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(a) Find the change in classical momentum of an electron that accelerates from \(0.900 c\) to \(0.940 c\), neglecting relativistic effects. (b) Repeat the calculation, using the expression for relativistic momentum.

Short Answer

Expert verified
The change in classical momentum of the electron is the difference between the final and initial classical momenta. The change in relativistic momentum of the electron is the difference between the final and initial relativistic momenta.

Step by step solution

01

Calculate classical momenta

Compute the initial and final classical momenta of the electron. The mass of an electron \(m = 9.11*10^{-31} kg\), the initial velocity \(v_i = 0.900c\), and final velocity \(v_f = 0.940c\). The classical momentum is given by \(p=mv\). Calculate both the initial and final classical momenta using these given values.
02

Find change in classical momentum

Obtain the change in classical momentum by subtracting the initial momentum from the final momentum.
03

Compute initial and final relativistic momenta

Find the initial and final relativistic momenta of the electron. The relativistic momentum is given by \(p=\frac{mv}{\sqrt{1-(v/c)^2}}\). Perform the calculations using the given initial and final velocities.
04

Determine change in relativistic momentum

Compute the change in relativistic momentum by subtracting the initial momentum from the final momentum.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Classical Momentum
Classical momentum is a fundamental concept in physics that is most suitable for analyzing objects moving at speeds much lower than the speed of light. It is defined as the product of an object's mass and its velocity, given by the equation \( p = mv \). For instance, in our original exercise involving an electron, the mass is known, \( m = 9.11 \times 10^{-31} \text{ kg} \), which helps in calculating the momentum once the velocity is provided.
  • Initial velocity \( v_i = 0.900c \) and final velocity \( v_f = 0.940c \).
  • Classical momentum computations neglect relativistic effects, so \( c \) does not influence calculations in this model.
By multiplying the mass of the electron by these velocities, both initial and final classical momenta can be determined. The change in classical momentum is simply the difference between the final and initial momenta. This equation simplifies many physical systems but is not accurate when speeds approach the speed of light.
Electron Velocity
The velocity of an electron is crucial when calculating both classical and relativistic momentum. In situations involving high speeds, especially those nearing the speed of light, electron velocity plays a key role in both calculations and the resultant physical behavior.
  • \( 0.900c \) and \( 0.940c \) are fractions of the speed of light \( c \).
  • Such high velocities impact how momentum is computed due to relativistic effects described by Einstein's theory of relativity.
In classical physics, velocity is simply plugged into the equation for momentum. However, in relativistic settings, as velocity increases, so does the factor by which it impacts the momentum formula. The result is that the electron behaves differently at higher velocities due to a distortion of time and space.
Relativistic Effects
Relativistic effects become significant when particles, such as electrons, reach velocities close to the speed of light. Unlike in classical physics, where momentum is linear, Einstein’s theory introduces complexities that need to be considered. This is synthesized through calculating relativistic momentum, using the formula \( p = \frac{mv}{\sqrt{1-(v/c)^2}} \).
  • It factors in the increase in mass as velocities near the speed of light.
  • It also accounts for time dilation, making calculations more accurate at high speeds.
For our electron, the velocity change from \( 0.900c \) to \( 0.940c \) significantly alters the impact of momentum calculations. The relativistic model shows momentum growing substantially as these relativistic speeds are reached. This calculation accounts for real-life phenomena, such as why particles in accelerators require so much energy to increase speed at such scales.

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Most popular questions from this chapter

An astronaut wishes to visit the Andromeda galaxy, making a one-way trip that will take \(30.0\) years in the spaceship's frame of reference. Assume the galaxy is \(2.00\) million light-years away and his speed is constant. (a) How fast must he travel relative to Earth? (b) What will be the kinetic energy of his spacecraft, which has mass of \(1.00 \times\) \(10^{6} \mathrm{~kg} ?\) (c) What is the cost of this energy if it is purchased at a typical consumer price for electric energy, \(13.0\) cents per kWh? The following approximation will prove useful: $$ \frac{1}{\sqrt{1+x}}=1-\frac{x}{2} \quad \text { for } x<1 $$

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An unstable particle with a mass equal to \(3.34 \times 10^{-27} \mathrm{~kg}\) is initially at rest. The particle decays into two fragments that fly off with velocities of \(0.987 c\) and \(-0.868 c\), respectively. Find the masses of the fragments. Hint: Conserve both mass-energy and momentum.

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