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A girl delivering newspapers covers her route by traveling \(3.00\) blocks west, \(4.00\) blocks north, and then \(6.00\) blocks east. (a) What is her resultant displacement? (b) What is the total distance she travels?

Short Answer

Expert verified
The resultant displacement is \(5.00\) blocks, and the total distance she travels is \(13.00\) blocks.

Step by step solution

01

Calculate the resultant displacement

Firstly, determine the resultant displacement along the east-west direction (x-axis). This involves subtracting the distance traveled west from the distance traveled east, i.e., \(6.00 - 3.00 = 3.00\) blocks east. Her resultant north-south (y-axis) direction is the same as the distance she traveled north, i.e., \(4.00\) blocks north. You can represent her total displacement as a right-angled triangle, with one side as \(3.00\) blocks east and the other as \(4.00\) blocks north. To find the hypotenuse, which represents her resultant displacement, use the Pythagorean theorem, \(c = \sqrt{a^{2} + b^{2}}\), where \(c\) is the hypotenuse and \(a\) and \(b\) are the two sides. Thus, \(c = \sqrt{(3.00^{2} + 4.00^{2})} = 5.00\) blocks.
02

Calculate the total distance

The total distance she travels is the sum of the distances she travels in each direction. This simply involves adding the distance she traveled west, north and east. \(3.00 + 4.00 + 6.00 = 13.00\) blocks.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Vector Addition
To understand how the girl’s route translates into a single movement, we use the concept of vector addition. Imagine each segment of her journey as a vector, which indicates both direction and magnitude. This is a common way to describe displacement in physics.

The girl travels in three directions: west, north, and east.
  • The westward movement can be seen as a vector pointing to the left.
  • Northward movement is a vertical vector pointing upwards.
  • Eastward movement is a vector pointing to the right.
These vectors can be added together to find a resultant vector, which shows the direct path from her starting point to her ending point. By breaking each vector down into components (such as just horizontal or vertical movement), we can simplify the math and find the end result of her combined movements. In this exercise, the horizontal (east-west) vectors are combined first, followed by the inclusion of the vertical (north) vector to determine the overall displacement.
Pythagorean Theorem
Once the vector components are sorted, the Pythagorean theorem comes into play. This mathematical principle is crucial for finding the magnitude of the resultant vector (displacement) in problems involving right-angled triangles.

In simple terms, if you have two sides of a right-angle triangle, you can find the third side (the hypotenuse) using the formula: \[ c = \sqrt{a^2 + b^2} \] Where \(c\) is the hypotenuse, and \(a\) and \(b\) are the other two sides. For the newspaper delivery girl, her path forms such a triangle:
  • A (east-west) side of \(3.00\) blocks.
  • A vertical (north) side of \(4.00\) blocks.
By applying the theorem, \(c\), her displacement, is \(5.00\) blocks. This shows the beauty of the Pythagorean theorem in calculating direct paths from journey splits.
Distance Calculation
Understanding the concept of distance calculation is fundamental when determining the total path someone has traveled. Unlike displacement, which is concerned with the most direct route from start to finish, total distance focuses on every segment covered. In this case, the girl’s journey isn't a straight line.

Her total distance is simply the sum of all individual segments of her trip. Here's how it's calculated:
  • She travels \(3.00\) blocks west.
  • Then \(4.00\) blocks north.
  • Finally, \(6.00\) blocks east.
Adding these values gives \(13.00\) blocks as her total traveled distance.

While displacement asks "how far out of place" the girl is, the total distance asks "how far has she walked in all?" It’s a measure that doesn’t care about direction, only total ground covered.

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Most popular questions from this chapter

Vector \(\vec{A}\) has a magnitude of \(8.00\) units and makes an angle of \(45.0^{\circ}\) with the positive \(x\) -axis. Vector \(\overrightarrow{\mathbf{B}}\) also has a magnitude of \(8.00\) units and is directed along the negative \(x\) -axis. Lsing graphical methods, find (a) the vector \(\operatorname{sum} \overrightarrow{\mathrm{A}}+\overrightarrow{\mathbf{B}}\) and \((\mathrm{b})\) the vector difference \(\overrightarrow{\mathrm{A}}-\overrightarrow{\mathbf{B}}\).

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