently calculate it using the simple formula: time = distance / speed. This is particularly relevant for the hunter who wants to know how long it will take to cross the river.

Once the hunter's relative speed to the river bank is calculated (thanks to our Pythagorean theorem application), the remaining task is straightforward. Using the provided river width (the distance to be crossed) and the calculated relative speed, we apply the time formula:
  • Distance the hunter needs to travel across the river (1.5 km)
  • The speed of the boat relative to the river bank (approx. 10.9 km/h)
Dividing the distance by speed gives us the hunter's crossing time in hours. Mathematically, it’s a simple division, but contextually, it tells us how swiftly the hunter can maneuver across the water without being swept too far downstream. Such time calculations are essential in everyday life, from planning our commutes to estimating the duration of tasks.

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Most popular questions from this chapter

The cye of a hurricane passes over Grand Bahama Island in a direction \(60.0^{\circ}\) north of west with a speed of \(41.0 \mathrm{~km} / \mathrm{h}\). Three hours later the course of the hur. ricane suddenly shifts due north, and its speed slows to \(25.0 \mathrm{~km} / \mathrm{h}\). How far from Grand Bahama is the hurricane \(4.50 \mathrm{~h}\) after it passes over the island?

A girl delivering newspapers covers her route by traveling \(3.00\) blocks west, \(4.00\) blocks north, and then \(6.00\) blocks east. (a) What is her resultant displacement? (b) What is the total distance she travels?

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How long does it take an automobile traveling in the left lane of a highway at \(60.0 \mathrm{~km} / \mathrm{h}\) to overtake (become even with) another car that is traveling in the right lane at \(40.0 \mathrm{~km} / \mathrm{h}\) when the cars' front bumpers are initially \(100 \mathrm{~m}\) apart?

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